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用表格单元格中的数据拟合大型方程

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用表格单元格中的数据拟合大型方程

我目前有一张表格和两个这样的方程式：

\documentclass[a4paper,12pt]{extarticle}
\usepackage[utf8]{inputenc}
\usepackage[a4paper, total={7in, 9in}]{geometry}
\usepackage[T1]{fontenc}
\usepackage{amsmath}
\usepackage{booktabs}
\usepackage{array}
\usepackage{multirow}
\usepackage[stable]{footmisc}
\usepackage[justification=centering]{caption}
\onehalfspacing
\usepackage{float}
\floatstyle{plaintop}
\restylefloat{table}

%center align fixed width column
\newcolumntype{P}[1]{>{\centering\arraybackslash}p{#1}}
\date{}
\begin{document}


\begin{table}[htbp]
\centering
\begin{tabular}{|P{6 cm}|P{2.7 cm}|c|P{2 cm}|P{2 cm}|}
\toprule
    \textbf{Model} & \textbf{Research Question} & \textbf{Coefficient} & \textbf{Response A} & \textbf{Response B} \\ \hline
    \multirow{ 2}{*}{Model 7} & RQ1a & \delta_{1} & $−.094^{***}$ $(.017)$ & $−0.458^{***}$ $(0.067)$ \\\cline{2-5}
    & RQ1b & \delta_{2} & $−.091^{***}$ (−.020) & $−0.210^{**}$ (0.039)\\ \hline
    \multirow{ 2}{*}{Model 8} & RQ2 & \delta_{1} & $−.020$ $(.014)$
 & $0.039$ $(0.055)$ \\\cline{2-5}
    & RQ2 & \delta_{2} & $.023^{\dagger}$ $(.014)$ & $0.209^{***}$ $(0.053)$ \\ \hline
\end{tabular}
\caption{Caption}
\label{table2}
\end{table}
\noindent\textit{Note:} Unstandardized coefficients with corrected standard errors in parentheses.\\ 
$^{\dagger}$  p < .10, $^{*}$ p < .05, $^{**}$ p < .01, $^{***}$ p <  .001.

\begin{equation}
    \begin{gathered}
    \mathrm{Y}=\beta_{0}+\beta_{1} \text{Income}+  \beta_{2}(\text{GrossSalary $-$ Housing}) + \\ \beta_{3}(\text{Dearness $-$ Extra }) +  \delta_{1} \text{Housing}+\delta_{2} \text{Extra}
    \end{gathered}
\end{equation}

\begin{equation}
    \begin{gathered}
    \mathrm{Y}=\beta_{0}+\beta_{1} \text{Income}+  \beta_{2}(\text{GrossSalary $-$ Housing}) + \\ \beta_{3}(\text{Dearness $-$ Extra }) +  \delta_{1} \text{Housing}+\delta_{2} \text{Extra}
    \end{gathered}
\end{equation}
\clearpage

\end{document}

它看起来像： 在此处输入图片描述

不过，我也希望在单元格中包含方程式（代替模型 1 和 2 这两个词）。

当我用整个方程式替换单词时，我的表格看起来很丑陋：

在此处输入图片描述

代码如下：

\documentclass[a4paper,12pt]{extarticle}
\usepackage[utf8]{inputenc}
\usepackage[a4paper, total={7in, 9in}]{geometry}
\usepackage[T1]{fontenc}
\usepackage{amsmath}
\usepackage{booktabs}
\usepackage{array}
\usepackage{multirow}
\usepackage[stable]{footmisc}
\usepackage[justification=centering]{caption}
\onehalfspacing
\usepackage{float}
\floatstyle{plaintop}
\restylefloat{table}

%center align fixed width column
\newcolumntype{P}[1]{>{\centering\arraybackslash}p{#1}}
\date{}
\begin{document}


\begin{table}[htbp]
\centering
\begin{tabular}{|P{6 cm}|P{2.7 cm}|c|P{2 cm}|P{2 cm}|}
\toprule
    \textbf{Model} & \textbf{Research Question} & \textbf{Coefficient} & \textbf{Response A} & \textbf{Response B} \\ \hline
    \multirow{ 2}{*}{\begin{equation}
    \begin{gathered}
    \mathrm{Y}=\beta_{0}+\beta_{1} \text{Income}+ \\ \beta_{2}(\text{GrossSalary $-$ Housing}) + \\ \beta_{3}(\text{Dearness $-$ Extra }) +  \\ \delta_{1} \text{Housing}+\delta_{2} \text{Extra}
    \end{gathered}
\end{equation}} & RQ1a & \delta_{1} & $−.094^{***}$ $(.017)$ & $−0.458^{***}$ $(0.067)$ \\\cline{2-5}
    & RQ1b & \delta_{2} & $−.091^{***}$ (−.020) & $−0.210^{**}$ (0.039)\\ \hline
    \multirow{ 2}{*}{\begin{equation}
    \begin{gathered}
    \mathrm{Y}=\beta_{0}+\beta_{1} \text{Income}+  \\ \beta_{2}(\text{GrossSalary $-$ Housing}) + \\ \beta_{3}(\text{Dearness $-$ Extra }) +  \\ \delta_{1} \text{Housing}+\delta_{2} \text{Extra}
    \end{gathered}
\end{equation}} & RQ2 & \delta_{1} & $−.020$ $(.014)$
 & $0.039$ $(0.055)$ \\\cline{2-5}
    & RQ2 & \delta_{2} & $.023^{\dagger}$ $(.014)$ & $0.209^{***}$ $(0.053)$ \\ \hline
\end{tabular}
\caption{Caption}
\label{table2}
\end{table}
\noindent\textit{Note:} Unstandardized coefficients with corrected standard errors in parentheses.\\ 
$^{\dagger}$  p < .10, $^{*}$ p < .05, $^{**}$ p < .01, $^{***}$ p <  .001.
\clearpage

\end{document}

我想让行变宽以适合方程式。我该怎么做？

编辑：@koleygr 的答案对我来说不太适用。我明白了

在此处输入图片描述

一些列分隔符不完整，并且所有单元格值在所有边上的填充并不相同（看起来不一致）。

至于@Mico的回答，我给出的方程式是示例方程式。较长的方程式不适合单元格。

答案1

只是一个避免多行的想法：

\documentclass[a4paper,12pt]{extarticle}
\usepackage[utf8]{inputenc}
\usepackage[a4paper, total={7in, 9in}]{geometry}
\usepackage[T1]{fontenc}
\usepackage{amsmath}
\usepackage{array}

\usepackage[stable]{footmisc}
\usepackage[justification=centering]{caption}
%\onehalfspacing
\usepackage{float}
\floatstyle{plaintop}
\restylefloat{table}

%center align fixed width column
\newcolumntype{P}[1]{>{\centering\arraybackslash}p{#1}}
\date{}
\begin{document}


\begin{table}[htbp]
\centering
\begin{tabular}{|P{6.5 cm}|@{}P{2.7 cm}|P{2.15cm}|P{2 cm}|P{2 cm}@{}|}
\hline
    \textbf{Model} & \textbf{Research Question} & \textbf{Coefficient} & \textbf{Response A} & \textbf{Response B} \\ \hline
    \parbox{6.5cm}{\begin{equation}
    \begin{gathered}
    \mathrm{Y}=\beta_{0}+\beta_{1} \text{Income}+ \\ \beta_{2}(\text{GrossSalary $-$ Housing}) + \\ \beta_{3}(\text{Dearness $-$ Extra }) +  \\ \delta_{1} \text{Housing}+\delta_{2} \text{Extra}
    \end{gathered}
\end{equation}} &\begin{tabular}{@{}P{2.7 cm}P{2.15cm}|P{2 cm}|P{2 cm}@{}|} RQ1a & $\delta_{1}$ & $-.094^{***}$ $(.017)$ & $-0.458^{***}$ $(0.067)$ \\[+0.6cm]\hline
     RQ1b & $\delta_{2}$ & $-.091^{***}$ (-.020) & $-0.210^{**}$ (0.039)\\[+0.6cm]\end{tabular}\\ \hline
    \parbox{6.5cm}{\begin{equation}
    \begin{gathered}
    \mathrm{Y}=\beta_{0}+\beta_{1} \text{Income}+  \\ \beta_{2}(\text{GrossSalary $-$ Housing}) + \\ \beta_{3}(\text{Dearness $-$ Extra }) +  \\ \delta_{1} \text{Housing}+\delta_{2} \text{Extra}
    \end{gathered}
\end{equation}} &\begin{tabular}{@{}P{2.7 cm}P{2.15cm}|P{2 cm}|P{2 cm}@{}|} RQ2 & $\delta_{1}$ & $-.020$ $(.014)$
 & $0.039$ $(0.055)$ \\[+0.6cm]\hline
     RQ2 & $\delta_{2}$ & $.023^{\dagger}$ $(.014)$ & $0.209^{***}$ $(0.053)$ \\[+0.6cm]\end{tabular}\\ \hline
\end{tabular}
\caption{Caption}
\label{table2}
\end{table}
\noindent\textit{Note:} Unstandardized coefficients with corrected standard errors in parentheses.\\ 
$^{\dagger}$  p < .10, $^{*}$ p < .05, $^{**}$ p < .01, $^{***}$ p <  .001.
\clearpage

\end{document}

在此处输入图片描述

答案2

使用包\makecell（用于多行列标题）、tabularx（用于X列类型）、 threeparttablex（用于表格中\notes和\tnote表格末尾）、siunitx（用于S最后两列的列类型）、\mathtools（用于multline数学环境）和˙nccmath (for\medmath` 来减少方程的大小）：

在此处输入图片描述

\documentclass[12pt]{extarticle}
%\usepackage[utf8]{inputenc}
\usepackage[a4paper, total={7in, 9in}]{geometry}
\usepackage[T1]{fontenc}
\usepackage{mathtools, nccmath}
\usepackage{array, booktabs, makecell, multirow, tabularx}
\usepackage[referable]{threeparttablex}
\renewcommand\theadfont{\small\bfseries}
\renewcommand\theadgape{}
\usepackage{siunitx}

\begin{document}

\begin{table}[htbp]
    \centering
    \sisetup{input-symbols={( )},
             table-space-text-post={$^{***}$},
             table-format=-1.3
             }
    \begin{ThreePartTable}
\begin{tabularx}{\linewidth}{@{} X c >{$}c<{$} S S @{}}
    \toprule
    &   &   &   \multicolumn{2}{c}{\thead{Response}}
                                                        \\
    \cmidrule{4-5}
\thead{Model}
    &   \multirow{-2}{*}{\thead[b]{Research\\ Question}}
        &   \thead{\text{Coef.}}
            &   {\thead{A}}
                &   {\thead{B}}                     \\
    \midrule
\multirow{4}{=}{
\begin{equation}\medmath{\begin{multlined}
    \mathrm{Y}=\beta_{0}+\beta_{1} \text{Income}+  \beta_{2}(\text{GrossSalary $-$ Housing}) + \\ \beta_{3}(\text{Dearness $-$ Extra }) +  \delta_{1} \text{Housing}+\delta_{2} \text{Extra}
            \end{multlined}
}\end{equation}
}% end of multirow
    & RQ1a  & \delta_1  & 0.094\tnote{***}  &  0.458\tnote{***} \\ 
    &       &           & (0.017)           & (0.067)           \\
    \addlinespace
    & RQ1b  & \delta_2  &  0.091\tnote{***} &  0.210\tnote{**}  \\
    &       &           & (0.020)           & (0.039)           \\
    \midrule
\multirow{4}{=}{
\begin{equation}\medmath{\begin{multlined}
    \mathrm{Y}=\beta_{0}+\beta_{1} \text{Income}+  \beta_{2}(\text{GrossSalary $-$ Housing}) + \\ \beta_{3}(\text{Dearness $-$ Extra }) +  \delta_{1} \text{Housing}+\delta_{2} \text{Extra}
            \end{multlined}
}\end{equation}
}% end of multirow
    & RQ2a  & \delta_1  & 0.020             &  0.039            \\
    &       &           & (0.014)           & (0.055)           \\
    \addlinespace
    & RQ2b  & \delta_2  &  0.023\tnote{$\dagger$}
                                            &  0.209\tnote{***} \\
    &       &           & (0.014)           & (0.053)           \\    
    \bottomrule
\end{tabularx}
\begin{tablenotes}[flushleft, para]\footnotesize\raggedright
\note{Unstandardized coefficients with corrected standard errors in parentheses.}\\
\item[$\dagger$]  $p <0.10$, 
\item[*]    $p <0.05$, 
\item[**]   $p <0.01$, 
\item[***]  $p <0.001$.
\end{tablenotes}
    \end{ThreePartTable}
    \end{table}
\end{document}

答案3

我会使用tabularx环境，将最后两列的数字与小数点对齐，删除所有垂直规则，并尽可能挤压最后四列，所有这些都是为了为第一列留出尽可能多的可用宽度。这样，就可以只是aligned在第一列中适合两行环境。

哦，我会的不是使用方程编号。

在此处输入图片描述

\documentclass[a4paper,12pt]{extarticle}
\usepackage[T1]{fontenc}
\usepackage[utf8]{inputenc}
\usepackage[total={7in, 9in}]{geometry}

\usepackage{amsmath,booktabs,tabularx,ragged2e}
\usepackage{multirow,dcolumn}
\usepackage[stable]{footmisc}
\usepackage[justification=centering,
            skip=0.333\baselineskip]{caption}

\usepackage{setspace}
\onehalfspacing

\usepackage{float}
\floatstyle{plaintop}
\restylefloat{table}

\usepackage{dcolumn}
\newcolumntype{d}[1]{D..{#1}}
\newcolumntype{C}{>{\Centering\arraybackslash}X}

\newcolumntype{P}[1]{>{\Centering\arraybackslash}p{#1}}
\newcommand\mC[1]{\multicolumn{1}{P{\mylenb}@{}}{#1}}

\newlength\mylena
\settowidth\mylena{\textbf{Research}}
\newlength\mylenb
\settowidth\mylenb{\textbf{Response}}

\newcommand\mybox[1]{\parbox{\hsize}{\raggedright#1}}

\begin{document}


\begin{table}[htbp]

\begin{tabularx}{\textwidth}{@{} C P{\mylena} c d{2.5} d{2.5} @{}}
\toprule
\textbf{Model} & \textbf{Research Question} & \textbf{Coeff.} & 
\mC{\textbf{Response A}} & \mC{\textbf{Response B}} \\ 
\midrule
\multirow{4}{*}{\mybox{%
$\begin{aligned}
Y&=\beta_{0} + \beta_{1} \mathrm{Income} + \beta_{2}(\mathrm{GrossSalary}-\mathrm{Housing}) \\
&\ + \beta_{3}(\mathrm{Dearness}-\mathrm{Extra}) + \delta_{1} \mathrm{Housing} + \delta_{2} \mathrm{Extra}
\end{aligned}$}} 
& RQ1a & $\delta_{1}$ & -0.094^{***} & -0.458^{***} \\
& & & (0.017) & (0.067) \\
\cmidrule(l){2-5}
& RQ1b & $\delta_{2}$ & -0.091^{***} & -0.210^{**} \\ 
& & & (0.020) & (0.039) \\
\midrule
\multirow{4}{*}{\mybox{%
$\begin{aligned}
Y&=\beta_{0} + \beta_{1} \mathrm{Income} + \beta_{2}(\mathrm{GrossSalary}-\mathrm{Housing}) \\
&\ + \beta_{3}(\mathrm{Dearness}-\mathrm{Extra}) + \delta_{1} \mathrm{Housing} + \delta_{2} \mathrm{Extra}
\end{aligned}$}} 
& RQ2 & $\delta_{1}$ & -0.020 & 0.039 \\
& & & (0.014) & (0.055) \\
\cmidrule(l){2-5}
& RQ2 & $\delta_{2}$ & 0.023^{\dagger} & 0.209^{***} \\ 
& & & (0.014) & (0.053) \\
\bottomrule
\addlinespace
\multicolumn{5}{@{}l}{\small\textit{Note:} Unstandardized coefficients with corrected standard errors in parentheses.}\\ 
\multicolumn{5}{@{}l}{\small$^{\dagger}\ p < .10$, $^{*}\ p < .05$, $^{**} p < .01$, $^{***} p <  .001$.}
\end{tabularx}

\caption{Caption}
\label{table2}
\end{table}

\end{document}

答案4

@Mico 解决方案的一个变体，使用\multline环境，\useshortskip来自nccmath和thead来自makecell：

\documentclass[a4paper,12pt]{extarticle}
\usepackage[T1]{fontenc}
\usepackage[utf8]{inputenc}
\usepackage[total={7in, 9in}]{geometry}

\usepackage{amsmath, booktabs, tabularx, ragged2e}
\usepackage{nccmath}
\usepackage{multirow,dcolumn, makecell}
\usepackage[stable]{footmisc}
\usepackage[justification=centering, skip=6pt]{caption}
\renewcommand{\theadfont}{\small\bfseries}
\usepackage{setspace}
\onehalfspacing

\usepackage{float}
\floatstyle{plaintop}
\restylefloat{table}

\usepackage{dcolumn}
\newcolumntype{d}[1]{D..{#1}}

\begin{document}

\begin{table}[!htbp]
\setlength{\tabcolsep}{4pt}\centering
\begin{tabularx}{\linewidth}{@{}>{\useshortskip}Xc c d{2.5} d{2.5} @{}}
\toprule
\thead{Model} & \thead{Research\\ Question} & \thead{Coeff.} &
\multicolumn{1}{c}{\thead{Response\\ A}} & \multicolumn{1}{c}{\thead{Response\\ B}} \\
\midrule
\multirow{2}{=}{%
\begin{multline}
Y=\beta_{0} + \beta_{1} \mathrm{Income} + \beta_{2}(\mathrm{GrossSalary}-\mathrm{Housing}) \\
  + \beta_{3}(\mathrm{Dearness}-\mathrm{Extra}) + \delta_{1} \mathrm{Housing} + \delta_{2} \mathrm{Extra}
\end{multline}}%
& RQ1a & $\delta_{1}$ & -0.094^{***} & -0.458^{***} \\
& & & (0.017) & (0.067) \\
\cmidrule(l){2-5}
& RQ1b & $\delta_{2}$ & -0.091^{***} & -0.210^{**} \\
& & & (0.020) & (0.039) \\
\midrule
\multirow{2}{=}{%
\begin{multline}
Y=\beta_{0} + \beta_{1} \mathrm{Income} + \beta_{2}(\mathrm{GrossSalary}-\mathrm{Housing}) \\
 + \beta_{3}(\mathrm{Dearness}-\mathrm{Extra}) + \delta_{1} \mathrm{Housing} + \delta_{2} \mathrm{Extra}
\end{multline}}
& RQ2 & $\delta_{1}$ & -0.020 & 0.039 \\
& & & (0.014) & (0.055) \\
\cmidrule(l){2-5}
& RQ2 & $\delta_{2}$ & 0.023^{\dagger} & 0.209^{***} \\
& & & (0.014) & (0.053) \\
\bottomrule
\addlinespace[0.6ex]
\multicolumn{5}{@{}l}{\small\textit{Note:} Unstandardized coefficients with corrected standard errors in parentheses.}\\
\multicolumn{5}{@{}l}{\small$^{\dagger}\ p < .10$,\enspace $^{*}\ p < .05$,\enspace $^{**} p < .01$,\enspace $^{***} p < .001$.}
\end{tabularx}
\caption{Caption}
\label{table2}
\end{table}

\end{document}

在此处输入图片描述

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