不同头部的 Squigarrows

Question

我想使用曲线来改变和$\rightsquigarrow$中的项目符号的尖箭头（以及这两个的倒数，其中点位于左侧）。是否可以定义这样的符号？$\multimap$$\multimapdot$

Answer 1

像这样的东西？它们看起来真的很有趣……

\documentclass{article}
\usepackage{txfonts}

\usepackage{trimclip}
\makeatletter
\DeclareRobustCommand*{\squigmultimap}{%
  \mathrel{%
    \mathpalette\@squigmultimap{}%
  }%
}
\newcommand*{\@squigmultimap}[2]{%
  \vcenter{\hbox{\clipbox{0 {.25\height} {.22\width} {.15\height}}{$#1\rightsquigarrow\m@th$}}}%
  \clipbox{{.55\width} 0 0 0}{$#1\multimap\m@th$}%
}

\DeclareRobustCommand*{\squigmultimapdot}{%
  \mathrel{%
    \mathpalette\@squigmultimapdot{}%
  }%
}
\newcommand*{\@squigmultimapdot}[2]{%
  \vcenter{\hbox{\clipbox{0 {.25\height} {.22\width} {.15\height}}{$#1\rightsquigarrow\m@th$}}}%
  \clipbox{{.55\width} 0 0 0}{$#1\multimapdot\m@th$}%
}

\DeclareRobustCommand*{\squigmultimapinv}{%
  \mathrel{%
    \mathpalette\@squigmultimapinv{}%
  }%
}
\newcommand*{\@squigmultimapinv}[2]{%
  \clipbox{0 0 {.55\width} 0}{$#1\multimapinv\m@th$}%
  \vcenter{\hbox{\clipbox{{.22\width} {.25\height} 0 {.15\height}}{$#1\leftsquigarrow\m@th$}}}%
}

\DeclareRobustCommand*{\squigmultimapdotinv}{%
  \mathrel{%
    \mathpalette\@squigmultimapdotinv{}%
  }%
}
\newcommand*{\@squigmultimapdotinv}[2]{%
  \clipbox{0 0 {.55\width} 0}{$#1\multimapdotinv\m@th$}%
  \vcenter{\hbox{\clipbox{{.22\width} {.25\height} 0 {.15\height}}{$#1\leftsquigarrow\m@th$}}}%
}
\makeatother


\begin{document}
\centering

$A \multimap B$

$A \squigmultimap B$

$C \squigmultimapdotinv D$

\bigskip

$n_{A \squigmultimapdotinv B} + x^{C \squigmultimap D}$

\bigskip

$\frac{A \squigmultimapdot B}{C \squigmultimapinv D}$

\end{document}