我有以下代码：
\documentclass[tikz,border=2pt,convert]{standalone}
\usepackage{mathtools}
\usetikzlibrary{
arrows.meta,
bbox,
decorations.pathmorphing,
ext.shapes.superellipse,
positioning,
quotes,
}
\tikzset{
shorten/.style={shorten <={#1},shorten >={#1}},
math node/.style={execute at begin node=$, execute at end node=$}}
\begin{document}
\begin{tikzpicture}[scale=1,
@label/.style n args={4}{"#4{#1}" {#2, inner sep=+.1em},
"\vphantom{#1}" {#3, inner sep=+.1em}},
l/.style={@label={#1}{above}{below}{\mathclap}},
l'/.style={@label={#1}{below left}{above left}{}},
>={Triangle[scale=1.33, angle=45:1pt 3]},
dot/.style={shape=circle, fill=black, draw=none, minimum size=+3pt,
inner sep=+0pt, outer sep=+0pt, node contents=},
mat/.style={
every outer matrix/.append style={thick,shape=ellipse},
draw=black, fill=gray!30},
mat line/.style={draw=red},
snakes/.style={
decorate, decoration={snake, segment length=#1, amplitude=+.5pt}},
every label/.append style=math node,every edge quotes/.append style=math node,
dashed line/.style={dash pattern=on \pgflinewidth off 4\pgflinewidth},
]
\matrix[mat, "\tilde X" right] (upper set) {
\node (us-q) at (-10mm,0) [dot, l=\tilde f(0)];
\node (us--q) at (10mm,0) [dot, l=\tilde f(1)];
\draw[mat line, snakes=3.333mm] (us-q) -- (us--q);
\\};
\matrix[mat, "X" right, below=1.5cm of upper set] (lower set) {
\node (ls-R) at (-10mm,0) [dot, l'=f(0)];
\node (ls--R) at (10mm,0) [dot, l'= f(1)];
\draw[mat line, snakes=3.333mm] (ls-R) -- (ls--R);
\\};
\path[dashed, out=90, in=-90] (ls-R) edge (us-q);
\path[thick,|->, shorten=2mm] (upper set) edge["p" name=P] (lower set);
\path[shift=(P), xshift=-5cm, |-|] (0,0) edge["I"' name=I] ++(right:1.5cm);
\path[->, shorten=1mm] (I)
edge[out=60, in=185, "\tilde f"] (upper set)
edge[out=45, in=160, "f"] (lower set);
\end{tikzpicture}
\end{document}
这给了我以下输出：
我想让上部集合大于下部集合。有没有办法指定这样的尺寸？