右边公式怎么写？

Question

我尝试在 Latex 中写下以下公式

我的问题是右边的公式怎么写？如何保证公式环境中右边的文本段落一致？

我的代码是

$\mathbb{P}[\mbox{there exists a black path from ${0}\times [0,s]$ to $\pho s\mtis [0,s]$ in the rectangle $[0,\pho s]\times [0,s]$}]

Answer 1

我会选择tabular，但有一点变化：

\documentclass{article}
\usepackage{amsmath}

\begin{document}

\[
f_s(\rho)=\mathbf{P}\left[
  \begin{tabular}{@{\,}l@{\,}}
  there exists a black path from $\{0\}\times[0,s]$ to \\
  $\{\rho s\}\times[0,s]$ in the rectangle $[0,\rho s]\times[0,s]$
  \end{tabular}
\right]
\]

\end{document}

这似乎完全复制了您所展示的图片。

---

我的普通 TeX 版本将是

$$
f_s(\rho)={\bf P}\left[
  \,\vcenter{\ialign{#\hfil\cr
    there exists a black path from $\{0\}\times[0,s]$ to\cr
    $\{\rho s\}\times[0,s]$ in the rectangle $[0,\rho s]\times[0,s]$\cr
  }}\,
\right]
$$

可能需要一个宏来减轻重量：

\def\longsetdesc#1{\,\vcenter{\ialign{##\hfil\cr#1\crcr}}\,}

$$
f_s(\rho)={\bf P}\left[
  \longsetdesc{
    there exists a black path from $\{0\}\times[0,s]$ to\cr
    $\{\rho s\}\times[0,s]$ in the rectangle $[0,\rho s]\times[0,s]$
  }
\right]
$$
\bye

Answer 2

和tabular：

\documentclass{article}

\begin{document}
\[ 
f_s(P) = \mathbf {P} 
        \left[\begin{tabular}{l}
        there exists a black path from ${0}\times [0,s]$ to\\ 
        $\rho s\times [0,s]$ in the rectangle $0,\rho s]\times [0,s]$
              \end{tabular}\right]
\]

\end{document}

Answer 3

这是TeX 原语的\vcenter任务：\hbox

$$
  f_s(P) = {\bf P} \left[
  \vcenter{
    \hbox{there exists a black path from ${0}\times [0,s]$ to}
    \hbox{$\rho s\times [0,s]$ in the rectangle $[0,\rho s]\times [0,s]$}
  }\right]
$$

Answer 4

这是一个使用 的解决方案，\parbox不需要加载任何额外的包。（我确实\pho用\rho、\mtis和替换了。）\times{0}\{0\}

\documentclass{article}
\newlength\mylen
\settowidth\mylen{there exists a black path from $\{0\}\times [0,s]$ to} % measure width
\begin{document}
\[
\mathbf{P}\left[\,
\parbox{\mylen}{\raggedright there exists a black path from $\{0\}\times [0,s]$ to 
  $\{\rho s\}\times [0,s]$ in the rectangle $[0,\rho s]\times [0,s]$}
\,\right]
\]
\end{document}