按边界均等调整分支距离

Question

看完之后这因此，我尝试了下面的例子，但是分支之间的距离现在是逐个中心计算的。我该如何改进它，让 3 个分支逐个边界均匀分布？

\documentclass{standalone}
\usepackage{tikz}
\usetikzlibrary{chains}
\begin{document}
    \begin{tikzpicture}
    \tikzset{
        node distance=0 and 2cm,
        start chain=going right,
        box/.style={on chain,draw,outer sep=0,inner sep=2pt},
        hide/.style={on chain,draw=none,inner sep=0},
    }

\node[hide]  {};
\begin{scope}[start branch=B1 going below]
    \foreach \x in {A,B,C,D} {
    \node[box,text width=2cm] (\x) {\x};
}
\end{scope}

\node[hide] {};
\begin{scope}[start branch=B2 going below]
    \foreach \x in {E,F,G,H,I,J,K} {
    \node[box,text width=1cm] (\x) {\x};
}
\end{scope}

\node[hide] {};
\begin{scope}[start branch=B3 going below]
\foreach \x in {L,M,N} {
    \node[box,text width=1cm] (\x) {\x};
}
\end{scope}
\end{tikzpicture}
\end{document}

输出：

Answer 1

您不需要任何hide节点或其他技巧，只需要一个matrix，就可以通过调整距离column sep。

\documentclass{standalone}
\usepackage{tikz}
\usetikzlibrary{chains}
\begin{document}
    \begin{tikzpicture}
    \tikzset{
        node distance=0 and 2cm,
        box/.style={on chain,draw,outer sep=0,inner sep=2pt},
    }
\matrix[column sep=3em]{
\begin{scope}[start chain=going below]
    \foreach \x in {A,B,C,D} {
    \node[box,text width=2cm] (\x) {\x};
}
\end{scope}
&
\begin{scope}[start chain=going below]
    \foreach \x in {E,F,G,H,I,J,K} {
    \node[box,text width=1cm] (\x) {\x};
}
\end{scope}
& 
\begin{scope}[start chain=going below]
\foreach \x in {L,M,N} {
    \node[box,text width=1cm] (\x) {\x};
}
\end{scope}
\\
};
\end{tikzpicture}
\end{document}