我正在写水解反应,但葡萄糖与蔗糖和果糖不一致。求助。
\documentclass[border=10pt]{standalone}
\usepackage{chemfig}
\begin{document}
\schemestart
\chemfig[cram width=2pt]{HO-[2,.5,2]?<[7,.7](-[2,.5]OH)-[,,,,line width=2.4pt](-[6,.5]OH)>[1,.7](-[:-65,.7]O-[:65,.7]?[b](-[2,.7]CH_2OH)<[:-60,.707](-[6,.5]OH)-[,,,,line width=2.4pt](-[2,.5,,2]HO)>[:60,.707](-[6,.5]CH_2OH)-[:162,.9]O?[b])-[3,.7]O-[4]?(-[2,.3]-[3,.5]HO)}
\arrow{<=>}
\chemfig[cram width=2pt]{HO-[2,0.5,2]?<[7,0.7](-[2,0.5]OH)-[,,,,
line width=2.4pt](-[6,0.5]OH)>[1,0.7](-[6,0.5]OH)-[3,0.7]
O-[4]?(-[2,0.3]-[3,0.5]OH)}
\+
\chemfig[cram width=2pt]{(?[b](-[2,.7]CH_2OH)<[:-60,.707](-[6,.5]OH)-[,,,,line width=2.4pt](-[2,.5,,2]HO)>[:60,.707](-[6,.5]CH_2OH)-[:162,.9]O?[b])}
\schemestop
\end{document}
答案1
根据手册版本 1.41在第12条中,+ 号,它指出,如果添加,则可以垂直对齐 + \arrow{0}[,0]
,这会绘制一个长度为零的不可见箭头。对于你的情况,你也需要将该技巧放在 + 号后面,IE, \arrow{0}[,0]\+\arrow{0}[,0]
。
\documentclass[border=10pt]{standalone}
\usepackage{chemfig}
\begin{document}
\schemestart
\chemfig[cram width=2pt]{HO-[2,.5,2]?<[7,.7](-[2,.5]OH)-[,,,,line width=2.4pt](-[6,.5]OH)>[1,.7](-[:-65,.7]O-[:65,.7]?[b](-[2,.7]CH_2OH)<[:-60,.707](-[6,.5]OH)-[,,,,line width=2.4pt](-[2,.5,,2]HO)>[:60,.707](-[6,.5]CH_2OH)-[:162,.9]O?[b])-[3,.7]O-[4]?(-[2,.3]-[3,.5]HO)}
\arrow{<=>}
\chemfig[cram width=2pt]{HO-[2,0.5,2]?<[7,0.7](-[2,0.5]OH)-[,,,,line width=2.4pt](-[6,0.5]OH)>[1,0.7](-[6,0.5]OH)-[3,0.7]O-[4]?(-[2,0.3]-[3,0.5]OH)}
\arrow{0}[,0]\+\arrow{0}[,0]
\chemfig[cram width=2pt]{(?[b](-[2,.7]CH_2OH)<[:-60,.707](-[6,.5]OH)-[,,,,line width=2.4pt](-[2,.5,,2]HO)>[:60,.707](-[6,.5]CH_2OH)-[:162,.9]O?[b])}
\schemestop
\end{document}