我希望节点在我的 tikz 图中以某种方式对齐。
首先考虑下面的代码：
\tikzstyle{rec style}= [draw , shape = rectangle , fill = white , drop shadow , minimum height = 1.5cm , rounded corners , minimum width = 2cm , align = center]
\newcommand\ppbb{path picture bounding box}
\tikzstyle{diamond plus} = [diamond, draw, minimum size=8mm , font=\bfseries ,
path picture = {\draw[line width=1mm,shorten <=2mm,shorten >=2mm]
(path picture bounding box.north) edge (\ppbb.south)
(\ppbb.west) edge (\ppbb.east);
},node contents={}]
\tikzstyle{arrow style} = [-{Latex[scale = 1.2]} , semithick]
\usepackage{positioning}
\usepackage{tikz}
\begin{document}
\begin{tikzpicture}[node distance = 2cm]
\node (a)[draw, rec style ]{A};
\node (b)[draw, rec style , below = of a.center ]{B};
\node (c)[draw, diamond plus , below = of b.center];
\node (d)[draw, rec style , below left = of c.center , xshift = -2cm]{C};
\node (e)[draw, rec style , below right = of c.center , xshift = 2cm]{D};
\node (f)[draw, diamond plus , below = of d.center];
\node (g)[draw, diamond plus , below = of e.center];
\node (h)[draw, rec style, below left = of f.center , yshift = -1cm]{E};
\node (i)[draw, rec style, below left = of g.center , yshift = -1cm]{F};
\node(j)[diamond plus , below = of c.center , yshift = -9cm];
\node(k)[draw , rec style , below = of j]{G};
% Now let's draw the arrows;
\draw [arrow style] (a) -- (b);
\draw [arrow style] (b) -- (c);
\draw [arrow style] (c) -| (d);
\draw [arrow style] (c) -| (e);
\draw [arrow style] (d) -- (f);
\draw [arrow style] (e) -- (g);
\draw [arrow style] (f) -| (h); % Node on which we will place text;
\draw [arrow style] (g) -| (i);
\draw [arrow style] (h) |- (j);
\draw [arrow style] (h) |- (j);
\draw [arrow style] (f) -| (j);
\draw [arrow style](j) -- (k);
\end{tikzpicture}
\end{document}
下图说明了我想要做的事情。我希望图中红点所示的节点与节点 i 和 j 的中心对齐。
答案1
我认为您在处理相对位置未沿树向下对齐的问题（我的代码中的节点 h 和 i）。我为可能对此更了解的其他人清理了 MWE。我自己会使用绝对坐标。
\documentclass{article}
\usepackage{tikz}
\usetikzlibrary{positioning}
\begin{document}
\begin{tikzpicture}
\node (a)[draw]{A};
\node (b)[draw, below = of a]{B};
\node (junc1a)[draw, below = of b]{};
\node (junc1b)[right = of junc1a]{};
\node (c)[draw, below left = of junc1a]{C};
\node (d)[draw, below right = of junc1b]{D};
\node (junc2a)[draw, below = of c]{};
\node (junc2b)[draw, below = of d]{};
\node (e)[draw, below left = of junc2a]{E};
\node (junc3)[below right = of junc2a]{};
\node (f)[draw, below left = of junc2b]{F};
\node (junc4)[draw, below = of junc3]{};
\node (g)[draw, below = of junc4]{G};
\node (h)[draw, below = of f]{};
\node (i)[draw, right = of junc4]{};
\draw (a) -- (b);
\draw (b) -- (junc1a);
\draw (junc1a) -| (c);
\draw (junc1a) -| (d);
\draw (c) -- (junc2a);
\draw (d) -- (junc2b);
\draw (junc2a) -| (e);
\draw (junc2a) -| (junc4);
\draw (junc2b) -| (f);
\draw (e) |- (junc4);
\draw (junc4) -- (g);
\end{tikzpicture}
\end{document}
为了明确起见，我会使用：
\documentclass{article}
\usepackage{tikz}
\usetikzlibrary{positioning}
\begin{document}
\begin{tikzpicture}
\node (a)[draw] at (2,0) {A};
\node (b)[draw] at (2,-1) {B};
\node (junc1)[draw] at (2,-2) {};
\node (c)[draw] at (1,-3) {C};
\node (d)[draw] at (4,-3) {D};
\node (junc2a)[draw] at (1,-4) {};
\node (junc2b)[draw] at (4,-4) {};
\node (e)[draw] at (0,-5) {E};
\node (f)[draw] at (3,-5) {F};
\node (junc3)[draw] at (2,-6) {};
\node (g)[draw] at (2,-7) {G};
\node (h)[draw] at (3,-6) {};
\draw (a) -- (b);
\draw (b) -- (junc1);
\draw (junc1) -| (c);
\draw (junc1) -| (d);
\draw (c) -- (junc2a);
\draw (d) -- (junc2b);
\draw (junc2a) -| (e);
\draw (junc2a) -| (junc3);
\draw (junc2b) -| (f);
\draw (e) |- (junc3);
\draw (junc3) -- (g);
\end{tikzpicture}
\end{document}