![使用多个“\paragraph”时出错](https://linux22.com/image/406271/%E4%BD%BF%E7%94%A8%E5%A4%9A%E4%B8%AA%E2%80%9C%5Cparagraph%E2%80%9D%E6%97%B6%E5%87%BA%E9%94%99.png)
我正在尝试使用 \paragraph 连续创建两个段落:
\begin{proof}
\paragraph{Case 1}
If $ \mu E_N = \infty $ for some $ N $, then $ \mu E_m = \infty $
for all $ m \geq N $. Also $ \cup E_n \supseteq E_N $. So $ \mu (\cup E_n ) = \infty $.
\paragraph{Case 2}
If $ \mu E_n < \infty $ for all $ n $, then set $ C_1 := E_1, C_n := E_n\setminus E_{n-1} $. Then $ \cup E_n := \sqcup C_n $. By our lemma, $ \mu C_n = \mu E_n - \mu E_{n-1} $. Then
\begin{align*}
\mu (\cup E_n) &= \mu (\sqcup C_n) \\
&= \sum_{n=1}^{\infty} \mu C_n \\
&= \lim_{N\to \infty } \sum_{n=1}^N \mu C_n \\
&= \lim_{N\to \infty } \mu E_N
\end{align*}
\end{proof}
但是 pdflatex 给出错误:
! LaTeX Error: Something's wrong--perhaps a missing \item.
See the LaTeX manual or LaTeX Companion for explanation.
Type H <return> for immediate help.
...
l.319 \paragraph
{Case 2}
我试过
\begin{enumerate}[label=Case(\arabic*)] ... \end{enumerate}
如错误消息所示,但标签与其余文本不一致。
答案1
在第一个之前您需要一些文本\paragraph
。
另一方面,我看不出它们有什么用处,所以我提供了不同的代码,修复了符号和墓碑。特别注意\bigcup
。
\documentclass{article}
\usepackage{amsmath,amsthm}
\begin{document}
\begin{proof}
We divide the proof into two cases.
\paragraph{Case 1}
If $ \mu E_N = \infty $ for some $ N $, then $ \mu E_m = \infty $
for all $ m \geq N $. Also $ \cup E_n \supseteq E_N $. So $ \mu (\cup E_n ) = \infty $.
\paragraph{Case 2}
If $ \mu E_n < \infty $ for all $ n $, then set $ C_1 := E_1, C_n := E_n\setminus E_{n-1} $.
Then $ \cup E_n := \sqcup C_n $. By our lemma, $ \mu C_n = \mu E_n - \mu E_{n-1} $. Then
\begin{align*}
\mu (\cup E_n) &= \mu (\sqcup C_n) \\
&= \sum_{n=1}^{\infty} \mu C_n \\
&= \lim_{N\to \infty } \sum_{n=1}^N \mu C_n \\
&= \lim_{N\to \infty } \mu E_N
\end{align*}
\end{proof}
\begin{proof}
We divide the proof into two cases.
\textbf{Case 1.}
If $ \mu E_N = \infty $ for some $ N $, then $ \mu E_m = \infty $
for all $ m \geq N $. Also $ \bigcup E_n \supseteq E_N $. So $ \mu (\bigcup E_n ) = \infty $.
\textbf{Case 2.}
If $ \mu E_n < \infty $ for all $ n $, then set $ C_1 := E_1, C_n := E_n\setminus E_{n-1} $.
Then $ \bigcup E_n := \bigsqcup C_n $. By our lemma, $ \mu C_n = \mu E_n - \mu E_{n-1} $. Then
\begin{align*}
\mu \Bigl(\bigcup E_n\Bigr) &= \mu \Bigl(\bigsqcup C_n\Bigr) \\
&= \sum_{n=1}^{\infty} \mu C_n \\
&= \lim_{N\to \infty } \sum_{n=1}^N \mu C_n \\
&= \lim_{N\to \infty } \mu E_N \qedhere
\end{align*}
\end{proof}
\end{document}
答案2
要将标签与enumerate
左边距对齐,只需使用此代码:
\usepackage{enumitem}
......
\begin{enumerate}[label=Case(\arabic*), wide=0pt, font=\bfseries]
\item ...
.........
\end{enumerate}