使用 circuitikz 连接点

Question

我正在尝试使用 circuitikz 包将输入连接到逻辑图中的一个门。

我已经使用各种来源（包括 SE）获得了这一结果，但我想将 B 输入上的第一个点连接到 and2 门输入 2. ANd...然后添加通过 C 输入的交叉点。

我怀疑我遗漏了一些非常简单的东西......

\begin{circuitikz}
    \ctikzset{
        logic ports=ieee,
        logic ports/scale=1,
        logic ports/fill=white
    }

    \draw
    (0,2)       node (and1) [xshift=1cm,and port]      {and1}
    (and1.out)  node        [anchor=south]        {\it A.B}
    (and1.in 1) node (A1)   [anchor=east,xshift=-1cm]  {A}
    (and1.in 2) node (B1)   [anchor=east,xshift=-1cm]  {B} 
    
    (0,0)       node (or1)  [xshift=1cm,or port]       {or1}
    (or1.out)   node        [anchor=south]         {\it B+C}
    (or1.in 2)  node (C1)   [anchor=east, xshift=-1cm] {C}
    (0,-2)       node (and2) [xshift=1cm,and port]       {and2}
    (and2.out)  node        [anchor=south]              {\it B.C}
    (4,-1)       node (and3) [and port] {and3}
    (and3.out)  node        [anchor=north,xshift=0.5cm] {\it BC(B+C)}
    (7,1)       node (or2) [or port] {or2}
    (or2.out)   node (Q)    [anchor=west] {Q = AB+BC(B+C)}
    
    (A1) -- (and1.in 1)
    (B1) -- (and1.in 2)
    (C1) -- (or1.in 2)
    (B1) -| (or1.in 1)
    (C1) -| (and2.in 1)
    (B1) -- (and2.in 2)
    
    (and1.out) -| (or2.in 1)
    (or1.out) -| (and3.in 1)
    (and2.out) -| (and3.in 2)
    (and3.out) -| (or2.in 2)
    ;  

    \node [xshift=1.25cm] at (B1) {$\bullet$};
    \node [xshift=1.25cm] at (C1) {$\bullet$};
    \node [xshift=0.7cm] at (B1) {$\bullet$};
    
\end{circuitikz}

Answer 1

我的第一个建议是避免交叉 --- 绘制电路时的标准规定，如果没有点，交叉线就不会连接，因此教授和学习标准是很好的。在这种情况下，这很容易：

1. 不要直接从(B1)到 画(and2.in 2)，那是对角线；
2. 使用circ节点进行连接（比项目符号更好），并命名有趣的节点；
3. 使用正交坐标。参见：

\documentclass[border=10pt]{standalone}
\usepackage[siunitx, RPvoltages]{circuitikz}
\begin{document}
\begin{tikzpicture}[]
    \ctikzset{
        logic ports=ieee,
        logic ports/scale=1,
        logic ports/fill=white
    }

    \draw
    (0,2)       node (and1) [xshift=1cm,and port]      {and1}
    (and1.out)  node        [anchor=south]        {\it A.B}
    (and1.in 1) node (A1)   [anchor=east,xshift=-1cm]  {A}
    (and1.in 2) node (B1)   [anchor=east,xshift=-1cm]  {B}

    (0,0)       node (or1)  [xshift=1cm,or port]       {or1}
    (or1.out)   node        [anchor=south]         {\it B+C}
    (or1.in 2)  node (C1)   [anchor=east, xshift=-1cm] {C}
    (0,-2)       node (and2) [xshift=1cm,and port]       {and2}
    (and2.out)  node        [anchor=south]              {\it B.C}
    (4,-1)       node (and3) [and port] {and3}
    (and3.out)  node        [anchor=north,xshift=0.5cm] {\it BC(B+C)}
    (7,1)       node (or2) [or port] {or2}
    (or2.out)   node (Q)    [anchor=west] {Q = AB+BC(B+C)}

    (A1) -- (and1.in 1)
    (B1) -- (and1.in 2)
    (C1) -- (or1.in 2)
    (B1) -| (or1.in 1)
    (C1) -| (and2.in 1)
    % (B1) -- (and2.in 2) <<<- removed

    (and1.out) -| (or2.in 1)
    (or1.out) -| (and3.in 1)
    (and2.out) -| (and3.in 2)
    (and3.out) -| (or2.in 2)
    ;

    \node [circ, xshift=1.25cm] at (B1) {};
    \node [circ, xshift=1.25cm] at (C1) {};
    \node [circ, xshift=0.7cm](B1-dot1) at (B1) {};
    
    \draw (B1-dot1) |- (and2.in 2);

\end{tikzpicture}
\end{document}

如果你坚持要穿越，你可以这样做来代替最后的绘制：

    % find the crossing between wire C and the vertical of B1-dot
    \coordinate (c cross) at (B1-dot1 |- C1);
    % plant a jump crossing node there (vertical)
    \node [jump crossing, rotate=90](X) at (c cross) {};
    % draw the connections, be careful with the rotated anchors 
    \draw (B1-dot1) -- (X.east) (X.west) |- (and2.in 2);

获得：

C1请注意，这不是最优的，您还应该从到移除电线or1.in 2，并用交叉点周围的两个线段替换它X，但我会把这个交给您；-)

Answer 2

我用圆圈替换了您的项目符号，并将它们移到了使用它们的线条中。您也可以使用圆圈添加连接，to[short,*-*]但只能在直线上添加。

\documentclass{standalone}
\usepackage{circuitikz}

\begin{document}

\begin{circuitikz}
    \ctikzset{
        logic ports=ieee,
        logic ports/scale=1,
        logic ports/fill=white
    }

    \draw
    (0,2)       node (and1) [xshift=1cm,and port]      {and1}
    (and1.out)  node        [anchor=south]        {\it A.B}
    (and1.in 1) node (A1)   [anchor=east,xshift=-1cm]  {A}
    (and1.in 2) node (B1)   [anchor=east,xshift=-1cm]  {B} 
    
    (0,0)       node (or1)  [xshift=1cm,or port]       {or1}
    (or1.out)   node        [anchor=south]         {\it B+C}
    (or1.in 2)  node (C1)   [anchor=east, xshift=-1cm] {C}
    (0,-2)       node (and2) [xshift=1cm,and port]       {and2}
    (and2.out)  node        [anchor=south]              {\it B.C}
    (4,-1)       node (and3) [and port] {and3}
    (and3.out)  node        [anchor=north,xshift=0.5cm] {\it BC(B+C)}
    (7,1)       node (or2) [or port] {or2}
    (or2.out)   node (Q)    [anchor=west] {Q = AB+BC(B+C)}
  
    (A1) -- (and1.in 1)
    (B1) -- (and1.in 2)
    (C1) -- (or1.in 2)
    (B1) -| (or1.in 1) node[circ, midway] {}
    (C1) -| (and2.in 1) node[circ, midway] {}
    (B1) ++(0.7cm,0) node[circ] {} |- (and2.in 2)
    
    (and1.out) -| (or2.in 1)
    (or1.out) -| (and3.in 1)
    (and2.out) -| (and3.in 2)
    (and3.out) -| (or2.in 2)
    ;  
    
\end{circuitikz}

\end{document}