为什么下面的代码会画一条倾斜的线?我以为总和 ($(1,6) + (2,0)$) 会返回一个点 (3,6)。
\documentclass[dvipsnames]{article}
\usepackage[utf8]{inputenc}
\usepackage{xcolor}
\usepackage{pgfplots,tikz}
\usetikzlibrary{babel,calc,backgrounds,quotes,angles,patterns,decorations.markings,intersections,arrows,arrows.meta}
\pgfplotsset{compat=newest}
\usepgflibrary{arrows}
\usepgfplotslibrary{fillbetween}
\begin{document}
\begin{tikzpicture}
\begin{axis}[ axis lines = middle,
xmin = -1,
ymin = -5,
xmax = 10,
ymax = 14,
domain = -1:10,
xtick = {1,2,...,9},
ytick = \empty,
xlabel style={below right},
ylabel style={above left},
x tick label style={below},
samples = 100,
axis on top=true,
xlabel = {$x$},
ylabel = {$f$}
]
\addplot[very thick, domain=0:11] {5 + x};
\draw[thick, dashed] (1,6) -- ($(1,6) + (2,0)$);
\end{axis}
\end{tikzpicture}
\end{document}
结果是:
提前致谢!
答案1
来自 pgfplots 文档:
为了表达相对位置(或长度),需要使用轴方向 cs。
所以你必须使用:
\draw[thick, dashed] (1,6) -- ($(1,6) + (axis direction cs:2,0)$);
例子:
\documentclass[dvipsnames]{article}
%\usepackage[utf8]{inputenc}% need for outdated TeX distributions
\usepackage{pgfplots}% loads tikz and xcolor
\pgfplotsset{compat=newest}
\usetikzlibrary{babel,calc,backgrounds,quotes,angles,patterns,decorations.markings,intersections,arrows,arrows.meta}
\usepgfplotslibrary{fillbetween}
\begin{document}
\begin{tikzpicture}
\begin{axis}[ axis lines = middle,
xmin = -1,
ymin = -5,
xmax = 10,
ymax = 14,
domain = -1:10,
xtick = {1,2,...,9},
ytick = \empty,
xlabel style={below right},
ylabel style={above left},
x tick label style={below},
samples = 100,
axis on top=true,
xlabel = {$x$},
ylabel = {$f$}
]
\addplot[very thick, domain=0:11] {5 + x};
\draw[thick, dashed] (1,6) -- ($(1,6) + (axis direction cs:2,0)$);
\end{axis}
\end{tikzpicture}
\end{document}
解释
轴内部的坐标axis cs
默认使用。
来自文档:
的效果
axis cs
是应用任何自定义转换(包括symbolic x coords
)、对数、数据缩放转换或 pgfplots 通常执行的任何操作并提供低级 pgf 坐标作为结果。
低级 pgf 坐标指的是坐标(rel axis cs:0,0)
。这是轴区域的左下角(而不是轴的原点)。因此axis cs
坐标是轴中的绝对位置。如果将它们相加,您会得到意想不到的结果:
代码:
\documentclass[dvipsnames]{article}
%\usepackage[utf8]{inputenc}% need for outdated TeX distributions
\usepackage{pgfplots}% loads tikz and xcolor
\pgfplotsset{compat=newest}
\usetikzlibrary{babel,calc,backgrounds,quotes,angles,patterns,decorations.markings,intersections,arrows,arrows.meta}
\usepgfplotslibrary{fillbetween}
\tikzset{point/.style={circle,fill=black,inner sep=1pt},>=latex'}
\begin{document}
\begin{tikzpicture}
\begin{axis}[ axis lines = middle,
xmin = -1,
ymin = -5,
xmax = 10,
ymax = 14,
domain = -1:10,
xtick = {1,2,...,9},
ytick = \empty,
xlabel style={below right},
ylabel style={above left},
x tick label style={below},
samples = 100,
axis on top=true,
xlabel = {$x$},
ylabel = {$f$},
]
\addplot[very thick, domain=0:11] {5 + x};
\path
(1,6) coordinate(P) node[point,label=above:P]{}
(2,0) coordinate(Q) node[point,label=above left:Q]{}
(rel axis cs:0,0) node{x}
;
\draw[blue!50!black] (1,6) -- ($(1,6) + (2,0)$);
\end{axis}
\path (0,0) coordinate(O) node[point,label=below:O]{};% origin of the rel axis cs
\begin{scope}[->,red]
\draw (O)--(P);
\draw (O)--(Q);
\draw (Q)--+(P)node[point]{};
\end{scope}
\end{tikzpicture}
\end{document}
可以使用以下任一方法修复此问题
\draw[thick, dashed] (1,6) -- ($(1,6) + (axis direction cs:2,0)$);
或者
\draw[thick,dashed] (1,6) -- ($(1,6) + (2,0)-(0,0)$);
代码:
\documentclass[dvipsnames]{article}
%\usepackage[utf8]{inputenc}% need for outdated TeX distributions
\usepackage{pgfplots}% loads tikz and xcolor
\pgfplotsset{compat=newest}
\usetikzlibrary{babel,calc,backgrounds,quotes,angles,patterns,decorations.markings,intersections,arrows,arrows.meta}
\usepgfplotslibrary{fillbetween}
\tikzset{point/.style={circle,fill=black,inner sep=1pt},>=latex'}
\begin{document}
\begin{tikzpicture}
\begin{axis}[ axis lines = middle,
xmin = -1,
ymin = -5,
xmax = 10,
ymax = 14,
domain = -1:10,
xtick = {1,2,...,9},
ytick = \empty,
xlabel style={below right},
ylabel style={above left},
x tick label style={below},
samples = 100,
axis on top=true,
xlabel = {$x$},
ylabel = {$f$},
clip=false
]
\addplot[very thick, domain=0:11] {5 + x};
\draw[thick,blue!50!black] (1,6) -- ($(1,6) + (2,0)$);
\draw[thick,green!50!black] (1,6) -- ($(1,6) + (2,0)-(0,0)$);
\draw[thick,dashed] (1,6) -- ($(1,6) + (axis direction cs:2,0)$);
%
\path
(rel axis cs:0,0) coordinate(O) node[point,label=below:O]{}
(0,0) coordinate(A) node[point,label=above left:A]{}
(1,6) coordinate(P) node[point,label=above:P]{}
(2,0) coordinate(Q) node[point,label=above left:Q]{}
;
\begin{scope}[->,red]
\draw[thick,dotted,cyan] (A)--(O);
\draw (O)--(P);
\draw (O)--(Q);
\draw (Q)--+(P)node[point]{};
\draw[thick,cyan] (Q) ++(P)-- +($(O)-(A)$)node[point]{};
\end{scope}
\end{axis}
\end{tikzpicture}
\end{document}
答案2
为了更好地理解发生了什么,坐标 (axis cs: 2,0) 是距离 (rel axis cs: 0,0) 的距离。而不是 (axis cs: 0,0)。y 方向上额外的 5 来自 [ymin=-5]。
\documentclass[dvipsnames]{article}
\usepackage[utf8]{inputenc}
\usepackage{xcolor}
\usepackage{pgfplots,tikz}
\usetikzlibrary{babel,calc,backgrounds,quotes,angles,patterns,decorations.markings,intersections,arrows,arrows.meta}
\pgfplotsset{compat=newest}
\usepgflibrary{arrows}
\usepgfplotslibrary{fillbetween}
\begin{document}
\begin{tikzpicture}
\begin{axis}[ axis lines = middle,
xmin = -1,
ymin = -5,
xmax = 10,
ymax = 14,
domain = -1:10,
xtick = {1,2,...,9},
ytick = \empty,
xlabel style={below right},
ylabel style={above left},
x tick label style={below},
samples = 100,
axis on top=true,
xlabel = {$x$},
ylabel = {$f$}
]
\addplot[very thick, domain=0:11] {5 + x};
\coordinate (A) at (1,6);% axis cs: is the default
\coordinate (B) at (2,0);
\coordinate (origin) at (0,0);
\end{axis}
\draw[thick, dashed] (A) -- ($(A) + (B) - (origin)$);
\end{tikzpicture}
\end{document}