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如何在使用数组环境对齐等号时缩进或使用制表符分隔多部分问题（详情见图片）？

tag-icon • tag-icon indentation enumitem arrays
如何在使用数组环境对齐等号时缩进或使用制表符分隔多部分问题（详情见图片）？ 
\documentclass{article}
\usepackage[shortlabels]{enumitem}
\usepackage{amsmath}

\begin{document}
Let \(f(x)=2x^2-12x+13\)
    \begin{enumerate}[(a)]
        \item Express $f$ in standard form.
        \begin{align*}
            f(x)&=2x(x-6x)+13 \\
            &=2x(x-6x+9)+13-(2\times9) \\
            &=2x(x-3)^2-5
        \end{align*}
    \end{enumerate}
\end{document}

它应该是什么样子的例子

答案1

喜欢这个 (只限项目 a) 吗？

编辑：
在您的文档中，您似乎希望等于零\parident，并且所有列表项标签都从文本的左边框开始。这可以通过 MWE 的第一个版本中的更改来实现，现在标记为% <---：

在此处输入图片描述

（红线表示文本块边框）

\documentclass{article}
%\usepackage{geometry}
%---------------- show page layout. don't use in a real document!
\usepackage{showframe}
\renewcommand\ShowFrameLinethickness{0.15pt}
\renewcommand*\ShowFrameColor{\color{red}}
%---------------------------------------------------------------%
\usepackage{lipsum}% For dummy text. Don't use in a real document

\usepackage{enumitem}                           % <--- 
\setlist[enumerate]{label=(\textbf{\alph*}),    % <--- 
                    align=left,                 % <--- 
                    leftmargin=*}               % <--- 
\usepackage{tabularray}
\UseTblrLibrary{amsmath}
\setlength\parindent{0pt}                       % <---

\begin{document}
Let \(f(x)=2x^2-12x+13\)

    \begin{enumerate} % <---
\item   Since the coefficient of $x^2$ is not 1, \dots

    \begin{tblr}{colspec={@{} Q[l,m, mode=math]@{\,} 
                              Q[l,m, mode=math] 
                              X[l,m, font=\small\linespread{0.84}\selectfont,
                                fg=cyan7]},
                row{Z} = {belowsep+=1ex}
                }
f(x)    
    & = f(x)=2x^2-12x+13
        &                                               \\
    & = 2x(x-6x)+13             
        & Factor 2 from the $x$ terms                   \\
    & = 2x(x-6x+\textcolor{red}{9})+13-(2\cdot\textcolor{red}{9}) 
        & {Complete the square: Add 9 inside\\
           parenthesis, subtract $2\cdot 9$ outside}    \\
    & =2 x(x-3)^2-5
        & Factor 2 from the $x$ terms   
    \end{tblr}
    The standard form is ...
\item   From the standard form of $f$ we can ...
    \end{enumerate}
\item   Since the coefficient of $x^2$ is not 1, \dots

    \begin{tblr}{colspec={@{} Q[l,m, mode=math]@{\,} 
                              Q[l,m, mode=math] 
                              X[l,m, font=\small\linespread{0.84}\selectfont,
                                fg=cyan7]},
                row{Z} = {belowsep+=1ex}
                }
f(x)    
    & = f(x)=2x^2-12x+13
        &                                               \\
    & = 2x(x-6x)+13             
        & Factor 2 from the $x$ terms                   \\
    & = 2x(x-6x+\textcolor{red}{9})+13-(2\cdot\textcolor{red}{9}) 
        & {Complete the square: Add 9 inside\\
           parenthesis, subtract $2\cdot 9$ outside}    \\
    & =2 x(x-3)^2-5
        & Factor 2 from the $x$ terms   
    \end{tblr}
    The stabdard form is ...
\item   From the standard form of $f$ we can ...
    \end{enumerate}
\end{document}

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