我是 LaTeX 新手。我使用表格生成器网站制作了一个回归表。现在到了最后阶段,我想让表格和页面一样宽,但我不知道该怎么做。有人能建议一个解决方案来解决这个问题吗?
代码表及环境如下:
\documentclass{article}
\usepackage[utf8]{inputenc}
\usepackage{graphicx}
\usepackage{caption}
\usepackage{fancyhdr}
\usepackage{booktabs}
\usepackage{array}
\usepackage{graphicx}
\usepackage{booktabs}
\usepackage{lscape}
\usepackage{threeparttable}
\begin{document}
\clearpage
\renewcommand\arraystretch{1.4}
\thispagestyle{empty}
\begin{landscape}
\begin{table}[]
\small
\centering
\caption{Lorem ipsum dolor sit amet, consectetur adipiscing elit. Sed ornare diam erat, quis accumsan massa congue bibendum. Praesent et ex et nisl mattis pulvinar at non lectus.}
\label{tab:my-tab5}
\resizebox{1\textwidth}{!}{%
\begin{tabular}{@{}lcccccccc@{}}
\cmidrule(l){2-9}
\textbf{} &
\multicolumn{2}{c}{\textbf{Model 1}} &
\multicolumn{2}{c}{\textbf{Model 2}} &
\multicolumn{2}{c}{\textbf{Model 3}} &
\multicolumn{2}{c}{\textbf{Model 4}} \\ \midrule
Occupational class &
\textbf{Coefficient\textsuperscript{a}} &
\textbf{95\% CI\textsuperscript{b}} &
\textbf{Coefficient\textsuperscript{a}} &
\multicolumn{1}{l}{\textbf{95\% CI}} &
\textbf{Coefficient} &
\textbf{95\% CI\textsuperscript{b}} &
\textbf{Coefficient\textsuperscript{a}} &
\textbf{95\% CI\textsuperscript{b}} \\
\textbf{Father's occupational class at age 5} &
&
&
&
\multicolumn{1}{l}{} &
&
&
&
\\
\hspace{2mm}{Female} (N=2,980) &
\multicolumn{1}{l}{} &
\multicolumn{1}{l}{} &
&
\multicolumn{1}{l}{} &
\multicolumn{1}{l}{} &
\multicolumn{1}{l}{} &
\multicolumn{1}{l}{} &
\multicolumn{1}{l}{} \\
\textit{\begin{tabular}[c]{@{}l@{}} \hspace{5mm}{I Professional/II Intermediate}\\ \hspace{5mm}{III Skilled (non-manual or manual)}\\ \hspace{5mm}{IV Partly skilled/V Unskilled}\end{tabular}} &
\begin{tabular}[c]{@{}c@{}}0.00 (ref)\\ 0.004\\ 0.00\end{tabular} &
\begin{tabular}[c]{@{}c@{}}—\\ 0.009, 0.00\\ 0.00, 0.00\end{tabular} &
\multicolumn{1}{c}{\begin{tabular}[c]{@{}c@{}}0.00 (ref)\\ 0.00\\ 0.00\end{tabular}} &
\begin{tabular}[c]{@{}c@{}}—\\ 0.00, 0.00\\ 0.00, 0.00\end{tabular} &
\begin{tabular}[c]{@{}c@{}}0.00 (ref)\\ 0.00\\ 0.00\end{tabular} &
\begin{tabular}[c]{@{}c@{}}—\\ 0.00, 0.00\\ 0.00, 0.00\end{tabular} &
\begin{tabular}[c]{@{}c@{}}0.00 (ref)\\ 0.00\\ 0.00\end{tabular} &
\begin{tabular}[c]{@{}c@{}}—\\ 0.00, 0.00\\ 0.00, 0.00\end{tabular} \\
p-values (overall\textsuperscript{c}; test for trend\textsuperscript{d}) &
&
\textless{}0.001; \textless{}0.001 &
\multicolumn{1}{c}{} &
0.025; 0.025 &
&
0.003; 0.004 &
&
0.002; 0.002 \\
\hspace{2mm}{Female} (N=2,925) &
\multicolumn{1}{l}{} &
\multicolumn{1}{l}{} &
&
\multicolumn{1}{l}{} &
\multicolumn{1}{l}{} &
\multicolumn{1}{l}{} &
\multicolumn{1}{l}{} &
\multicolumn{1}{l}{} \\
\begin{tabular}[c]{@{}l@{}}\hspace{5mm}{I Professional/II Intermediate}\\ \hspace{5mm}{III Skilled (non-manual or manual)}\\ \hspace{5mm}{IV Partly skilled/V Unskilled}\end{tabular} &
\begin{tabular}[c]{@{}c@{}}0.00 (ref)\\ -0.00\\ 0.00\end{tabular} &
\begin{tabular}[c]{@{}c@{}}—\\ 0.00, 0.00\\ 0.00, 0.00\end{tabular} &
\multicolumn{1}{c}{\begin{tabular}[c]{@{}c@{}}0.00 (ref)\\ 0.36\\ 1.01\end{tabular}} &
\begin{tabular}[c]{@{}c@{}}—\\ 0.00, 0.00\\ 0.00, 0.00\end{tabular} &
\begin{tabular}[c]{@{}c@{}}0.00 (ref)\\ 0.00\\ 0.00\end{tabular} &
\begin{tabular}[c]{@{}c@{}}—\\ 0.00, 0.00\\ 0.00, 0.00\end{tabular} &
\begin{tabular}[c]{@{}c@{}}0.00 (ref)\\ 0.00\\ 0.00\end{tabular} &
\begin{tabular}[c]{@{}c@{}}—\\ 0.00, 0.00\\ 0.00, 0.00\end{tabular} \\
p-values (overall\textsuperscript{c}; test for trend\textsuperscript{d}) &
\multicolumn{1}{l}{} &
\multicolumn{1}{l}{0.743; 0.568} &
&
0.123; 0.045 &
\multicolumn{1}{l}{} &
\multicolumn{1}{l}{0.411; \textless{}0.001} &
\multicolumn{1}{l}{} &
\multicolumn{1}{l}{0.261; 0.408} \\
\textbf{Mother's highest qualification at age 5} &
&
&
\multicolumn{1}{c}{} &
&
&
&
&
\\
\hspace{2mm}{Female} (N=2,485) &
\multicolumn{1}{l}{} &
\multicolumn{1}{l}{} &
&
\multicolumn{1}{l}{} &
\multicolumn{1}{l}{} &
\multicolumn{1}{l}{} &
\multicolumn{1}{l}{} &
\multicolumn{1}{l}{} \\
\textit{\begin{tabular}[c]{@{}l@{}}\hspace{5mm}{Vocational/degree and higher}\\ \hspace{5mm}{A-level/equivalent}\\ \hspace{2mm}{Vocational/O-level/equivalent}\\ \hspace{5mm}{No qualification}\end{tabular}} &
\begin{tabular}[c]{@{}c@{}}0.00 (ref)\\ 0.00\\ 0.00\\ 0.00\end{tabular} &
\begin{tabular}[c]{@{}c@{}}—\\ 0.00, 0.00\\ 0.00, 0.00\\ 0.00, 0.00\end{tabular} &
\multicolumn{1}{c}{\begin{tabular}[c]{@{}c@{}}0.00 (ref)\\ 0.00\\ 0.00\\ 0.00\end{tabular}} &
\begin{tabular}[c]{@{}c@{}}—\\ 0.00, 0.00\\ 0.00, 0.00\\ 0.00, 0.00\end{tabular} &
\begin{tabular}[c]{@{}c@{}}0.00 (ref)\\ 0.00\\ 0.00\\ 0.00\end{tabular} &
\begin{tabular}[c]{@{}c@{}}—\\ 0.00, 0.00\\ 0.00, 0.00\\ 0.00, 0.00\end{tabular} &
\begin{tabular}[c]{@{}c@{}}0.00 (ref)\\ 0.00\\ 0.00\\ 0.00\end{tabular} &
\begin{tabular}[c]{@{}c@{}}—\\ 0.00, 0.00\\ 0.00, 0.00\\ 0.00, 0.00\end{tabular} \\
p-values (overall\textsuperscript{c}; test for trend\textsuperscript{d}) &
&
\textless{}0.001; \textless{}0.001 &
\multicolumn{1}{c}{} &
\textless{}0.001; 0.008 &
&
\textless{}0.001; 0.002 &
&
0.005; 0.001 \\
\hspace{2mm}{Female} (N=2,412) &
\multicolumn{1}{l}{} &
\multicolumn{1}{l}{} &
&
\multicolumn{1}{l}{} &
\multicolumn{1}{l}{} &
\multicolumn{1}{l}{} &
\multicolumn{1}{l}{} &
\multicolumn{1}{l}{} \\
\begin{tabular}[c]{@{}l@{}}\hspace{2mm}{Vocational/degree and higher}\\ \hspace{5mm}{A-level/equivalent}\\ Vocational/O-level/equivalent\\ No qualification\end{tabular} &
\begin{tabular}[c]{@{}c@{}}0.00 (ref)\\ 0.00\\ 0.00\\ 0.00\end{tabular} &
\begin{tabular}[c]{@{}c@{}}—\\ 0.00, 0.00\\ 0.00, 0.00\\ 0.00, 0.00\end{tabular} &
\multicolumn{1}{c}{\begin{tabular}[c]{@{}c@{}}0.00 (ref)\\ 0.00\\ 0.00\\ 0.00\end{tabular}} &
\begin{tabular}[c]{@{}c@{}}—\\ 0.00, 0.00\\ 0.00, 0.00\\ 0.00, 0.00\end{tabular} &
\begin{tabular}[c]{@{}c@{}}0.00 (ref)\\ 0.00\\ 0.00\\ 0.00\end{tabular} &
\begin{tabular}[c]{@{}c@{}}—\\ 0.00, 0.00\\ 0.00, 0.00\\ 0.00, 1.46\end{tabular} &
\begin{tabular}[c]{@{}c@{}}0.00 (ref)\\ 0.00\\ 0.00\\ 0.00\end{tabular} &
\begin{tabular}[c]{@{}c@{}}—\\ 0.00, 0.00\\ 0.00, 0.00\\ 0.00, 0.00\end{tabular} \\
p-values (overall\textsuperscript{c}; test for trend\textsuperscript{d}) &
\multicolumn{1}{l}{} &
0.304; 0.064 &
&
072; 0.046 &
\multicolumn{1}{l}{} &
0.160; 0.305 &
\multicolumn{1}{l}{} &
0.078; - \\
\textbf{Father's highest qualification at age 5} &
\multicolumn{1}{l}{} &
\multicolumn{1}{l}{} &
&
\multicolumn{1}{l}{} &
\multicolumn{1}{l}{} &
\multicolumn{1}{l}{} &
\multicolumn{1}{l}{} &
\multicolumn{1}{l}{} \\
\hspace{2mm}{Female} (N=2,343) &
\multicolumn{1}{l}{} &
\multicolumn{1}{l}{} &
&
\multicolumn{1}{l}{} &
\multicolumn{1}{l}{} &
\multicolumn{1}{l}{} &
\multicolumn{1}{l}{} &
\multicolumn{1}{l}{} \\
\textit{\begin{tabular}[c]{@{}l@{}}\hspace{5mm}{Vocational/degree and higher}\\ \hspace{5mm}{A-level/equivalent}\\ \hspace{5mm}{Vocational/O-level/equivalent}\\ \hspace{5mm}{No qualification}\end{tabular}} &
\begin{tabular}[c]{@{}c@{}}0.00 (ref)\\ 0.00\\ 0.00\\ 0.00\end{tabular} &
\begin{tabular}[c]{@{}c@{}}—\\ 0.00, 0.00\\ 0.00, 0.00\\ 0.00, 0.00\end{tabular} &
\multicolumn{1}{c}{\begin{tabular}[c]{@{}c@{}}0.00 (ref)\\0.00\\ 0.00\\ 0.00\end{tabular}} &
\begin{tabular}[c]{@{}c@{}}—\\ -0.00, 0.00\\ 0.00, 0.00\\ 0.00, 0.00\end{tabular} &
\begin{tabular}[c]{@{}c@{}}0.00 (ref)\\ 0.00\\ 0.00\\ -0.00\end{tabular} &
\begin{tabular}[c]{@{}c@{}}—\\ 0.00, 0.00\\ 0.00, 0.00\\ 0.00, 0.00\end{tabular} &
\begin{tabular}[c]{@{}c@{}}0.00 (ref)\\ 0.00\\ 0.00\\ 0.00\end{tabular} &
\begin{tabular}[c]{@{}c@{}}—\\ 0.00, 0.00\\ 0.00, 0.00\\ 0.00, 0.00\end{tabular} \\
p-values (overall\textsuperscript{c}; test for trend\textsuperscript{d}) &
&
0.304; 0.064 &
\multicolumn{1}{c}{} &
0.899; 0.698 &
&
0.715; 0.368 &
&
0.642; 0.287 \\
\hspace{2mm}{Female} (N=2,286) &
\multicolumn{1}{l}{} &
\multicolumn{1}{l}{} &
&
\multicolumn{1}{l}{} &
\multicolumn{1}{l}{} &
\multicolumn{1}{l}{} &
\multicolumn{1}{l}{} &
\multicolumn{1}{l}{} \\
\textit{\begin{tabular}[c]{@{}l@{}}\hspace{5mm}{Vocational/degree and higher}\\ \hspace{5mm}{A-level/equivalent}\\ \hspace{5mm}{Vocational/O-level/equivalent}\\ \hspace{5mm}{No qualification}\end{tabular}} &
\begin{tabular}[c]{@{}c@{}}0.00 (ref)\\ 0.00\\ 0.002\\ 0.00\end{tabular} &
\begin{tabular}[c]{@{}c@{}}—\\ 0.00, 0.002\\ 0.00, 0.00\\ 0.00, 0.00\end{tabular} &
\multicolumn{1}{c}{\begin{tabular}[c]{@{}c@{}}0.00 (ref)\\ 0.00\\ 0.00\\ 0.00\end{tabular}} &
\begin{tabular}[c]{@{}c@{}}—\\ 0.00, 0.00\\ 0.00, 0.00\\ 0.00, 0.00\end{tabular} &
\begin{tabular}[c]{@{}c@{}}0.00 (ref)\\ 0.00\\ 0.00\\ 0.00\end{tabular} &
\begin{tabular}[c]{@{}c@{}}—\\ 0.00, 0.00\\ 0.00, 0.00\\ 0.00, 0.00\end{tabular} &
\begin{tabular}[c]{@{}c@{}}0.00 (ref)\\ 0.08\\ 0.00\\ -0.08\end{tabular} &
\begin{tabular}[c]{@{}c@{}}—\\ 0.00, 0.00\\ 0.00, 0.80\\ 0.00, 0.00\end{tabular} \\
p-values (overall\textsuperscript{c}; test for trend\textsuperscript{d}) &
\multicolumn{1}{l}{} &
0.123; 0.020 &
&
0.003; \textless{}0.001 &
\multicolumn{1}{l}{} &
0.056; 0.009 &
\multicolumn{1}{l}{} &
0.986; 0.866 \\ \bottomrule
\end{tabular}%
}
\begin{tablenotes}
\footnotesize
\item
\textsuperscript{a} Duis leo ante, malesuada sit amet magna at, dictum feugiat dui; \textsuperscript{b} CI: Confidence Interval; \textsuperscript{c} P-value: p-value from a likelihood ratio test of the overall association; \textsuperscript{d} P-trend: p-value not presented for relationship where there was significant deviation from linearity
\end{tablenotes}
\end{table}
\end{landscape}
\end{document}
表格目前如下所示:
答案1
如果使用\scriptsize
(而不仅仅是\small
),以及 10pt 的基本字体大小,如果愿意减少的值\arraystretch
(1.4 似乎太多了),并且使用相当窄的边距(例如,2.5cm),那么只是表格(包括标题和tablenotes
部分)可以放入文本块内。
我忍不住要补充一点:你用来生成表格的代码质量真的很差。你是怎么想出这段代码的?我尝试在下面的答案中提高代码质量,但仍然不是很好。
\documentclass{article}
\usepackage[a4paper,margin=2.5cm]{geometry} % set page parameters suitably
\usepackage[utf8]{inputenc}
\usepackage[T1]{fontenc}
\usepackage{graphicx}
\usepackage{caption}
\usepackage{fancyhdr}
\usepackage{booktabs}
\usepackage{array}
\usepackage{booktabs}
\usepackage{rotating} % for 'sidewaytable' env.
\usepackage[para]{threeparttable}
\newcommand\mytabC[1]{\begin{tabular}{@{}c@{}} #1 \end{tabular}}
\newcommand\mytabL[1]{\hspace{5mm}\begin{tabular}{@{}l@{}} #1 \end{tabular}}
\begin{document}
\clearpage
\renewcommand\arraystretch{1.2} % 1.4 is excessive
\begin{sidewaystable}
\setlength\tabcolsep{0pt}
\scriptsize
\begin{threeparttable}
\caption{Lorem ipsum dolor sit amet, consectetur adipiscing elit. Sed ornare diam erat, quis accumsan massa congue bibendum. }
\label{tab:my-tab5}
\begin{tabular*}{\textwidth}{@{\extracolsep{\fill}} l *{8}{c} }
\toprule
&
\multicolumn{2}{c}{Model 1} &
\multicolumn{2}{c}{Model 2} &
\multicolumn{2}{c}{Model 3} &
\multicolumn{2}{c}{Model 4} \\
\cmidrule{2-3} \cmidrule{4-5} \cmidrule{6-7} \cmidrule{8-9}
Occupational class &
Coefficient\tnote{a} & 95\% CI\tnote{b} &
Coefficient\tnote{a} & 95\% CI &
Coefficient & 95\% CI\tnote{b} &
Coefficient\tnote{a} & 95\% CI\tnote{b} \\
\midrule
\multicolumn{5}{@{}l}{\textbf{Father's occupational class at age 5}} & \\
Female ($N=2{,}980$) & \\
\mytabL{I Professional/II Intermediate\\ III Skilled (non-manual\ or manual)\\ IV Partly skilled/V Unskilled} &
\mytabC{0.00 (ref)\\ 0.004\\ 0.00} &
\mytabC{—\\ 0.009, 0.00\\ 0.00, 0.00} &
\mytabC{0.00 (ref)\\ 0.00\\ 0.00} &
\mytabC{—\\ 0.00, 0.00\\ 0.00, 0.00} &
\mytabC{0.00 (ref)\\ 0.00\\ 0.00} &
\mytabC{—\\ 0.00, 0.00\\ 0.00, 0.00} &
\mytabC{0.00 (ref)\\ 0.00\\ 0.00} &
\mytabC{—\\ 0.00, 0.00\\ 0.00, 0.00} \\
\hspace{2.5mm}$p$-values (overall\tnote{c}; test for trend\tnote{d}) &
& <0.001; <0.001 & & 0.025; 0.025 & & 0.003; 0.004 & & 0.002; 0.002 \\
\addlinespace
Female ($N=2{,}925$) & \\
\mytabL{I Professional/II Intermediate\\ III Skilled (non-manual\ or manual)\\ IV Partly skilled/V Unskilled} &
\mytabC{0.00 (ref)\\ -0.00\\ 0.00} &
\mytabC{—\\ 0.00, 0.00\\ 0.00, 0.00} &
\multicolumn{1}{c}{\mytabC{0.00 (ref)\\ 0.36\\ 1.01}} &
\mytabC{—\\ 0.00, 0.00\\ 0.00, 0.00} &
\mytabC{0.00 (ref)\\ 0.00\\ 0.00} &
\mytabC{—\\ 0.00, 0.00\\ 0.00, 0.00} &
\mytabC{0.00 (ref)\\ 0.00\\ 0.00} &
\mytabC{—\\ 0.00, 0.00\\ 0.00, 0.00} \\
\hspace{2.5mm}$p$-values (overall\tnote{c}; test for trend\tnote{d}) &
& 0.743; 0.568 & & 0.123; 0.045 & & 0.411; <0.001 & & 0.261; 0.408 \\
\addlinespace
\multicolumn{5}{@{}l}{\textbf{Mother's highest qualification at age 5}} & \\
Female ($N=2{,}485$) & \\
\mytabL{Vocational/degree and higher\\ A-level/equiv.\\ \hspace{2mm}Vocational/O-level/equiv.\\ No qualification} &
\mytabC{0.00 (ref)\\ 0.00\\ 0.00\\ 0.00} &
\mytabC{—\\ 0.00, 0.00\\ 0.00, 0.00\\ 0.00, 0.00} &
\multicolumn{1}{c}{\mytabC{0.00 (ref)\\ 0.00\\ 0.00\\ 0.00}} &
\mytabC{—\\ 0.00, 0.00\\ 0.00, 0.00\\ 0.00, 0.00} &
\mytabC{0.00 (ref)\\ 0.00\\ 0.00\\ 0.00} &
\mytabC{—\\ 0.00, 0.00\\ 0.00, 0.00\\ 0.00, 0.00} &
\mytabC{0.00 (ref)\\ 0.00\\ 0.00\\ 0.00} &
\mytabC{—\\ 0.00, 0.00\\ 0.00, 0.00\\ 0.00, 0.00} \\
\hspace{2.5mm}$p$-values (overall\tnote{c}; test for trend\tnote{d}) &
& <0.001; <0.001 & & <0.001; 0.008 & & <0.001; 0.002 & & 0.005; 0.001 \\
\addlinespace
Female ($N=2{,}412$) & \\
\mytabL{Vocational/degree and higher\\
A-level/equiv.\\
Vocational/O-level/equiv.\\
No qualification} &
\mytabC{0.00 (ref)\\ 0.00\\ 0.00\\ 0.00} &
\mytabC{—\\ 0.00, 0.00\\ 0.00, 0.00\\ 0.00, 0.00} &
\multicolumn{1}{c}{\mytabC{0.00 (ref)\\ 0.00\\ 0.00\\ 0.00}} &
\mytabC{—\\ 0.00, 0.00\\ 0.00, 0.00\\ 0.00, 0.00} &
\mytabC{0.00 (ref)\\ 0.00\\ 0.00\\ 0.00} &
\mytabC{—\\ 0.00, 0.00\\ 0.00, 0.00\\ 0.00, 1.46} &
\mytabC{0.00 (ref)\\ 0.00\\ 0.00\\ 0.00} &
\mytabC{—\\ 0.00, 0.00\\ 0.00, 0.00\\ 0.00, 0.00} \\
\hspace{2.5mm}$p$-values (overall\tnote{c}; test for trend\tnote{d}) &
& 0.304; 0.064 & & 072; 0.046 & & 0.160; 0.305 & & 0.078; — \\
\addlinespace
\multicolumn{5}{@{}l}{\textbf{Father's highest qualification at age 5}} \\
Female ($N=2{,}343$) & \\
\mytabL{Vocational/degree and higher\\
A-level/equiv.\\
Vocational/O-level/equiv.\\
No qualification} &
\mytabC{0.00 (ref)\\ 0.00\\ 0.00\\ 0.00} &
\mytabC{—\\ 0.00, 0.00\\ 0.00, 0.00\\ 0.00, 0.00} &
\mytabC{0.00 (ref)\\0.00\\ 0.00\\ 0.00} &
\mytabC{—\\ -0.00, 0.00\\ 0.00, 0.00\\ 0.00, 0.00} &
\mytabC{0.00 (ref)\\ 0.00\\ 0.00\\ -0.00} &
\mytabC{—\\ 0.00, 0.00\\ 0.00, 0.00\\ 0.00, 0.00} &
\mytabC{0.00 (ref)\\ 0.00\\ 0.00\\ 0.00} &
\mytabC{—\\ 0.00, 0.00\\ 0.00, 0.00\\ 0.00, 0.00} \\
\hspace{2.5mm}$p$-values (overall\tnote{c}; test for trend\tnote{d}) &
& 0.304; 0.064 & & 0.899; 0.698 & & 0.715; 0.368 & & 0.642; 0.287 \\
\addlinespace
Female ($N=2{,}286$) & \\
\mytabL{Vocational/degree and higher\\
A-level/equiv.\\
Vocational/O-level/equiv.\\
No qualification} &
\mytabC{0.00 (ref)\\ 0.00\\ 0.002\\ 0.00} &
\mytabC{—\\ 0.00, 0.002\\ 0.00, 0.00\\ 0.00, 0.00} &
\mytabC{0.00 (ref)\\ 0.00\\ 0.00\\ 0.00} &
\mytabC{—\\ 0.00, 0.00\\ 0.00, 0.00\\ 0.00, 0.00} &
\mytabC{0.00 (ref)\\ 0.00\\ 0.00\\ 0.00} &
\mytabC{—\\ 0.00, 0.00\\ 0.00, 0.00\\ 0.00, 0.00} &
\mytabC{0.00 (ref)\\ 0.08\\ 0.00\\ -0.08} &
\mytabC{—\\ 0.00, 0.00\\ 0.00, 0.80\\ 0.00, 0.00} \\
\hspace{2.5mm}$p$-values (overall\tnote{c}; test for trend\tnote{d}) &
& 0.123; 0.020 & & 0.003; <0.001 & & 0.056; 0.009 & & 0.986; 0.866 \\
\bottomrule
\end{tabular*}
\smallskip
\begin{tablenotes}
\item[a] Duis leo ante, malesuada sit amet magna at, dictum feugiat dui;
\item[b] CI: Confidence Interval;
\item[c] P-value: p-value from a likelihood ratio test of the overall association;
\item[d] P-trend: p-value not presented for relationship where there was significant deviation from linearity
\end{tablenotes}
\end{threeparttable}
\end{sidewaystable}
\end{document}
答案2
起点:
\documentclass{article}
\usepackage{caption}
\usepackage{booktabs}
\usepackage{pdflscape}
\usepackage{threeparttablex}
\usepackage{xltabular}
\begin{document}
\clearpage
\thispagestyle{empty}
\begin{landscape}
\begin{ThreePartTable}
\setlength{\tabcolsep}{3pt}
\small
\begin{TableNotes}[para]
\footnotesize
\item[a] Duis leo ante, malesuada sit amet magna at, dictum feugiat dui;
\item[b] CI: Confidence Interval;
\item[c] P-value: p-value from a likelihood ratio test of the overall association;
\item[d] P-trend: p-value not presented for relationship where there was significant deviation from linearity
\end{TableNotes}
\begin{xltabular}{\linewidth}{@{\;\;}>{\raggedright\arraybackslash}Xcccccccc@{}}
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\label{tab:my-tab5}\\
\toprule
&
\multicolumn{2}{c}{\textbf{Model 1}} &
\multicolumn{2}{c}{\textbf{Model 2}} &
\multicolumn{2}{c}{\textbf{Model 3}} &
\multicolumn{2}{c}{\textbf{Model 4}} \\
\cmidrule(r){2-3} \cmidrule(lr){4-5} \cmidrule(lr){6-7} \cmidrule(l){8-9}
Occupational class &
\textbf{Coeff.\tnote{a}} & \textbf{95\% CI\tnote{b}} &
\textbf{Coeff.\tnote{a}} & \textbf{95\% CI} &
\textbf{Coeff.} & \textbf{95\% CI\tnote{b}} &
\textbf{Coeff.\tnote{a}} & \textbf{95\% CI\tnote{b}} \\
\midrule
\endfirsthead
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\toprule
&
\multicolumn{2}{c}{\textbf{Model 1}} &
\multicolumn{2}{c}{\textbf{Model 2}} &
\multicolumn{2}{c}{\textbf{Model 3}} &
\multicolumn{2}{c}{\textbf{Model 4}} \\
\cmidrule(r){2-3} \cmidrule(lr){4-5} \cmidrule(lr){6-7} \cmidrule(l){8-9}
Occupational class &
\textbf{Coeff.\tnote{a}} & \textbf{95\% CI\tnote{b}} &
\textbf{Coeff.\tnote{a}} & \textbf{95\% CI} &
\textbf{Coeff.} & \textbf{95\% CI\tnote{b}} &
\textbf{Coeff.\tnote{a}} & \textbf{95\% CI\tnote{b}} \\
\midrule
\endhead
\bottomrule
\insertTableNotes
\endfoot
\multicolumn{9}{@{}l}{\textbf{Father's occupational class at age 5}} \\* \addlinespace
\textit{Female (N=2,980)} \\*
I Professional/II Intermediate & 0.00 (ref) & — & 0.00 (ref) & — & 0.00 (ref) & — & 0.00 (ref) & — \\
III Skilled (non-manual or manual) & 0.004 & 0.009, 0.00 & 0.00 & 0.00, 0.00 & 0.00 & 0.00, 0.00 & 0.00 & 0.00, 0.00 \\
IV Partly skilled/V Unskilled & 0.00 & 0.009, 0.00 & 0.00 & 0.00, 0.00 & 0.00 & 0.00, 0.00 & 0.00 & 0.00, 0.00 \\
p-values (overall\textsuperscript{c}; test for trend\textsuperscript{d})
& & \textless{}0.001; \textless{}0.001
& & 0.025; 0.025
& & 0.003; 0.004
& & 0.002; 0.002 \\ \addlinespace
\textit{Female (N=2,925)}\\*
I Professional/II Intermediate & & & & & & & & \\
III Skilled (non-manual or manual) & & & & & & & & \\
IV Partly skilled/V Unskilled & & & & & & & & \\
p-values (overall\textsuperscript{c}; test for trend\textsuperscript{d})
& & & & & & & & \\
\midrule
\multicolumn{9}{@{}l}{\textbf{Mother's highest qualification at age 5}}\\* \addlinespace
\textit{Female (N=2,485)}\\*
Vocational/degree and higher \\
A-level/equivalent \\
Vocational/O-level/equivalent\\
No qualification\\
p-values (overall\textsuperscript{c}; test for trend\textsuperscript{d}) \\ \addlinespace
\textit{Female (N=2,412)}\\*
Vocational/degree and higher \\
A-level/equivalent \\
Vocational/O-level/equivalent\\
No qualification\\
p-values (overall\textsuperscript{c}; test for trend\textsuperscript{d}) \\
\midrule
\multicolumn{9}{@{}l}{\textbf{Mother's highest qualification at age 5}}\\* \addlinespace
\textit{Female (N=2,343)}\\*
Vocational/degree and higher \\
A-level/equivalent \\
Vocational/O-level/equivalent\\
No qualification\\
p-values (overall\textsuperscript{c}; test for trend\textsuperscript{d}) \\ \addlinespace
\textit{Female (N=2,286)}\\*
Vocational/degree and higher \\
A-level/equivalent \\
Vocational/O-level/equivalent\\
No qualification\\
p-values (overall\textsuperscript{c}; test for trend\textsuperscript{d}) \\
\end{xltabular}%
\end{ThreePartTable}
\end{landscape}
\end{document}