我需要什么包来制作使用线条和旋转括号的部分家谱部分时间线的图表？

Question

因此，我试图复制某个图表，该图表看起来是公司部分谱系和时间线，使用表示下降的线条和表示合并的旋转括号。

以下是我想复制的内容：

我不知道如何开始。我一直在寻找各种 tikz 或其他图表的教程，但我还没有找到可以帮助我制作类似于此图表的东西。

也许更有经验的人可以给我指明正确的方向？

请注意，我不是要求别人为我做这个，而是问我自己如何才能做到这一点。

Answer 1

我在其他地方得到了答案。这是解决方案。

\documentclass{standalone}

\usepackage{graphicx}
\usepackage{tikz}
\usetikzlibrary{decorations.pathreplacing, calc, positioning}
\usepackage{comment}

\begin{document}

\begin{comment}
    \begin{tikzpicture}
    \node[align = center] (n1) {Felten \& \\ Fuillaume}; % Create first node with centred text
    \node[right = of n1] (n2) {Lahmeyer}; % Create second node next to first
    \draw[decorate,decoration={brace,mirror}] let \p1=(n1.south), \p2=(n2.south) in (\x1,\y1) -- (\x2,\y1); 
    \node[below = of $(n1)!0.5!(n2)$] (n3) {Felten \& Lahmeyer};
    \end{tikzpicture}
\end{comment}
    

%\begin{comment}
    \begin{tikzpicture}

        % Line 1
        \node[align=center] (n1) {Prior\\ to \\ 1900:};
        \node[align=center, right=of n1] (n2) {Felten \& \\ Fuillaume}; 
        \node[right=of n2] (n3) {Lahmeyer}; 

        \node[align=center, right=of n3] (n4) {Union A.E.G.};
        
        \node[align=center, right=of n4] (n5) {Siemens \\ \& Halske};
        \node[align=center, right=of n5] (n6) {Schuckert \\ \& Co. };
        
        \node[align=center, right=of n6] (n7) {Bergmann};
        \node[align=center, right=of n7] (n8) {Kummer};
        
        % Line 2
        \draw[decorate,decoration={brace,mirror}] let \p1=(n2.south), \p2=(n3.south) in (\x1,\y1) -- (\x2,\y1); 
        \node[align=center, below=of $(n2)!0.5!(n3)$] (n11) {Felten  \& \\ Lahmeyer};

        \node[align=center, below=of n4] (n12) {A.E.G. (Gen.El.Co.)};
        \draw[decorate] (n4) -- (n12);
        
        \draw[decorate,decoration={brace,mirror}] let \p1=(n5.south), \p2=(n6.south) in (\x1,\y1) -- (\x2,\y1); 
        \node[align=center, below=of $(n5)!0.5!(n6)$] (n13) {Siemens \& \\ Halske-Schuckert};
        
        \node[align=center, below=of n7] (n14) {Bergman};
        \draw[decorate] (n7) -- (n14);
        
        \node[align=center, below=of n8] (n15) {Failed \\ in 1900};
        \draw[decorate] (n8) -- (n15);
        
        % Line 3
        \draw[decorate,decoration={brace,mirror}] let \p1=(n11.south), \p2=(n12.south) in (\x1,\y1) -- (\x2,\y1); 
        \node[align=center, below=of $(n12)!0.5!(n11)$] (n21) {A.E.G. (General Electric Co.)};
        
        \draw[decorate,decoration={brace,mirror}] let \p1=(n13.south), \p2=(n14.south) in (\x1,\y1) -- (\x2,\y1); 
        \node[align=center, below=of $(n13)!0.5!(n14)$] (n22) {Siemens \&  Halske-Schuckert};
        
        % Line 4
        \node[align=center, below = of n1] (n10) {};
        \node[align=center, below = of n10] (n20) {};
        \node[align=center, below = of n20] (n30) {By \\ 1912:};
        
        %\draw[decorate,decoration={pathreplacing}] let \p1=(n21.south), \p2=(n22.south) in (\x1,\y1) -- (\x2,\y1); 
        \node[align=center, below=of $(n21)!0.5!(n22)$] (n31) {(In close ``cooperation'' since 1908)};
    \end{tikzpicture}
%\end{comment}

\end{document}

Answer 2

\documentclass[tikz, border=1cm]{standalone}
\usetikzlibrary{calc, decorations.pathreplacing, calligraphy}
\begin{document}
\begin{tikzpicture}[
every node/.style={align=center, outer sep=8pt},
node distance=3cm,
]
\node (a1) at (0,0) {Prior\\to\\1900:};
\node[right of=a1] (a2) {Felten \&\\Guillaume};
\node[right of=a2] (a3) {Lahmeyer};
\draw[very thick, decorate, decoration={calligraphic brace, mirror, amplitude=6pt}] (a2.south) -| (a3.south);
\node[below=1cm] (b1) at ($(a2)!0.5!(a3)$) {Felten \& Lahmeyer};
\end{tikzpicture}
\end{document}