当我使用 witharrows 包尝试标记和引用方程式时，我遇到了问题，我不知道如何修复它。如果有人知道如何修复它，那将非常有帮助。这里我放了代码（我知道有很多代码对于这个问题来说不是必要的，但我使用了一些我自己编写的函数，很难重写代码）：
\documentclass[a4paper, 12pt]{book}
% fuente de letra:
\usepackage{lmodern}
% matemáticas:
\usepackage{amsmath, amssymb}
% idioma:
\usepackage[utf8]{inputenc}
\usepackage[spanish, es-tabla]{babel} % 'cuadro' es el título del caption de table por defecto siguiendo indicaciones de RAE; es-tabla lo cambia a 'tabla'
% gestión de párrafos (hace innecesario indicar el salto de línea con doble barra y elimina el indent de todos los párrafos):
\usepackage{parskip}
% enlaces a URLs:
\usepackage{hyperref}
% gráficos:
\usepackage{graphicx, wrapfig, subcaption}
% tablas:
\usepackage{array, multirow}
\newcommand{\dl}{\left(}
\newcommand{\dr}{\right)}
\newcommand{\dsin}[1]{\sin{\left(#1\right)}}
\newcommand{\dtan}[1]{\tan{\left(#1\right)}}
\newcommand{\dcos}[1]{\cos{\left(#1\right)}}
\newcommand{\dsec}[1]{\sec{\left(#1\right)}}
\newcommand{\dcsc}[1]{\csc{\left(#1\right)}}
\newcommand{\dcot}[1]{\cot{\left(#1\right)}}
\newcommand{\darcsin}[1]{\arcsin{\left(#1\right)}}
\newcommand{\darccos}[1]{\arccos{\left(#1\right)}}
\newcommand{\darctan}[1]{\arctan{\left(#1\right)}}
\newcommand{\dsinh}[1]{\sinh{\left(#1\right)}}
\newcommand{\dcosh}[1]{\cosh{\left(#1\right)}}
\newcommand{\dtanh}[1]{\tanh{\left(#1\right)}}
\newcommand{\dln}[1]{\ln{\left(#1\right)}}
\newcommand{\dsum}[2]{\displaystyle\sum_{#1}^{#2}}
\newcommand{\dlim}[2]{\lim_{#1\rightarrow#2}}
\newcommand{\dint}[2]{\displaystyle\int_{#1}^{#2}}
\newcommand{\doint}[2]{\displaystyle\oint_{#1}^{#2}}
\NewDocumentCommand{\umathnote}{ mm }
{
\overset % ❶
{% The annotation goes above
\textcolor{black!20!white}{\hbox to 0pt{\hss % ❷
$ % return to math mode
\begin{array}{c} % ❸
\displaystyle #2\\ % ❹
\Big\downarrow % ❺
\end{array}
$
\hss}
}
}
{#1} %
}
\NewDocumentCommand{\dmathnote}{ mm }
{
\underset % ❶
{% The annotation goes above
\textcolor{black!20!white}{\hbox to 0pt{\hss % ❷
$ % return to math mode
\begin{array}{c} % ❸
\Big\uparrow\\ % ❹
\displaystyle #2 % ❺
\end{array}
$
\hss}
}
}
{#1} %
}
\renewcommand{\baselinestretch}{1.35}
\usepackage{titlesec}
\makeatletter
\renewcommand\paragraph{\@startsection{paragraph}{4}{\z@}%
{-2.5ex\@plus -1ex \@minus -.25ex}%
{1.25ex \@plus .25ex}%
{\normalfont\normalsize\bfseries}}
\makeatother
\setcounter{secnumdepth}{4} % how many sectioning levels to assign numbers to
\setcounter{tocdepth}{4} % how many sectioning levels to show in ToC
\usepackage[all]{xy}
\usepackage{pgfplots}
\pgfplotsset{compat=1.16}
\usepackage{tikz}
\usetikzlibrary{calc, arrows}
\usepackage[makeroom]{cancel}
\newenvironment{grand}
{\begin{center}\large}
{\end{center}}
\usepackage[framemethod=TikZ]{mdframed}
\newcounter{dem}[chapter]\setcounter{dem}{0}
\renewcommand{\thedem}{\Roman{dem}}
\newenvironment{dem}[2][]{%
\refstepcounter{dem}%
\ifstrempty{#1}%
{\mdfsetup{%
frametitle={%
\tikz[baseline=(current bounding box.east),outer sep=0pt]
\node[anchor=east,rectangle,fill=white]
{\strut Demostración~\thedem};}}
}%
{\mdfsetup{%
frametitle={%
\tikz[baseline=(current bounding box.east),outer sep=0pt]
\node[anchor=east,rectangle,fill=white]
{\begin{minipage}{0.99\linewidth}Demostración~\thedem~#1\end{minipage}};}}%
}%
\mdfsetup{innertopmargin=10pt,linecolor=black,%
linewidth=0.5pt,topline=true,%
frametitleaboveskip=\dimexpr-\ht\strutbox\relax
}
\begin{mdframed}[]\relax%
\label{#2}}{\end{mdframed}}
\usepackage{nccmath}
\usepackage{tcolorbox}
\tcbuselibrary{most}
\newtcolorbox[auto counter,
number within=chapter,
list inside=ej
]{ej}[1][]{%
enhanced, breakable,
title={{\begin{minipage}{\linewidth}\textbf{Ejercicio}~\thetcbcounter.~\textit{#1}\end{minipage}}},
halign title=left,
sharp corners,
colback=white,
coltitle=black,
colbacktitle=white,
boxrule=0pt,frame hidden,
underlay unbroken and first={%
\ifnumequal{\tcbsegmentstate}{0}{
\draw[black,double] (interior.north west)--(interior.south west);
}{\ifnumequal{\tcbsegmentstate}{1}{
\draw[black,double] (interior.north west)--(segmentation.west);
\begin{tcbclipinterior}
\draw[help lines, step=3.8mm, black!20!white](segmentation.south west) grid (frame.south east);
\end{tcbclipinterior}
}{\ifnumequal{\tcbsegmentstate}{2}{
\begin{tcbclipinterior}
\draw[help lines, step=3.8mm, black!20!white](interior.north west) grid (interior.south east);
\end{tcbclipinterior}
}}}
},
underlay middle and last={%
\ifnumequal{\tcbsegmentstate}{0}{
\draw[black,double] (interior.north west)--(interior.south west);
}{\ifnumequal{\tcbsegmentstate}{1}{
\draw[black,double] (interior.north west)--(segmentation.west);
\begin{tcbclipinterior}
\draw[help lines, step=3.8mm, black!20!white](segmentation.south west) grid (frame.south east);
\end{tcbclipinterior}
}{\ifnumequal{\tcbsegmentstate}{2}{
\begin{tcbclipinterior}
\draw[help lines, step=3.8mm, black!20!white](interior.north west) grid (interior.south east);
\end{tcbclipinterior}
}}}
},
boxed title style={%
colframe=white,
boxrule=0pt,
colback=white,
left=0pt,
right=0pt},
attach boxed title to top left={xshift={-5pt}},
lower separated=false,
before lower = {\tcbsubtitle[colback=white, opacityback=0, colframe=black, opacityframe=0, boxrule=1pt, height=1cm, width=2.55cm, valign=center]{\textbf{Solution:}}}
}
\newtcolorbox[auto counter,
number within=chapter,
list inside=defi
]{defi}[1][]{%
enhanced,
title={{\begin{minipage}{0.99\linewidth}\textit{#1}\end{minipage}}},
,
halign title=left,
sharp corners,
colback=white,
coltitle=black,
colbacktitle=white,
boxrule=0pt,frame hidden,
overlay unbroken={%
\draw[black,double] (interior.north west)--(interior.south west);%
},
boxed title style={%
colframe=white,
boxrule=0pt,
colback=white,
left=0pt,
right=0pt},
attach boxed title to top left={xshift={-5pt}},
}
\usepackage{float}
\usepackage{fancyhdr}
\usepackage{geometry}
\usepackage{witharrows}
\newgeometry{bottom=2cm,top=2cm,right=1cm,left=1cm,binding=1cm}
\labelformat{equation}{(#1)}
\title{Paquete para libros}
\author{alvarito mendez}
\date{January 2022}
\begin{document}
\maketitle
\section{Introduction}
\begin{DispWithArrows}[groups]
\left.\begin{array}{c}
m\ddot{x}_1=-kx_1+k\dl x_1-x_2\dr \\
m\ddot{x}_2=-kx_2+k\dl x_2-x_1\dr
\end{array}\right\} \Arrow{$\ddot{x}_1+\ddot{x}_2$} \Arrow[o, jump=2]{$\ddot{x}_1-\ddot{x}_2$} \label{eq:8.2.1}\\
m\dl\ddot{x}_1+\ddot{x}_2\dr=-k\dl x_1+x_2\dr \label{eq:8.2.2} \\
m\dl\ddot{x}_1-\ddot{x}_2\dr=-3k\dl x_1-x_2\dr \label{eq:8.2.3}
\end{DispWithArrows}
El sistema de ecuaciones \ref{eq:8.2.1} se encuentra en un estado acoplado \footnote{Esto se debe a que en ambas ecuaciones aparecen terminos cruzados que hacen que la una dependa de la otra}, sin embargo el sistema formado por las ecuaciones \ref{eq:8.2.2} y \ref{eq:8.2.3} el sistema esta desacoplado.
\end{document}
我把输出放在这里：
