简单的 tikz 通量图中的向上箭头

Question

我一直在尝试实现如下图所示的向上箭头，但在 Tikz 上实现它时遇到了很多麻烦。我的主要问题是关闭循环的向上箭头，我无法让它从侧面向上到达右侧的实现块。

我一直在测试的代码是这样的：

\tikzset{
    block/.style = {draw, rectangle,
        minimum height=2cm,
        minimum width=3cm},
    input/.style = {coordinate,node distance=1cm},
    output/.style = {coordinate,node distance=1cm},
    arrow/.style={draw, -latex,node distance=3cm},
    pinstyle/.style = {pin edge={latex-, black,node distance=2cm}},
    sum/.style = {draw, circle, node distance=1cm},
}



\begin{figure}[ht]
\begin{center}
    \begin{tikzpicture}[auto, node distance=1.5cm,>=latex']
    \node [block, name=input] {Implementation};
    \node [block, below=of input] (controller) {Optimization};
    \draw [->] (input) -- node {Data} (controller);
    \draw [->] (controller) |- node {Control Inputs} (input);
    \end{tikzpicture}  
\end{center}
\caption{TikzPicture}\label{fig}
\end{figure}

有什么建议关于如何实现侧面向外的箭头吗？

Answer 1

您已接近所需箭头位置：\draw [->] (controller) |- node {Control Inputs} (input);您应该写\draw [->] (controller.east) -- ++ (1,0) |- node {Control Inputs} (input);

完整的 MWE（具有更改的节点名称和仅相关的样式定义）：

\documentclass[tikz, margin=3mm]{standalone}
\usetikzlibrary{arrows.meta,
                positioning,
                quotes}

\begin{document}
    \begin{tikzpicture}[auto=right,
node distance = 12mm and 8mm,
 block/.style = {draw=blue, very thick, rounded corners, 
                 minimum height=2cm, minimum width=3cm,
                 top color=blue!10, bottom color=blue!50},
   arr/.style = {-Stealth, thick, rounded corners}
                        ]
\node (in)      [block]                 {Implementation};
\node (cntrl)   [block, below=of in]    {Optimization};
\draw [arr] (in)    edge ["Data"] (cntrl) 
            (cntrl.east) -- ++(1,0) |- (in)     % <---
            node[pos=0.25, align=left] {Control\\ Inputs} (in);
    \end{tikzpicture}
\end{document}