但出于某种原因,\\
它不起作用。这是我得到的结果:
%
\begin{equation}
\begin{pmatrix}
H^{TE,inc}_{y1}(1-R^{TE})\\[6pt]
-H^{TE,inc}_{x1}(1-R^{TE})
\end{pmatrix}
=
\begin{pmatrix}
Y^{TE,in}_{xx} & Y^{TE,in}_{xy}\\[6pt]
Y^{TE,in}_{yx} & Y^{TE,in}_{yy}
\end{pmatrix}
%
\begin{pmatrix}
E^{TE,inc}_{x1}(1+R^{TE})\\[6pt]
E^{TE,inc}_{y1}(1+R^{TE})
\end{pmatrix}
\\[6pt]
\text{and} \\[6pt]
\begin{pmatrix}
H^{TM,inc}_{y1}(1-R^{TM})\\[6pt]
-H^{TM,inc}_{x1}(1-R^{TM})
\end{pmatrix}
=
\begin{pmatrix}
Y^{TM,in}_{xx} & Y^{TM,in}_{xy}\\[6pt]
Y^{TM,in}_{yx} & Y^{TM,in}_{yy}
\end{pmatrix}
%
\begin{pmatrix}
E^{TM,inc}_{x1}(1+R^{TM})\\[6pt]
E^{TM,inc}_{y1}(1+R^{TM})
\end{pmatrix} \\[6pt]
\label{eqch3_9}
\end{equation}
%
答案1
希望以下内容能满足您的要求:
\documentclass{book}
\usepackage{mathtools}
\begin{document}
\begin{align}
\begin{pmatrix}
H^{TE,inc}_{y1}(1-R^{TE})\\[6pt]
-H^{TE,inc}_{x1}(1-R^{TE})
\end{pmatrix}
=
\begin{pmatrix}
Y^{TE,in}_{xx} & Y^{TE,in}_{xy}\\[6pt]
Y^{TE,in}_{yx} & Y^{TE,in}_{yy}
\end{pmatrix}
%
\begin{pmatrix}
E^{TE,inc}_{x1}(1+R^{TE})\\[6pt]
E^{TE,inc}_{y1}(1+R^{TE})
\end{pmatrix} \nonumber\\
\intertext{and}
\begin{pmatrix}
H^{TM,inc}_{y1}(1-R^{TM})\\[6pt]
-H^{TM,inc}_{x1}(1-R^{TM})
\end{pmatrix}
=
\begin{pmatrix}
Y^{TM,in}_{xx} & Y^{TM,in}_{xy}\\[6pt]
Y^{TM,in}_{yx} & Y^{TM,in}_{yy}
\end{pmatrix}
%
\begin{pmatrix}
E^{TM,inc}_{x1}(1+R^{TM})\\[6pt]
E^{TM,inc}_{y1}(1+R^{TM})
\end{pmatrix}\label{eqch3_9}
\end{align}
\end{document}