![如何表示给定图中的交点](https://linux22.com/image/409822/%E5%A6%82%E4%BD%95%E8%A1%A8%E7%A4%BA%E7%BB%99%E5%AE%9A%E5%9B%BE%E4%B8%AD%E7%9A%84%E4%BA%A4%E7%82%B9.png)
我想用 Q 表示直线 CD 和 AB 的交点,然后想遮蔽特定区域 PBQF,但以下代码出现错误,请帮忙...
\begin{tikzpicture}
\draw (0,5)--(0,0)--(4,0)node(f){F} %(2,0)node(a){A}--(0,4)node(b){B}
%(3,0)node(c){C}--(0,2.4)node(d){D}
(4,0)--(0,2)node(e){E} (0,5)node(p){P};
\draw[name path=P3] (2,0)node(a){A}--(0,4)node(b){B};
\draw[name path=P4] (3,0)node(c){C}--(0,2.4)node(d){D};
\path [name intersections={of=P3 and P4,by=Q}];
\node [dot=Q] at (Q) {};
\begin{pgfonlayer}{bg} % select background
\path [fill=orange!50] (p.center)--(b.center) -- (p.center) -- (f.center) --(Q.center)-- cycle;
\end{pgfonlayer}
\end{tikzpicture}
答案1
您的代码片段没有用。它包含错误和一些混乱,因此几乎不可能弄清楚您喜欢绘制什么。根据我的猜测和我之前对您问题的回答,看看以下 MWE 是否给出了您想要的内容:
\documentclass[tikz, margin=3mm]{standalone}
\usetikzlibrary{backgrounds,
intersections,
positioning}
\begin{document}
\begin{tikzpicture}[auto=right,
dot/.style = {circle, fill, inner sep=1pt},
every edge/.style = {draw, shorten >=-12mm},
every label/.style = {inner sep=1.5pt}
]
\coordinate (o);
\coordinate[label=below:A,right=2 of o] (a);
\coordinate[label=below:C,right=1 of a] (c);
\coordinate[label=below:F,right=1 of c] (f);
%
\coordinate[label=left: E,above=2 of o] (e);
\coordinate[label=left: D,above=1 of e] (d);
\coordinate[label=left: B,above=2 of d] (b);
\coordinate[label=left: P,above=2 of b] (p);
%
\draw (p) |- (f);
\draw[name path=AB] (a) -- (b);
\draw[name path=CD] (c) -- (d);
\path [name intersections={of=AB and CD,by=q}] node[dot, label=above right:Q] at (q) {};
%
\scoped[on background layer]
\fill[orange!50] (b) -- (d) -- (q) -- (a) -- (c) -- (q); % it is not clear, what you like to fill ... so two options
\fill[green!20,semitransparent] (p) -- (b) -- (q) -- (c) -- (f) -- (q);
\end{tikzpicture}
\end{document}