带切片计数器的环境

Question

我正在从头开始创建一个编号环境teo。我想要一个计数器，为此我使用了teoc。

\newcounter{teoc}[section]
\newenvironment{teo}[1][]
   {\refstepcounter{teoc}\par\smallskip
     \noindent \textbf{\color{blue}Teo~\theteoc. #1}
     \rmfamily}
   {\smallskip}

使用下面的两个调用我得到了Teo 1，Teo 2即使我在第 4 节，这意味着我没有得到Teo 4.1和Teo 4.2

\begin{teo}
  To prove it by contradiction try and assume that the statement is
  false, proceed from there and at some point you will arrive to a
  contradiction.
\end{teo}

\begin{teo}
  To prove it by contradiction try and assume that the statement is
  false, proceed from there and at some point you will arrive to a
  contradiction.
\end{teo}

我想在我的柜台前介绍分区编号方案。

Answer 1

• 您没有提供 MWE，所以我们不知道您使用哪个文档类以及使用哪个包来编写定理。
• 假设您使用amsthm包，可能的解决方案可能是：

\documentclass{article}
\usepackage{color}
\usepackage{amsmath, amsthm}
\newcounter{teoc}[section]
\renewcommand\theteoc{\thesection.\arabic{teoc}} % <---
\newenvironment{teo}[1][]
   {\refstepcounter{teoc}\par\smallskip
     \noindent \textbf{\color{blue}Teo~\theteoc. #1}
     \rmfamily}
   {\smallskip}
\begin{document}
\setcounter{section}{3}
\section{four}
\begin{teo}
  To prove it by contradiction try and assume that the statement is
  false, proceed from there and at some point you will arrive to a
  contradiction.
\end{teo}

\begin{teo}
  To prove it by contradiction try and assume that the statement is
  false, proceed from there and at some point you will arrive to a
  contradiction.
\end{teo}
\end{document}