文件名字符串比较

Question

如果“\filename{XYZ-2100011}”和“\include{XYZ-2100011}”输入文件名不匹配，则需要显示编译错误。

例如，如果 \filename{ABC-2100012} 和 \include{XYZ-2100011} 字符串文件名都不同，则在编译时需要显示错误消息。

请找到以下 MWE 文件：

\documentclass{article}

\makeatletter
\def\filename#1{\gdef\@filename{#1}}

\def\include#1{\relax
  \ifnum\@auxout=\@partaux
    \@latex@error{\string\include\space cannot be nested}\@eha
  \else \@include#1 \fi}

\makeatother

\filename{XYZ-2100011}

\begin{document}

\include{XYZ-2100011}

\end{document} 

Answer 1

关键是使用 来\ifx比较字符串值。因此，对于\include，设置#1到\@tmp宏中，然后\ifx\@filename\@tmp。

而且，显然，我不主张重新定义像这样的核心宏\include，所以更改名称。

如果目标是避免文件名匹配，那么这样做：

\documentclass{article}

\makeatletter
\def\filename#1{\gdef\@filename{#1}}

\def\myinclude#1{\relax
  \def\@tmp{#1}%
  \ifx\@filename\@tmp
    \@latex@error{\string Duplicate filename}\@eha
  \else
    \ifnum\@auxout=\@partaux
      \@latex@error{\string\include\space cannot be nested}\@eha
    \else \@include#1 \fi
  \fi}

\makeatother

\filename{XYZ-2100011}

\begin{document}

\myinclude{XYZ-2100011}

\end{document} 

如果目标是强制文件名匹配，那么这样做：

\documentclass{article}

\makeatletter
\def\filename#1{\gdef\@filename{#1}}

\def\myinclude#1{\relax
  \def\@tmp{#1}%
  \ifx\@filename\@tmp
    \ifnum\@auxout=\@partaux
      \@latex@error{\string\include\space cannot be nested}\@eha
    \else \@include#1 \fi
  \else
    \@latex@error{\string Filenames don't match}\@eha
  \fi}

\makeatother

\filename{XYZ-2100011}

\begin{document}

\myinclude{XYZ-210x0011}

\end{document}