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答案1
您想要的\left\{...\middle|...\right\}
;alignedat
您可以设定条件。
但是,您也希望简化输入以避免错误。
\documentclass{article}
\usepackage{amsmath,amssymb,bm}
\newcommand{\bE}{\mathbb{E}}
\newcommand{\bF}{\mathbb{F}}
\newcommand{\bQ}{\mathbb{Q}}
\newcommand{\bR}{\mathbb{R}}
\newcommand{\cP}{\mathcal{P}}
\newcommand{\cZ}{\mathcal{Z}}
\newcommand{\vv}[1]{\ifcat#1\relax\bm{#1}\else\mathbf{#1}\fi}
\newcommand{\barvv}[1]{\bar{\vv{#1}}}
\begin{document}
\[
\bar{\bF}=
\left\{
\bQ \in \cP_{0}(\bR^{M}\times\bR^{I})
\;\middle|\;
\begin{alignedat}{2}
& (\barvv{z},\barvv{v})\sim\bQ \\
& \bE_{\bQ}(\barvv{z} \mid \bar{\vv{v}}\in\Omega_{l})=\vv{\mu}_{l},{}
&& \forall l \in [L] \\
& \bE_{\bQ}((\bar{z}_{jl}-\mu_{jl})^{2} \mid \barvv{v}\in\Omega_{l})\le\sigma_{jl}^2,{}
&& \forall l \in [L], j \in [M] \\
& \bQ(\barvv{v}\in\Omega_{l})=p_l,{}
&& \forall l \in [L] \\
& \bQ(\barvv{z}\in\cZ_{l} \mid \barvv{v}\in\Omega_{l})=1,
&& \forall l \in [L]
\end{alignedat}
\right\}
\]
\end{document}
然而,如果你按照以下方式做,你的读者会更高兴:
\documentclass{article}
\usepackage{amsmath,amssymb,bm}
\newcommand{\bE}{\mathbb{E}}
\newcommand{\bF}{\mathbb{F}}
\newcommand{\bQ}{\mathbb{Q}}
\newcommand{\bR}{\mathbb{R}}
\newcommand{\cP}{\mathcal{P}}
\newcommand{\cZ}{\mathcal{Z}}
\newcommand{\vv}[1]{\ifcat#1\relax\bm{#1}\else\mathbf{#1}\fi}
\newcommand{\barvv}[1]{\bar{\vv{#1}}}
\begin{document}
Let $\bar{\bF}$ be the set of all snarfs $\bQ \in \cP_{0}(\bR^{M}\times\bR^{I})$
such that
\begin{alignat*}{2}
& (\barvv{z},\barvv{v})\sim\bQ \\
& \bE_{\bQ}(\barvv{z} \mid \bar{\vv{v}}\in\Omega_{l})=\vv{\mu}_{l},{}
&\quad& \forall l \in [L] \\
& \bE_{\bQ}((\bar{z}_{jl}-\mu_{jl})^{2} \mid \barvv{v}\in\Omega_{l})\le\sigma_{jl}^2,{}
&\quad& \forall l \in [L], j \in [M] \\
& \bQ(\barvv{v}\in\Omega_{l})=p_l,{}
&\quad& \forall l \in [L] \\
& \bQ(\barvv{z}\in\cZ_{l} \mid \barvv{v}\in\Omega_{l})=1,
&\quad& \forall l \in [L]
\end{alignat*}
\end{document}
代替咆哮使用适当的名称。;-)