如何在乳胶中两个节点之间画一条虚线

Question

如何在 latex 中在两个节点之间画一条虚线。我使用了下面的命令，但无法用虚线连接两个节点 3 和 4。

\begin{tikzpicture}[->,>=stealth',shorten >=1pt,auto,node distance=3cm,
        thick,main node/.style={circle,draw,font=\sffamily\Large\bfseries}]

    \node[main node] (1) {$1$};
    \node[main node] (2) [above of=1] {$2$};
    \node[main node] (3) [above of=2] {$3$};
    \node[main node] (4) [above of=3] {$4$};
    \path[every node/.style={font=\sffamily\small}]
    (1)  edge node [above] {} (2)
    edge [loop left] node {} (1) (1)
    (2)  edge node [above] {} (3)
    edge [loop left] node {} (2) (2)
    (3) edge node [above] {} (4)
    edge [loop left] node {} (3) (3);

    \end{tikzpicture}

Answer 1

正如@CFG在他的评论中提到的那样，将选项添加\dotted到边缘，该边缘应该是虚线。 我还使用了库positioning并稍微重新排列了您的代码：

\documentclass[tikz, margin=3mm]{standalone}
\usetikzlibrary{arrows,
                positioning}

\begin{document}
    \begin{tikzpicture}[auto,
    node distance = 12mm,
every edge/.style = {draw, -stealth', shorten >=1pt, thick},
 main node/.style = {circle,draw,font=\Large\sffamily\bfseries}
                        ]
\node[main node] (1)                {$1$};
\node[main node] (2) [above=of 1]   {$2$};
\node[main node] (3) [above=of 2]   {$3$};
\node[main node] (4) [above=of 3]   {$4$};
%
\path[every node/.style={font=\sffamily\small}]
    (1) edge                node [right] {} (2)
        edge [loop left]    node {} () 
    (2) edge                node [right] {} (3)
        edge [loop left]    node {} ()
    (3) edge [dotted]       node [right] {} (4) % <---
        edge [loop left]    node {} ();
    \end{tikzpicture}
\end{document}

您会标记边吗？到目前为止，节点都是空的。如果您不会，请删除它们。