TikZ Matrix 覆盖特定列/行的每列/行样式

Question

“覆盖”是下列摘录的结果tikz.code.tex：

\def\tikz@common@matrix@code{%
  \let\tikz@options=\pgfutil@empty%
  \let\tikz@mode=\pgfutil@empty%
  \tikzset{every cell/.try={\the\pgfmatrixcurrentrow}{\the\pgfmatrixcurrentcolumn}}%
  \tikzset{column \the\pgfmatrixcurrentcolumn/.try}%
  \ifodd\pgfmatrixcurrentcolumn%
    \tikzset{every odd column/.try}%
  \else%
    \tikzset{every even column/.try}%
  \fi%
  \tikzset{row \the\pgfmatrixcurrentrow/.try}%
  \ifodd\pgfmatrixcurrentrow%
    \tikzset{every odd row/.try}%
  \else%
    \tikzset{every even row/.try}%
  \fi%
  \tikzset{row \the\pgfmatrixcurrentrow\space column \the\pgfmatrixcurrentcolumn/.try}%
  \tikz@options%
}%

如您所见，它会按特定顺序浏览列和行选项。具体来说，它会查看行后列。因此，正如您所说，列的样式通常会被行的样式覆盖。

然而，这个问题远非无法解决。相反，我发现在大多数情况下，直接使用计数\pgfmatrixcurrentcolumn和是最方便的\pgfmatrixcurrentrow。这允许你实现你喜欢的任何规则。在你的例子中，你的目标可以通过一些代码来实现，这些代码计算一个整数来标记案例，

\pgfmathtruncatemacro{\itest}{ifthenelse(%
    \pgfmatrixcurrentcolumn==7||\pgfmatrixcurrentrow==6,0,%
     ifthenelse(isodd(\pgfmatrixcurrentrow),1,2))}

然后使用\ifcase，

\ifcase\itest
\tikzset{fill=green!10, font=\bfseries}%
\or
\tikzset{fill=yellow!10}%
\or
\fi

这种方法非常强大，因为您可以实现更一般的条件，如模条件，或行和列索引的更一般的函数。

以下是完整的代码。

\documentclass{article}

\usepackage{tikz}
\usetikzlibrary{matrix}
\tikzset{cond/.code={%
\pgfmathtruncatemacro{\itest}{ifthenelse(%
    \pgfmatrixcurrentcolumn==7||\pgfmatrixcurrentrow==6,0,%
     ifthenelse(isodd(\pgfmatrixcurrentrow),1,2))}
%\typeout{\the\pgfmatrixcurrentcolumn,\pgfmatrixcurrentrow->\itest}  
\ifcase\itest
\tikzset{fill=green!10, font=\bfseries}%
\or
\tikzset{fill=yellow!10}%
\or
\fi
}}
\begin{document}
\begin{tikzpicture}
\matrix [
  matrix of nodes,
  row sep=-\pgflinewidth,
  column sep=-\pgflinewidth,
  nodes={draw, anchor=center, minimum size=.75cm,cond},
  column 6/.style={column sep=5pt},
  row 5/.style={row sep=5pt},
] {
  1 & 1 & 1 & 0 & 1 & 0 & 0 \\
  0 & 0 & 1 & 0 & 1 & 1 & 1 \\
  0 & 1 & 0 & 1 & 1 & 0 & 1 \\
  0 & 1 & 1 & 0 & 0 & 0 & 0 \\
  1 & 0 & 1 & 1 & 0 & 1 & 0 \\
  0 & 1 & 0 & 0 & 1 & 0 & \\
};
\end{tikzpicture}
\end{document}

附录: 关于这个问题，您还可以安装一些重新排序的样式。

\documentclass{article}

\usepackage{tikz}
\usetikzlibrary{matrix}
\makeatletter
\tikzset{reorder matrix styles/.style={execute at begin matrix={
\def\tikz@common@matrix@code{%
  \let\tikz@options=\pgfutil@empty%
  \let\tikz@mode=\pgfutil@empty%
  \tikzset{every cell/.try={\the\pgfmatrixcurrentrow}{\the\pgfmatrixcurrentcolumn}}%
  \ifodd\pgfmatrixcurrentcolumn%
    \tikzset{every odd column/.try}%
  \else%
    \tikzset{every even column/.try}%
  \fi%
  \ifodd\pgfmatrixcurrentrow%
    \tikzset{every odd row/.try}%
  \else%
    \tikzset{every even row/.try}%
  \fi%
  \tikzset{column \the\pgfmatrixcurrentcolumn/.try}%
  \tikzset{row \the\pgfmatrixcurrentrow/.try}%
  \tikzset{row \the\pgfmatrixcurrentrow\space column \the\pgfmatrixcurrentcolumn/.try}%
  \tikz@options%
}%
}}}
\makeatother
\begin{document}
\begin{tikzpicture}[reorder matrix styles]
\matrix [
  matrix of nodes,
  row sep=-\pgflinewidth,
  column sep=-\pgflinewidth,
  nodes={draw, anchor=center, minimum size=.75cm},
  every odd row/.style={nodes={fill=yellow!10}},
  column 6/.style={column sep=5pt},
  column 7/.style={nodes={fill=green!10, font=\bfseries}},
  row 5/.style={row sep=5pt},
  row 6/.style={nodes={fill=green!10, font=\bfseries}}
] {
  1 & 1 & 1 & 0 & 1 & 0 & 0 \\
  0 & 0 & 1 & 0 & 1 & 1 & 1 \\
  0 & 1 & 0 & 1 & 1 & 0 & 1 \\
  0 & 1 & 1 & 0 & 0 & 0 & 0 \\
  1 & 0 & 1 & 1 & 0 & 1 & 0 \\
  0 & 1 & 0 & 0 & 1 & 0 & \\
};
\end{tikzpicture}
\end{document}

这会产生与上面相同的输出。但请注意，这有点儿像 hack，你可以想象到崩溃的情况。

Answer 1