![呈现整齐排列的向量列表](https://linux22.com/image/405243/%E5%91%88%E7%8E%B0%E6%95%B4%E9%BD%90%E6%8E%92%E5%88%97%E7%9A%84%E5%90%91%E9%87%8F%E5%88%97%E8%A1%A8.png)
我正在编写一个文件,其中我必须以一种好的方式呈现 14 个长度为 14 的(列)特征向量。到目前为止,我已经尝试使用align*
环境,但没有得到想要的结果。基本上,我希望一行并排显示 7 个向量,第二行显示另外 7 个向量(或者如果空间允许,则全部显示在同一行),但我现在不知道如何逐个对齐它们,以使垂直长度对齐。
\documentclass[12pt]{article}
\usepackage[utf8]{inputenc}
\usepackage[T1]{fontenc}
\usepackage[english]{babel}
\usepackage{graphicx}
\usepackage{amsmath,amsfonts,amssymb,amsthm}
\usepackage{mathtools}
\usepackage{commath}
\usepackage[sc,osf]{mathpazo}
\usepackage{authblk}
\usepackage{calc}
\usepackage{tkz-graph}
\usepackage{tikz}
\begin{document}
\begin{align*}
\begin{pmatrix} 1 \\ 1 \\ 1 \\ 1 \\ 1 \\ 1 \\ 1 \\ 1 \\ 1 \\ 1 \\ 1 \\ 1 \\ 1 \end{pmatrix},
& \begin{pmatrix} 0 \\ \frac{1}{\sqrt{2}} \\ 0 \\ \frac{-1}{\sqrt{2}} \\ \frac{1}{\sqrt{2}} \\ \frac{-1}{\sqrt{2}} \\ 0 \\ 1 \\ -1 \\ 0 \\ 0 \\ 0 \\ 0 \\0 \end{pmatrix},
& \begin{pmatrix} 0 \\ \frac{1}{\sqrt{2}} \\ \frac{1}{\sqrt{2}} \\ \frac{-1}{\sqrt{2}} \\ 0 \\ 0 \\ \frac{-1}{\sqrt{2}} \\ 1 \\ 0 \\ -1 \\ 0 \\ 0 \\ 0 \\ 0 \\0 \end{pmatrix},
& \begin{pmatrix} 0 \\ \frac{1}{\sqrt{2}} \\ \frac{1}{\sqrt{2}} \\ \frac{-1}{\sqrt{2}} \\ 0 \\ 0 \\ \frac{-1}{\sqrt{2}} \\ 1 \\ 0 \\ -1 \\ 0 \\ 0 \\ 0 \\ 0 \\0 \end{pmatrix},
& \begin{pmatrix} 0 \\ \frac{1}{\sqrt{2}} \\ \frac{1}{\sqrt{2}} \\ \frac{-1}{\sqrt{2}} \\ 0 \\ 0 \\ \frac{-1}{\sqrt{2}} \\ 1 \\ 0 \\ -1 \\ 0 \\ 0 \\ 0 \\ 0 \\0 \end{pmatrix},
& \begin{pmatrix} 0 \\ \frac{1}{\sqrt{2}} \\ \frac{1}{\sqrt{2}} \\ \frac{-1}{\sqrt{2}} \\ 0 \\ 0 \\ \frac{-1}{\sqrt{2}} \\ 1 \\ 0 \\ -1 \\ 0 \\ 0 \\ 0 \\ 0 \\0 \end{pmatrix},
& \begin{pmatrix} 0 \\ \frac{1}{\sqrt{2}} \\ \frac{1}{\sqrt{2}} \\ \frac{-1}{\sqrt{2}} \\ 0 \\ 0 \\ \frac{-1}{\sqrt{2}} \\ 1 \\ 0 \\ -1 \\ 0 \\ 0 \\ 0 \\ 0 \\0 \end{pmatrix},
& \begin{pmatrix} 0 \\ \frac{1}{\sqrt{2}} \\ \frac{1}{\sqrt{2}} \\ \frac{-1}{\sqrt{2}} \\ 0 \\ 0 \\ \frac{-1}{\sqrt{2}} \\ 1 \\ 0 \\ -1 \\ 0 \\ 0 \\ 0 \\ 0 \\0 \end{pmatrix}
% \begin{pmatrix}1 & 1 & 1 & 1 & 1 & 1 & 1 & 1 & -1 & 1 & 1 & 0 & 0 & 0\end{pmatrix} \\
% \begin{pmatrix}1 & 1 & 1 & 1 & 1 & 1 & 1 & 1 & -1 & 1 & 1 & 0 & 0 & 0\end{pmatrix}
\end{align*}
\end{document}
答案1
以下是将整个向量集合设置到矩阵中的不同方法。您可以\arraycolsep
根据文本块中的可用空间调整列分隔 ( ) 以满足您的需求。
\documentclass{article}
\usepackage{amsmath,bm}
\usepackage[sc,osf]{mathpazo}
\setcounter{MaxMatrixCols}{20}% https://tex.stackexchange.com/q/95162/5764
\begin{document}
\[
\bm{\epsilon} =
\begin{bmatrix}
\bm{\epsilon}_1^T \\
\\
\vdots \\
\\
\bm{\epsilon}_{14}^T
\end{bmatrix} =
\setlength{\arraycolsep}{.8\arraycolsep}% Reduce array column separation by 20%
\begin{bmatrix}
1 & 1 & 1 & 1 & 1 & 1 & 1 & 1 & 1 & 1 & 1 & 1 & 1 & 1 \\ % 1
0 & s & 0 & -s & s & -s & 0 & 1 & -1 & 0 & 0 & 0 & 0 & 0 \\ % 2
0 & s & 0 & -s & s & -s & 0 & 1 & -1 & 0 & 0 & 0 & 0 & 0 \\ % 3
0 & -s & 1 & s & 0 & 0 & -s & 1 & 0 & 1 & 1 & 0 & 0 & -1 \\ % 4
-1 & s & 1 & s & 0 & 0 & -s & -1 & 0 & 1 & 1 & 0 & 0 & -1 \\ % 5
1 & s & 1 & s & 0 & 0 & -s & -1 & 0 & -1 & 1 & 0 & 0 & 1 \\ % 6
1 & s & 1 & -s & 0 & 1 & s & -1 & 0 & -1 & -1 & 0 & -1 & 0 \\ % 7
1 & s & 1 & s & 0 & 0 & -s & -1 & 0 & -1 & 1 & 0 & 0 & 1 \\ % 8
1 & s & 1 & s & 0 & 0 & -s & -1 & 0 & -1 & 1 & -1 & 0 & 1 \\ % 9
1 & s & 1 & s & 0 & 0 & -s & -1 & 0 & -1 & 1 & 0 & 0 & 1 \\ % 10
1 & s & 1 & s & 0 & 0 & -s & -1 & 0 & -1 & 1 & 0 & 0 & 1 \\ % 11
1 & s & 1 & s & 0 & 0 & -s & -1 & 0 & -1 & 1 & 0 & 0 & 1 \\ % 12
1 & s & 1 & s & 0 & 0 & -s & -1 & 0 & -1 & 1 & 0 & 0 & 1 \\ % 13
1 & s & 1 & s & 0 & 0 & -s & -1 & 0 & -1 & 1 & 0 & 0 & 1 % 14
\end{bmatrix}
\]
where $s = 1/\sqrt{2}$.
\end{document}