我有以下代码:
\documentclass[twoside,leqno]{article}
\usepackage[fleqn]{mathtools}
\setlength{\mathindent}{14bp}
\begin{document}
\begin{equation}\label{14}
\left\{
\begin{aligned}
\begin{split}
T(E_1 \Fcap E_2) &= T(E_1) \Fcap T(E_2) \\
T(E_1 \Fcup E_2) &= T(E_1) \Fcup T(E_2)
\end{split}\\
\begin{split}
H(E_1 \Fcap E_2)&=\left[ T(E_1) \Fcap T(E_2) \right] \Fcup \left[-(E_1 \Fcap E_2)\right] \\
&=\left[ T(E_1) \Fcap T(E_2) \right] \Fcup \left[-(E_1) \Fcup T(-E_2)\right] \\
&=\left[ T(E_1) \Fcap T(E_2) \right] \Fcup T(-E_1) \Fcup T(-E_2)
\end{split}\\
\begin{split}
H(E_1 \Fcup E_2) &= T(E_1\Fcup E_2) \Fcup \left[T(-E_1\Fcup E_2) \right] \\
&= T(E_1\Fcup E_2) \Fcup \left[T(-E_1 \Fcap -E_2) \right] \\
&= T(E_1)\Fcup T(E_2) \Fcup \left[T(-E_1) \Fcap T(-E_2) \right]
\end{split}
\end{aligned}
\right.
\end{equation}
\end{document}
结果如下:
答案1
- 里面没有空行
equation
- 不
split
- 删除多余的(且有害的)
\left
和\right
。
我还添加了一些垂直空间,以便更好地区分方程组。
我提供了和的虚拟定义\Fcup
只是\Fcap
为了使代码可编译。
\documentclass[twoside,leqno]{article}
\usepackage[fleqn]{mathtools}
\setlength{\mathindent}{14bp}
\newcommand{\Fcap}{\cap}
\newcommand{\Fcup}{\cup}
\begin{document}
\begin{equation}\label{14}
\left\{
\begin{aligned}
T(E_1 \Fcap E_2) &= T(E_1) \Fcap T(E_2) \\[1ex]
T(E_1 \Fcup E_2) &= T(E_1) \Fcup T(E_2) \\[1ex]
H(E_1 \Fcap E_2) &=[ T(E_1) \Fcap T(E_2) ] \Fcup [-(E_1 \Fcap E_2)] \\
&=[ T(E_1) \Fcap T(E_2) ] \Fcup [-(E_1) \Fcup T(-E_2)] \\
&=[ T(E_1) \Fcap T(E_2) ] \Fcup T(-E_1) \Fcup T(-E_2) \\[1ex]
H(E_1 \Fcup E_2) &= T(E_1\Fcup E_2) \Fcup [T(-E_1\Fcup E_2) ] \\
&= T(E_1\Fcup E_2) \Fcup [T(-E_1 \Fcap -E_2) ] \\
&= T(E_1)\Fcup T(E_2) \Fcup [T(-E_1) \Fcap T(-E_2) ]
\end{aligned}
\right.
\end{equation}
\end{document}
根据评论,我猜您想要对\Fcup
和有更好的定义\Fcap
:
\documentclass[twoside,leqno]{article}
\usepackage[fleqn]{mathtools}
\setlength{\mathindent}{14bp}
\newcommand{\Fcap}{\mathbin{{}_\cap\kern-\scriptspace}}
\newcommand{\Fcup}{\mathbin{{}^\cup\kern-\scriptspace}}
\begin{document}
\begin{equation}\label{14}
\left\{
\begin{aligned}
T(E_1 \Fcap E_2) &= T(E_1) \Fcap T(E_2) \\[1ex]
T(E_1 \Fcup E_2) &= T(E_1) \Fcup T(E_2) \\[1ex]
H(E_1 \Fcap E_2) &=[ T(E_1) \Fcap T(E_2) ] \Fcup [-(E_1 \Fcap E_2)] \\
&=[ T(E_1) \Fcap T(E_2) ] \Fcup [-(E_1) \Fcup T(-E_2)] \\
&=[ T(E_1) \Fcap T(E_2) ] \Fcup T(-E_1) \Fcup T(-E_2) \\[1ex]
H(E_1 \Fcup E_2) &= T(E_1\Fcup E_2) \Fcup [T(-E_1\Fcup E_2) ] \\
&= T(E_1\Fcup E_2) \Fcup [T(-E_1 \Fcap -E_2) ] \\
&= T(E_1)\Fcup T(E_2) \Fcup [T(-E_1) \Fcap T(-E_2) ]
\end{aligned}
\right.
\end{equation}
\end{document}