\documentclass[12pt]{article}
\usepackage{lmodern}
\usepackage{amsmath}
\usepackage{amssymb}
\usepackage{mathrsfs}
\usepackage{amsthm}
\usepackage[utf8]{inputenc}
\usepackage[T1]{fontenc}
\usepackage[french]{babel}
\usepackage[utf8]{inputenc}
\usepackage[top=3cm, bottom=3cm, left=3cm, right=3cm]{geometry}
\usepackage[x11names]{xcolor}
\usepackage{framed, etoolbox}
\colorlet{framecolor}{VioletRed4}
\colorlet{shadecolor}{LavenderBlush2!60}
\usepackage{thmtools} %
\usepackage{titlesec}%%%%%% <---------addendum
\titleformat{\section}%%%%%% <---------addendum
{\color{magenta}\normalfont\Large\bfseries}%%%%%% <---------addendum
{\color{magenta}\thesection}{1.5em}{}%%%%%% <---------addendum
\makeatletter
\define@key{thmdef}{frame}[{}]{%
\thmt@trytwice{}{%
\RequirePackage{framed}%
\RequirePackage{thm-patch}%
\def\FrameCommand{\fcolorbox{framecolor}{shadecolor}}
\addtotheorempreheadhook[\thmt@envname]{%
\begin{framed}}%
\addtotheorempostfoothook[\thmt@envname]{\end{framed}}%
}%
}
\makeatother
\declaretheoremstyle[
bodyfont=\mdseries,
]{mystyle}
\declaretheorem[numberwithin=section, frame]{definition}
\declaretheorem[frame, sharenumber=definition,style=mystyle]{proposition}
\AtBeginEnvironment{proposition}{\colorlet{framecolor}{DarkSeaGreen4}
\colorlet{shadecolor}{Yellow1!15}}
\newcommand{\myarrow}[1][1cm]{\mathrel{%
\hbox{\rule[\dimexpr\fontdimen22\textfont2-.2pt\relax]{#1}{.4pt}}%
\mkern-4mu\hbox{\usefont{U}{lasy}{m}{n}\symbol{41}}}}
\makeatletter
\setbox0\hbox{$\xdef\scriptratio{\strip@pt\dimexpr
\numexpr(\sf@size*65536)/\f@size sp}$}
\newcommand{\myscriptarrow}[1][1cm]{{%
\hbox{\rule[\scriptratio\dimexpr\fontdimen22\textfont2-.2pt\relax]
{\scriptratio\dimexpr#1\relax}{\scriptratio\dimexpr.4pt\relax}}%
\mkern-4mu\hbox{\let\f@size\sf@size\usefont{U}{lasy}{m}{n}\symbol{41}}}}
\makeatother
\begin{document}
\begin{center}
\begin{tabular}{ | c | c | c }
\hline
\rule{0pt}{0.9\normalbaselineskip}
$P$& $\bar{P}$ \\ \hline
$V$ & $F$ \\ \hline
$F$ & $V$ \\
\hline
\end{tabular}
\end{center}
\end{document}
答案1
您需要\rule{0pt}{..}
通过插入来删除后面的空格%
,请记住,return
在 LaTeX 中按下该键意味着输入一个空格。
\documentclass[12pt]{article}
\begin{document}
\begin{center}
\begin{tabular}{ | c | c | c }
\hline
\rule{0pt}{0.9\normalbaselineskip}% <===
$P$& $\bar{P}$ \\ \hline
$V$ & $F$ \\ \hline
$F$ & $V$ \\
\hline
\end{tabular}
\end{center}
\end{document}
更好的是,摆脱它\rule{}{}
并使用\renewcommand{\arraystretch}{1.5}
它来增加表格内的行距。
如果表格仅包含数学元素,为什么不使用array
?如下所示:
\[
\renewcommand{\arraystretch}{1.5}
\begin{array}{|c|c|c|}
\hline
P & \bar{P} \\ \hline
V & F \\ \hline
F & V \\
\hline
\end{array}
\]