将 2 个 \foreach 循环合并为一个

Question

使用以下代码（来自这个问题) 使用 2 个 \foreach 循环绘制方框；并定义它们的起始位置 (yshift=.4cm 和 yshift=4.4cm)。我希望蓝色方框自动从红色方框结束的位置开始。

是否可以将它们组合成一个循环？

我的意思是使用一个 \foreach 循环来绘制下面 4 个红色框，然后继续绘制上面 2 个蓝色框。

\documentclass{beamer}
\beamertemplatenavigationsymbolsempty
\usepackage{verbatim}
\usepackage{tikz}
\usepackage{pgfplots}
\begin{document}
\begin{frame}[t]
\frametitle{}
\newsavebox{\recAr}
\savebox{\recAr}{%
\begin{tikzpicture}[scale=.6]
\draw [thick, black, fill=red] (0,0) rectangle +(1,1.24);
\end{tikzpicture}}
\newsavebox{\recAb}
\savebox{\recAb}{%
\begin{tikzpicture}[scale=.6]
\draw [thick, black, fill=blue!60!white] (0,0) rectangle +(1,1.24);
\end{tikzpicture}}
\begin{tikzpicture}[scale=.8, transform shape]
\draw [line width=.4mm, black, dashed] (0,5.8) -- +(0:11) (0,0) -- +(0:11) node [pos=.68] (A) {};
\foreach \X in {0,1,2,3}
{\node[yshift=.4cm] (y-\X) at (A|-0,\X){\usebox{\recAr}};}
\foreach \X in {0,1}
{\node[yshift=4.4cm] (y-\X) at (A|-0,\X){\usebox{\recAb}};}
\end{tikzpicture}
\end{frame}
\end{document}

Answer 1

仅使用部分循环并基于我的答案解决方案很简单：

\documentclass{beamer}
\beamertemplatenavigationsymbolsempty
\usepackage{verbatim}
\usepackage{tikz}
\usetikzlibrary{chains,
                positioning}

\begin{document}
\begin{frame}[t, fragile]
\frametitle{}
    \begin{tikzpicture}[
node distance = 1mm and 55mm,
  start chain = going below,
   box/.style = {draw,  thick, fill=#1,
                 minimum width=6mm, minimum height=12mm,
                 inner sep=0pt, outer sep=0mm,
                 on chain}
                        ] 
\node (n1) [box=blue] {};
\node (n2) [box=blue] {};
    \node (n3) [below=1ex of n2, % when you need additional space, otherwide omit this option
                box=red] {}; %
\foreach \i in {4,5,6}
    \node (n\i) [box=red] {};
\coordinate[left=of n1.north] (a); % for shift node to the right
\draw [line width=.4mm, dashed]
    (a) -- ++ (11,0)  
    (a |- n6.south) -- ++ (11,0);
\end{tikzpicture}
\end{frame}
\end{document}

Answer 2

添加了Dunno's根据 OP 要求制定解决方案的建议

您可以简单地循环变量：

\documentclass{beamer}
\beamertemplatenavigationsymbolsempty
\usepackage{verbatim}
\usepackage{tikz}
\usepackage{pgfplots}
\usetikzlibrary{positioning}
\begin{document}
\begin{frame}[t]
\frametitle{}
\newsavebox{\recAr}
\savebox{\recAr}{%
\begin{tikzpicture}[scale=.6]
\draw [thick, black, fill=red] (0,0) rectangle +(1,1.24);
\end{tikzpicture}}
\newsavebox{\recAb}
\savebox{\recAb}{%
\begin{tikzpicture}[scale=.6]
\draw [thick, black, fill=blue!60!white] (0,0) rectangle +(1,1.24);
\end{tikzpicture}}
\begin{tikzpicture}[scale=.8, transform shape]
\draw [line width=.4mm, black, dashed] (0,5.8) -- +(0:11) (0,0) -- +(0:11) coordinate[pos=.68,alias=y-6] (A) {}; \path foreach \X [remember=\X as \LastX (initially 6)] in {5,4,...,0}{ node[above=1.5mm of y-\LastX,outer sep=0pt,inner sep=0pt] (y-\X) {\ifnum \X>3 \usebox{\recAb} \else \usebox{\recAr} \fi}};
\end{tikzpicture}
\end{frame}
\end{document}

要得到：

附言：我这样编写代码，只yshift需要一个，从而使yshift蓝色和红色框通用。