我正在使用该longtable包以及booktabs样式规则和交替行颜色。MWE
\documentclass{article}
\usepackage[a6paper]{geometry}
\usepackage[T1]{fontenc}
\usepackage[utf8]{inputenc}
\usepackage{lmodern}
\usepackage{threeparttablex}
\usepackage{longtable}
\usepackage{booktabs}
\usepackage[table]{xcolor}
\usepackage{calc}
\begin{document}
\begin{ThreePartTable}
\rowcolors{2}{white}{gray}
\begin{longtable}{p{.333\textwidth-2\tabcolsep}p{.333\textwidth-2\tabcolsep}p{.333\textwidth-2\tabcolsep}}
\caption{Lorem Ipsum.}\\
\toprule
Lorem & Ipsum & Dolor\\
\midrule
\endfirsthead
Lorem & Ipsum & Dolor\\
\midrule
\endhead
\hline
\multicolumn{3}{r}{(\emph{continued on next page})} \\
\endfoot
\bottomrule
\endlastfoot
foo & bar & foo\\
foo & bar & foo\\
foo & bar & foo\\
foo & bar & foo\\
foo & bar & foo\\
foo & bar & foo\\
foo & bar & foo\\
foo & bar & foo\\
foo & bar & foo\\
foo & bar & foo\\
foo & bar & foo\\
foo & bar & foo\\
foo & bar & foo\\
foo & bar & foo\\
foo & bar & foo\\
foo & bar & foo\\
foo & bar & foo\\
foo & bar & foo\\
foo & bar & foo\\
foo & bar & foo\\
foo & bar & foo\\
foo & bar & foo\\
foo\newline foo & bar & foo\\
foo & bar & foo\\
foo & bar & foo\\
foo & bar & foo\\
foo & bar & foo\\
foo & bar & foo\\
foo & bar & foo\\
foo & bar & foo\\
foo & bar & foo\\
foo & bar & foo\\
foo & bar & foo\\
foo & bar & foo\\
foo & bar & foo\\
foo & bar & foo\\
foo & bar & foo\\
foo & bar & foo\\
foo & bar & foo\\
foo & bar & foo\\
foo & bar & foo\\
foo & bar & foo\\
foo & bar & foo\\
foo & bar & foo\\
foo & bar & foo\\
foo & bar & foo\\
\end{longtable}
\end{ThreePartTable}
\end{document}
会给：
\midrule第 3 页的第一行和最后一行之间有一些空白。\bottomrule我从这个答案可以使用\belowrulesepcolor和来填补这些空白\aboverulesepcolor：
\documentclass{article}
\usepackage[a6paper]{geometry}
\usepackage[T1]{fontenc}
\usepackage[utf8]{inputenc}
\usepackage{lmodern}
\usepackage{threeparttablex}
\usepackage{longtable}
\usepackage{booktabs}
\usepackage[table]{xcolor}
\usepackage{calc}
\newcommand*{\belowrulesepcolor}[1]{%
\noalign{%
\kern-\belowrulesep
\begingroup
\color{#1}%
\hrule height\belowrulesep
\endgroup
}%
}
\newcommand*{\aboverulesepcolor}[1]{%
\noalign{%
\begingroup
\color{#1}%
\hrule height\aboverulesep
\endgroup
\kern-\aboverulesep
}%
}
\begin{document}
\begin{ThreePartTable}
\rowcolors{2}{white}{gray}
\begin{longtable}{p{.333\textwidth-2\tabcolsep}p{.333\textwidth-2\tabcolsep}p{.333\textwidth-2\tabcolsep}}
\caption{Lorem Ipsum.}\\
\toprule
Lorem & Ipsum & Dolor\\
\midrule
\endfirsthead
Lorem & Ipsum & Dolor\\
%\aboverulesepcolor{gray}
\midrule
\belowrulesepcolor{gray}
\endhead
\hline
\multicolumn{3}{r}{(\emph{continued on next page})} \\
\endfoot
\aboverulesepcolor{gray}
\bottomrule
\endlastfoot
foo & bar & foo\\
foo & bar & foo\\
foo & bar & foo\\
foo & bar & foo\\
foo & bar & foo\\
foo & bar & foo\\
foo & bar & foo\\
foo & bar & foo\\
foo & bar & foo\\
foo & bar & foo\\
foo & bar & foo\\
foo & bar & foo\\
foo & bar & foo\\
foo & bar & foo\\
foo & bar & foo\\
foo & bar & foo\\
foo & bar & foo\\
foo & bar & foo\\
foo & bar & foo\\
foo & bar & foo\\
foo & bar & foo\\
foo & bar & foo\\
foo\newline foo & bar & foo\\
foo & bar & foo\\
foo & bar & foo\\
foo & bar & foo\\
foo & bar & foo\\
foo & bar & foo\\
foo & bar & foo\\
foo & bar & foo\\
foo & bar & foo\\
foo & bar & foo\\
foo & bar & foo\\
foo & bar & foo\\
foo & bar & foo\\
foo & bar & foo\\
foo & bar & foo\\
foo & bar & foo\\
foo & bar & foo\\
foo & bar & foo\\
foo & bar & foo\\
foo & bar & foo\\
foo & bar & foo\\
foo & bar & foo\\
foo & bar & foo\\
foo & bar & foo\\
\end{longtable}
\end{ThreePartTable}
\end{document}
这将给出：
但是，尽管第 2 页的第一行是白色的，但它前面也会有一个灰色条。有没有办法让它更强大，例如使用一些使用当前行号的 if-else 语句？谢谢。
答案1
使用新 LaTeX3 包的替代解决方案tabularray：
\documentclass{article}
\usepackage[a6paper]{geometry}
\usepackage{xcolor}
\usepackage{tabularray}
\UseTblrLibrary{booktabs}
\begin{document}
\begin{longtblr}[
caption = {Lorem Ipsum},
note{a} = {First note.},
note{b} = {Second note.},
]{
colspec={XXX},
row{odd} = {gray8},
row{1} = {white},
rowhead = 1,
rowsep = 1pt,
}
\toprule
Lorem & Ipsum & Dolor\\
\midrule
foo & bar & foo\\
foo & bar & foo\\
foo & bar & foo\\
foo & bar & foo\\
foo & bar & foo\\
foo & bar & foo\\
foo & bar & foo\\
foo & bar & foo\\
foo & bar & foo\\
foo & bar & foo\\
foo & bar & foo\\
foo & bar & foo\\
foo & bar & foo\\
foo & bar & foo\\
foo & bar & foo\\
foo & bar & foo\\
foo & bar & foo\\
foo & bar & foo\\
foo & bar & foo\\
foo & bar & foo\\
foo & bar & foo\\
foo & bar & foo\\
foo\newline foo & bar & foo\\
foo & bar & foo\\
foo & bar & foo\\
foo & bar & foo\\
foo & bar & foo\\
foo & bar & foo\\
foo & bar & foo\\
foo & bar & foo\\
foo & bar & foo\\
foo & bar & foo\\
foo & bar & foo\\
foo & bar & foo\\
foo & bar & foo\\
foo & bar & foo\\
foo & bar & foo\\
foo & bar & foo\\
foo & bar & foo\\
foo & bar & foo\\
foo & bar & foo\\
foo & bar & foo\\
foo & bar & foo\\
foo & bar & foo\\
foo & bar & foo\\
foo & bar & foo\\
\bottomrule
\end{longtblr}
\end{document}
答案2
这个解决方案怎么样？这个包似乎longtable以一种奇怪的方式执行代码，这意味着需要一些变通方法才能解决问题。如果你对此没意见，我认为这应该足够了。
\documentclass{article}
\usepackage{booktabs}
\usepackage[a6paper]{geometry}
\usepackage{expl3}
\usepackage{array}
\usepackage{xcolor, colortbl}
\usepackage{longtable}
\begin{document}
% define some colors
\definecolor{colora}{HTML}{00bfff}
\definecolor{colorb}{HTML}{ffffff}
\definecolor{colorc}{HTML}{00ff7f}
\definecolor{colord}{HTML}{ffffff}
\ExplSyntaxOn
% set up the list of colors to be used
\clist_new:N \l_colors_clist
\clist_set:Nn \l_colors_clist {colora, colorb, colorc, colord}
\int_new:N \l_color_ind_int
% the function that computes color index
\cs_new:Npn \__compute_color_index:n #1 {
\int_set:Nn \l_tmpb_int { \clist_count:N \l_colors_clist }
\int_set:Nn \l_tmpa_int { \int_div_truncate:nn {#1} {\l_tmpb_int} }
\int_gset:Nn \l_color_ind_int { #1 - \l_tmpa_int * \l_tmpb_int + 1}
}
\int_new:N \l_list_ind_int
\bool_new:N \l_is_header_bool
\cs_new:Npn \resetlistindex {
\int_gset:Nn \l_list_ind_int {0}
\bool_gset_false:N \l_is_header_bool
\__compute_color_index:n {\l_list_ind_int}
}
\cs_new:Npn \calloneachrow {
\bool_if:NTF \l_is_header_bool {
\bool_gset_false:N \l_is_header_bool
} {
% increment row counter
\int_gincr:N \l_list_ind_int
\__compute_color_index:n {\l_list_ind_int}
}
}
% this function sets correct cell color
\cs_new:Npn \calloneachcell {
\bool_if:NTF \l_is_header_bool {}
{
% get color name
\tl_set:Nx \l_tmpa_tl { \clist_item:Nn \l_colors_clist {\l_color_ind_int} }
% use this color
\exp_args:No \cellcolor {\l_tmpa_tl}
}
}
% suppress color in header
\cs_new:Npn \callonheader {
\bool_gset_true:N \l_is_header_bool
}
\ExplSyntaxOff
% unfortunately, using \rowcolor directly doesn't seem to work
% therefore, I use the following workaround:
% declare a new column type, which calls \calloneachcell every time
\newcolumntype{C}{>{\calloneachcell}c}
% set list index to 0
\resetlistindex
\begin{longtable}{CCC<{\calloneachrow}}
\caption{Caption}\\
\toprule
\callonheader %suppress background color for headers
% here, I need to explicitly execute \cellcolor{white}
% because the code of column type C will be executed
% before \callonheader, which means the first cell will
% have background color. I simply just override it with
% white color.
\cellcolor{white} Lorem & Ipsum & Dolor\\
\midrule
\endfirsthead
\callonheader %suppress background color for headers
\cellcolor{white} Lorem & Ipsum & Dolor\\
\midrule
\endhead
\hline
\multicolumn{3}{r}{(\emph{continued on next page})} \\
\endfoot
\bottomrule
\endlastfoot
foo & bar & foo\\
foo & bar & foo\\
foo & bar & foo\\
foo & bar & foo\\
foo & bar & foo\\
foo & bar & foo\\
foo & bar & foo\\
foo & bar & foo\\
foo & bar & foo\\
foo & bar & foo\\
foo & bar & foo\\
foo & bar & foo\\
foo & bar & foo\\
foo & bar & foo\\
foo & bar & foo\\
foo & bar & foo\\
foo & bar & foo\\
foo & bar & foo\\
foo & bar & foo\\
foo & bar & foo\\
foo & bar & foo\\
foo & bar & foo\\
% need to use a \parbox to wrap around \newline
\parbox{3ex}{foo\newline} & bar & foo\\
foo & bar & foo\\
foo & bar & foo\\
foo & bar & foo\\
foo & bar & foo\\
foo & bar & foo\\
foo & bar & foo\\
foo & bar & foo\\
foo & bar & foo\\
foo & bar & foo\\
foo & bar & foo\\
foo & bar & foo\\
foo & bar & foo\\
foo & bar & foo\\
foo & bar & foo\\
foo & bar & foo\\
foo & bar & foo\\
foo & bar & foo\\
foo & bar & foo\\
foo & bar & foo\\
foo & bar & foo\\
foo & bar & foo\\
foo & bar & foo\\
foo & bar & foo\\
\end{longtable}
\end{document}