带箭头的矩阵

Question

我怎样在 Latex 中创建带有箭头的矩阵？

Answer 1

这是一个全自动的建筑。

\documentclass[tikz,border=3.14mm]{standalone}
\usetikzlibrary{matrix}
\begin{document}
\begin{tikzpicture}
\def\NM{5}
\matrix[matrix of nodes,column sep=1.5ex,row sep=1.5ex,
nodes in empty cells,
cells={nodes={
execute at begin node={%
\ifnum\the\pgfmatrixcurrentcolumn<\NM
\ifnum\the\pgfmatrixcurrentrow<\NM
$a_{\the\pgfmatrixcurrentrow\the\pgfmatrixcurrentcolumn}$
\fi
\else
\ifnum\the\pgfmatrixcurrentrow<\NM
$\cdots$
\else
$\ddots$
\fi
\fi
\ifnum\the\pgfmatrixcurrentrow=\NM
\ifnum\the\pgfmatrixcurrentcolumn<\NM
$\vdots$
\fi
\fi
}}},
execute at end matrix={%
\foreach \X in {2,...,\the\numexpr\NM-1\relax}
{
\ifodd\X
 \draw[-latex] (\tikzmatrixname-\the\numexpr\X-1\relax-1)
  --
  (\tikzmatrixname-\X-1);
\else
 \draw[-latex] (\tikzmatrixname-1-\the\numexpr\X-1\relax)
  --
  (\tikzmatrixname-1-\X);
\fi
\foreach \Y in {2,...,\X}
 {\ifodd\X
  \draw[latex-] (\tikzmatrixname-\the\numexpr1+\Y-2\relax-\the\numexpr\X-\Y+2\relax)
  --
  (\tikzmatrixname-\the\numexpr2+\Y-2\relax-\the\numexpr\X-\Y+1\relax);
 \else
  \draw[-latex] (\tikzmatrixname-\the\numexpr1+\Y-2\relax-\the\numexpr\X-\Y+2\relax)
  --
  (\tikzmatrixname-\the\numexpr2+\Y-2\relax-\the\numexpr\X-\Y+1\relax);
 \fi}
}}]{
 & & & & \\ 
 & & & &\\ 
 & & & &\\ 
 & & & &\\ 
 & & & &\\ 
};
\end{tikzpicture}
\end{document}