我使用 a 和 b 定义两个点\coordinate
。然后我尝试绘制以 a 为圆心,以 ab 为半径的圆。我尝试了 3 次,请参阅下面的代码
- 有点天真,不起作用
- 使用https://tex.stackexchange.com/a/58287,不起作用
- 使用https://tex.stackexchange.com/a/38500这会生成一个半径很大的圆。
有没有办法让这三种方法都奏效?越简单越好。
\documentclass{article}
\usepackage{tkz-euclide}
\usetkzobj{all}
\usetikzlibrary{calc,patterns,angles,quotes,intersections}
\makeatletter
\def\calcLength(#1,#2)#3{%
\pgfpointdiff{\pgfpointanchor{#1}{center}}%
{\pgfpointanchor{#2}{center}}%
\pgf@xa=\pgf@x%
\pgf@ya=\pgf@y%
\FPeval\@temp@a{\pgfmath@tonumber{\pgf@xa}}%
\FPeval\@temp@b{\pgfmath@tonumber{\pgf@ya}}%
\FPeval\@temp@sum{(\@temp@a*\@temp@a+\@temp@b*\@temp@b)}%
\FProot{\FPMathLen}{\@temp@sum}{2}%
\FPround\FPMathLen\FPMathLen5\relax
\global\expandafter\edef\csname #3\endcsname{\FPMathLen}
}
\makeatother
\begin{document}
Attempt 1:
\begin{center}
\begin{tikzpicture}[]
\coordinate (a) at (0,0);
\coordinate (b) at (1.3,1.5);
\draw (a) circle (2);
\draw (a) circle ($(b)-(a)$);
\end{tikzpicture}
\end{center}
Attempt 2:
\begin{center}
\begin{tikzpicture}[]
\coordinate (a) at (0,0);
\coordinate (b) at (1.3,1.5);
\draw (a) circle (2);
% https://tex.stackexchange.com/a/58287
\draw
let
\p1 = (a),
\p2 = (b),
\n1 = {veclen((\x2-\x1),(\y2-\y1))}
(a) circle ({\n1});
\end{tikzpicture}
\end{center}
Attempt 3:
\begin{center}
\begin{tikzpicture}[]
\coordinate (a) at (0,0);
\coordinate (b) at (1.3,1.5);
\draw (a) circle (2);
% https://tex.stackexchange.com/a/38500
\calcLength(a,b){mylen}
\draw (a) circle (\mylen);
\end{tikzpicture}
\end{center}
\end{document}
答案1
第一次尝试稍作修改即可。如果添加缺失部分,第二次尝试同样有效in
(并且可能想要切换到现代语法circle[radius=<radius>]
)。
\documentclass{article}
\usepackage{tikz}
\usetikzlibrary{calc}
\begin{document}
Attempt 1 slightly modified:
\begin{center}
\begin{tikzpicture}
\coordinate (a) at (0,0);
\coordinate (b) at (1.3,1.5);
\draw let \p1=($(b)-(a)$),\n1={veclen(\x1,\y1)} in (a) circle[radius=\n1] ;
\end{tikzpicture}
\end{center}
\begin{center}
\begin{tikzpicture}[]
\coordinate (a) at (0,0);
\coordinate (b) at (1.3,1.5);
% https://tex.stackexchange.com/a/58287
\draw
let
\p1 = (a),
\p2 = (b),
\n1 = {veclen((\x2-\x1),(\y2-\y1))} in
(a) circle[radius={\n1}];
\end{tikzpicture}
\end{center}
\end{document}
答案2
使用 tikzlibrarythrough
可以轻松完成:
\node [draw] at (a) [circle through={(b)}] {};
\documentclass{article}
\usepackage{tikz}
\usetikzlibrary{through}
\begin{document}
\begin{tikzpicture}
\draw[help lines] (-2,-2) grid (2,2);
\node[circle,fill=red,inner sep=1pt] (a) at (0,0){a};
\node[circle,fill=red,inner sep=1pt] (b) at (1.3,1.5){b};
\node [draw,thick] at (a) [circle through={(b)}] {};
\end{tikzpicture}
\end{document}