我有个问题。问题出在哪里？？当我在第二个表格中使用 \begin{textblock*} 时出现错误。请帮帮我
\documentclass[a4paper, 12pt, twoside ,titlepage]{article}
\usepackage[T1]{fontenc}
\usepackage[utf8]{inputenc}
\usepackage[italian]{babel}
\usepackage{titlesec}
\titlespacing*{\section}{0pt}{0pt}{20pt}
\usepackage{geometry}
\geometry{a4paper,top=4cm,bottom=4cm,left=3cm,right=3cm,heightrounded,bindingoffset=5mm}
\usepackage{amsmath}
\usepackage{graphicx}
\usepackage{caption}
\captionsetup{skip=20pt,format=hang,position=bottom,font=small,labelformat=parens}
\usepackage{tikz}
\usepackage{hyperref}
\hypersetup{hidelinks}
\usepackage{textpos}
\usepackage{fancyhdr}
\fancyhf{}
\fancyfoot[C]{\thepage}
\fancyhead[LO]{\slshape \rightmark}
\fancyhead[RE]{\slshape \leftmark}
\pagestyle{fancy}
\renewcommand{\headrulewidth}{0.4pt}
\renewcommand{\footrulewidth}{0.8pt}
\renewcommand{\sectionmark}[1]{\markboth{\thesection\ \ #1}{}}
\newcommand{\HRule}[1]{\rule{\linewidth}{#1}}
\title{
\vspace{1.5cm}
\HRule{0.5pt}\\ [0.4cm]
\textbf{\Huge\textsc{Progetto\\ blabla}}
\HRule{1pt}\\ [0.6cm]}
\author{\textbf{Nome:} Luca \\ \textbf{Cognome:} blabla \\
\textbf{Matricola:} blablabla}
\date{\textbf{Anno Accademico:} 21-22}
\begin{document}
\begin{figure}
\centering
\includegraphics[width=6cm]{logo.png}
\HRule{0.5pt}\\ [0.2cm]
\Large \texttt{Dipartimento di Ingegneria e Architettura} \\
\Large\texttt{Ingegneria Eletronica - Informatica}
\end{figure}
\maketitle
\tableofcontents
\thispagestyle{empty}
\newpage
\listoftables
\thispagestyle{empty}
\newpage
\setcounter{page}{1}
\section*{Introduzione}
blabla
\addcontentsline{toc}{section}{Introduzione}
\thispagestyle{plain}
\newpage
\section{blablabla \mbox{alla} matricola}
blablabla; \\
\hspace{12pt}\textbf{Numero Matricola: blabla}
\begin{enumerate}
\item blabla
\item blabla
$ blablabla $ \\
\item blablabla
\begin{textblock*}{150pt}(150pt, 30pt)
\begin{tabular}{r|c}
42280&0 \\
21140&0 \\
10570&0 \\
5285&1 \\
2642&0 \\
1321&1 \\
660&0 \\
330& 0 \\
165&1 \\
82&0 \\
41&1 \\
20&0 \\
10&0 \\
5&1 \\
2&0 \\
1&1 \\
0& / \\
\end{tabular}
\begin{table}
\caption{blablabla}
\label{tab: Fun}
\end{table}
\end{textblock*}
\begin{textblock*}{180pt}(220pt,20pt)
\begin{tikzpicture}
\node (A) at (0, -9) {};
\node (B) at (0, 0) {};
\draw[->] (A) -- (B);
\end{tikzpicture}
\end{textblock*}
\newpage
Letto dal basso verso l'alto, come indica la freccia nella Tabella (\ref{tab: Fun}), il \mbox{risultato} è il seguente: \\
\hspace{4cm} $blablabla$ \\
\item blablabla :
\end{enumerate}
\begin{textblock*}{100pt}{180pt,50pt}
\begin{tabular}{ c c c c||c }
$x$ & $y$ & $z$ & $w$ & $f(x, y, z, w)$ \\
\hline
0 & 0 & 0 & 0 & 1\\
0 & 0 & 0 & 1 & 0\\
0 & 0 & 1 & 0 & 1\\
0 & 0 & 1 & 1 & 0\\
0 & 1 & 0 & 0 & 0\\
0 & 1 & 0 & 1 & 1\\
0 & 1 & 1 & 0 & 0\\
0 & 1 & 1 & 1 & 1\\
1 & 0 & 0 & 0 & 0\\
1 & 0 & 0 & 1 & 0\\
1 & 0 & 1 & 0 & 1\\
1 & 0 & 1 & 1 & 0\\
1 & 1 & 0 & 0 & 1\\
1 & 1 & 0 & 1 & 0\\
1 & 1 & 1 & 0 & 0\\
1 & 1 & 1 & 1 & 0\\
\end{tabular}
\end{textblock*}
\end{document}
答案1
你\begin{textblock*}{100pt}{180pt,50pt}應該是\begin{textblock*}{100pt}(180pt,50pt)。