列宽不相等

Question

\documentclass{article}

\begin{document}
    \begin{table}[h!]
        \centering
        \caption{Bobot kriteria}
        \label{tabel6}
        \begin{tabular}{|c|c|c|c|c|c|}
            \hline
            Kriteria&\multicolumn{4}{c|}{Pembuat keputusan ($D_1 - D_4$)}&Nilai rata-rata\\
            \hline
            $C_1$&AI&AI&AI&AI&$([0.8, 0.9], [0, 0.1])$\\
            \hline
            $C_2$&VI&VI&VI&I&$([0.659,0.762], [0.132,0.238])$\\
            \hline
        \end{tabular}
    \end{table}
\end{document}

为什么第 5 列的宽度与第 2、3、4 列的宽度不一样？如何修复？

Answer 1

如果\multicolumn对象的宽度大于跨越列的总自然宽度，则多余的空间将进入最后一列跨越列。

如果无法将宽\multicolumn条目拆分到多行，则可以测量它并将列宽设置为该宽度的四分之一。

\documentclass{article}
\usepackage{array}

\newlength{\spannedlength}
\AtBeginEnvironment{table}{%
  \setlength{\belowcaptionskip}{\abovecaptionskip}%
  \setlength{\abovecaptionskip}{0pt}%
}

\begin{document}

\begin{table}[h!]
\centering

\caption{Bobot kriteria}
\label{tabel6}

\settowidth{\spannedlength}{Pembuat keputusan ($D_1$ -- $D_4$}
% this will span four columns, six \tabcolsep spaces, but
% we need to take care of four \arrayrulewidth wide rules
\setlength{\spannedlength}{\dimexpr(\spannedlength-6\tabcolsep+4\arrayrulewidth)/4}

\begin{tabular}{|c|*{4}{w{c}{\spannedlength}|}c|}
\hline
Kriteria & \multicolumn{4}{c|}{Pembuat keputusan ($D_1$ -- $D_4$)} & Nilai rata-rata\\
\hline
$C_1$ & AI & AI & AI & AI & $([0.8, 0.9], [0, 0.1])$\\
\hline
$C_2$ & VI & VI & VI & I  & $([0.659,0.762], [0.132,0.238])$\\
\hline
\end{tabular}

\end{table}

\end{document}

我已经改成了$D_1-D_2$，$D_1$ -- $D_2$因为它看起来不像减法。我还建议如何在标题和表格之间获得适当的距离。

booktabs有和没有垂直线的表格的不同实现。

\documentclass{article}
\usepackage{array,booktabs}

\newlength{\spannedlength}
\AtBeginEnvironment{table}{%
  \setlength{\belowcaptionskip}{\abovecaptionskip}%
  \setlength{\abovecaptionskip}{0pt}%
}

\begin{document}

\begin{table}[h!]
\centering

\caption{Bobot kriteria}
\label{tabel6}

\settowidth{\spannedlength}{Pembuat keputusan ($D_1$ -- $D_4$}
% this will span four columns and six \tabcolsep spaces
\setlength{\spannedlength}{\dimexpr(\spannedlength-6\tabcolsep)/4}

\begin{tabular}{@{} c *{4}{w{c}{\spannedlength}} c @{}}
\toprule
Kriteria & \multicolumn{4}{c}{Pembuat keputusan ($D_1$ -- $D_4$)} & Nilai rata-rata\\
\midrule
$C_1$ & AI & AI & AI & AI & $([0.8, 0.9], [0, 0.1])$\\
$C_2$ & VI & VI & VI & I  & $([0.659,0.762], [0.132,0.238])$\\
\bottomrule
\end{tabular}

\end{table}

\end{document}

Answer 2

我建议您将其放在($D_1 - D_4$)单独的一行上，正下方Pembuat keputusan。

\documentclass{article}
\usepackage{array}
\begin{document}
    \begin{table}[h!]
    \setlength\extrarowheight{2pt}
    \addtolength\tabcolsep{2pt}
        \centering
        \caption{Bobot kriteria\strut}
        \label{tabel6}
        \begin{tabular}{ | *{6}{c|} }
            \hline
            Kriteria & \multicolumn{4}{c|}{Pembuat keputusan} & Nilai rata-rata \\
                     & \multicolumn{4}{c|}{($D_1 - D_4$)} &  \\
            \hline
            $C_1$ & AI & AI & AI & AI & ($[0.8, 0.9]$, $[0, 0.1]$)\\
            \hline
            $C_2$ & VI & VI & VI & I & ($[0.659,0.762]$, $[0.132,0.238]$)\\
            \hline
        \end{tabular}
    \end{table}
\end{document}

Answer 3

您可以手动固定第 2、3、4 和 5 列的宽度。

\documentclass{article}
\usepackage{caption}
\usepackage{array}

\begin{document}
\begin{table}[h!]
    \centering
    \caption{Bobot kriteria}
    \label{tabel6}
    \begin{tabular}{|c|*{4}{w{c}{1cm}|}c|}
        \hline
        Kriteria&\multicolumn{4}{c|}{Pembuat keputusan ($D_1 - D_4$)}&Nilai rata-rata\\
        \hline
        $C_1$&AI&AI&AI&AI&$([0.8, 0.9], [0, 0.1])$\\
        \hline
        $C_2$&VI&VI&VI&I&$([0.659,0.762], [0.132,0.238])$\\
        \hline
    \end{tabular}
\end{table}
\end{document}