我目前有一张表格,总结了一些门及其操作,但它看起来不合适,格式也不正确。有人知道如何将图像与文本对齐吗?此外,在“效果”列中,我希望文本一个接一个地排列。请参阅下面的 Latex 代码和附加的图像。
\begin{figure}
\centering
\begin{threeparttable}
\begin{tabular}{cccc}
%{m{15mm} m{70mm} m{18mm}}
Gates & Circuit Symbol & Matrix Representation & Effect\\
\midrule\midrule
Pauli-X &
\includegraphics[scale = 1 , trim= {50 50 32 25}, clip
]{Chapter2/Figs/Raster/x.png} &
$U(\pi, 0 , \pi) =
\begin{pmatrix}
0 & 1 \\
1& 0
\end{pmatrix}$ &
\begin{itemize}
\item $\emph{X}\ket{0}\longrightarrow\ket{1}$
\item $\emph{X}\ket{1}\longrightarrow\ket{0}$
\end{itemize}
\\%new row
Pauli-Y &
\includegraphics[scale = 1 , trim= {50 50 32 25}, clip
]{Chapter2/Figs/Raster/y.png} &
$U(\pi , \frac{\pi}{2},\frac{\pi}{2}) =
\begin{pmatrix}
0 & -i \\
i & 0
\end{pmatrix}$ &
\begin{itemize}
\item $\emph{Y}\ket{0}\longrightarrow i\ket{1}$
\item $\emph{Y}\ket{1}\longrightarrow-i\ket{0}$,
\end{itemize}
\\%new row
Pauli-Z &
\includegraphics[scale = 1 , trim= {50 50 32 25}, clip
]{Chapter2/Figs/Raster/z.png} &
$U(0 , 0 , \pi) =
\begin{pmatrix}
1 & 0 \\
0 & -1
\end{pmatrix}$ &
\begin{itemize}
\item $\emph{Z}\ket{0}\longrightarrow\ket{0}$
\item $\emph{Z}\ket{1}\longrightarrow-\ket{1}$
\end{itemize}
\\%new row
Hadamard &
\includegraphics[scale = 1 , trim= {50 50 32 25}, clip
]{Chapter2/Figs/Raster/h.png} &
$U(\frac{\pi}{2},0 , \pi) = \frac{1}{\sqrt{2}}
\begin{pmatrix}
1 & 1 \\
1 & -1
\end{pmatrix}$ &
\begin{itemize}
\item $\emph{H}\ket{0}\longrightarrow \frac{1}{\sqrt{2}}(\ket{0}+\ket{1})$
\item $\emph{H}\ket{1}\longrightarrow \frac{1}{\sqrt{2}}(\ket{0}-\ket{1})$ \end{itemize}
\\% end of rows
\midrule\midrule
\end{tabular}
\begin{tablenotes}
\caption{Names, circuit symbols and unitary matrix representation for common single qubit gates.}
\end{tablenotes}
\end{threeparttable}
\end{figure}
答案1
要将图像垂直居中于表格单元格内,您可以\raisebox{-0.5\height}
在 之前使用\includegraphics
。使用简单的表格和标准示例图像,这是使用和不使用 时获得的结果。\raisebox{-0.5\height}
完整代码如下
\documentclass[leqno]{article}
\usepackage{graphicx}
\usepackage{booktabs}
\begin{document}
%
%
\begin{table}
\centering
\caption{Vertical centering of figures in cells.}
\begin{tabular}{lll}
\toprule
Column1 & Column2 & Column3 \\
\midrule
Cols1 & \raisebox{-0.5\height}{\includegraphics[width=2cm]{example-image}} & Cols3 \\
Cols1 & \raisebox{-0.5\height}{\includegraphics[width=4cm]{example-image}} & Cols3 \\
Cols1 & Cols2 & Cols3 \\
\bottomrule
\end{tabular}
\end{table}
%
\begin{table}
\centering
\caption{NO vertical centering of figures in cells.}
\begin{tabular}{lll}
\toprule
Column1 & Column2 & Column3 \\
\midrule
Cols1 & \includegraphics[width=2cm]{example-image} & Cols3 \\
Cols1 & \includegraphics[width=4cm]{example-image} & Cols3 \\
Cols1 & Cols2 & Cols3 \\
\bottomrule
\end{tabular}
\end{table}
%
\end{document}
祝你好运!
答案2
这是我建议使用valign=c
该软件包附带的adjustbox
。我还添加了一个自定义版本以itemize
供此表内使用。
\documentclass{article}
\usepackage{graphicx}
\usepackage[export]{adjustbox}
\usepackage{amsmath}
\usepackage{booktabs}
%\usepackage{threeparttable}
\usepackage{array}
\usepackage{physics}
\usepackage{enumitem}
\newlist{tabitem}{itemize}{1}
\setlist[tabitem]{wide=0pt, leftmargin= * ,label=\textbullet}
\begin{document}
\begin{figure}
\centering
% \begin{threeparttable}
\begin{tabular}{cccm{37mm}}
%{m{15mm} m{70mm} m{18mm}}
Gates & Circuit Symbol & Matrix Representation & Effect\\
\midrule\midrule
Pauli-X &
\includegraphics[width=1cm, valign=c]{example-image} &
$U(\pi, 0 , \pi) =
\begin{pmatrix}
0 & 1 \\
1& 0
\end{pmatrix}$ &
\begin{tabitem}
\item $\emph{X}\ket{0}\longrightarrow\ket{1}$
\item $\emph{X}\ket{1}\longrightarrow\ket{0}$
\end{tabitem}
\\%new row
Pauli-Y &
\includegraphics[width=1cm, valign=c]{example-image} &
$U(\pi , \frac{\pi}{2},\frac{\pi}{2}) =
\begin{pmatrix}
0 & -i \\
i & 0
\end{pmatrix}$ &
\begin{tabitem}
\item $\emph{Y}\ket{0}\longrightarrow i\ket{1}$
\item $\emph{Y}\ket{1}\longrightarrow-i\ket{0}$,
\end{tabitem}
\\%new row
Pauli-Z &
\includegraphics[width=1cm, valign=c]{example-image} &
$U(0 , 0 , \pi) =
\begin{pmatrix}
1 & 0 \\
0 & -1
\end{pmatrix}$ &
\begin{tabitem}
\item $\emph{Z}\ket{0}\longrightarrow\ket{0}$
\item $\emph{Z}\ket{1}\longrightarrow-\ket{1}$
\end{tabitem}
\\%new row
Hadamard &
\includegraphics[width=1cm, valign=c]{example-image} &
$U(\frac{\pi}{2},0 , \pi) = \frac{1}{\sqrt{2}}
\begin{pmatrix}
1 & 1 \\
1 & -1
\end{pmatrix}$ &
\begin{tabitem}
\item $\emph{H}\ket{0}\longrightarrow \frac{1}{\sqrt{2}}(\ket{0}+\ket{1})$
\item $\emph{H}\ket{1}\longrightarrow \frac{1}{\sqrt{2}}(\ket{0}-\ket{1})$
\end{tabitem}
\\% end of rows
\midrule\midrule
\end{tabular}
% \begin{tablenotes}
%
%\end{tablenotes}
%\end{threeparttable}
\caption{Names, circuit symbols and unitary matrix representation for common single qubit gates.}
\end{figure}
\end{document}