Tikz：两个矩形之间的线结束

Question

我想使用 tikz 库将菱形的东点与两个矩形（第 2 阶段、第 3 阶段）之间的中点连接起来；请看图。

以下是示例代码：

\documentclass[tikz,border=3.14mm]{standalone}
\usepackage{tikz}
\usetikzlibrary{shapes.geometric, arrows}

\begin{document}
\begin{tikzpicture}[sibling distance=80pt,box/.style={rectangle,draw}] 

\tikzstyle{box} = [rectangle, minimum width=3cm, minimum height=1cm, text centered, draw=black]
\tikzstyle{arrow} = [thick,->,>=stealth]
\tikzstyle{decision} = [diamond, minimum width=3cm, minimum height=1cm, text centered, draw=black, aspect=3]

\node (dec)  [decision] {$A>B$};
\node (proc1) [box, below of=dec, yshift=-0.5cm] {Phase 1};
\node (proc2) [box, below of=proc1, yshift=-0.5cm] {Phase 2};
\node (proc3) [box, below of=proc2, yshift=-0.5cm] {Phase 3};

\draw [arrow] (dec) -- (proc1);
\draw [arrow] (proc1) -- (proc2);
\draw [arrow] (proc2) -- (proc3);
\draw [arrow] (dec) -| ([xshift=1cm, yshift=0cm]dec.east) |- coordinate[midway](proc3)(proc2);

\end{tikzpicture}
\end{document}

主要思想是计算两个矩形的中点：Phase2 和 Phase 3。

不幸的是，最终得到的终点是矩形第 2 阶段东边的中点。

感谢您的帮助。

Answer 1

我将按以下方式绘制您的流程图：

\documentclass[border=3.14mm]{standalone}
\usepackage{tikz}
\usetikzlibrary{arrows.meta,
                calc, chains,
                positioning,
                shapes.geometric}

\begin{document}
    \begin{tikzpicture}[
              > = Stealth,  
  node distance = 8mm and 12mm,
    start chain = going below,
     box/.style = {draw, minimum width=3cm, minimum height=1cm, align=center},
decision/.style = {diamond, draw, minimum width=3cm, minimum height=1cm, 
                   align=center, aspect=3}
                        ]
    \begin{scope}[nodes={on chain, join=by ->}]
\node (dec)     [decision]  {$A>B$};
\node (proc1)   [box]       {Phase 1};
\node (proc2)   [box]       {Phase 2};
\node (proc3)   [box]       {Phase 3};
    \end{scope}
\draw [->]      (dec.east) --++ (1,0) |- ($(proc2.south)!0.5!(proc3.north)$);

\end{tikzpicture}
\end{document}

• 节点以链形式连接
• 节点之间的箭头由宏绘制join
• calc最后两个节点之间的坐标通过链计算
• 在定义图像元素样式时使用最近的钾Z语法，用于定位库`定位。

Answer 2

解决方案很简单。连接两个矩形时，计算中点：

\draw [arrow] (proc2) -- (proc3) coordinate[midway] (mid);

并与钻石的东点相连：

\draw [arrow] (dec) -| ([xshift=1cm, yshift=0cm]dec.east) |- (mid);