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{amsmath} 使用 \enumitem 与 \tasks 日志中的多个错误

tag-icon • tag-icon amsmath enumitem tasks
{amsmath} 使用 \enumitem 与 \tasks 日志中的多个错误

下面的 mwe 代码在 overleaf.com 中编译。

但是下面的截图显示了生成的错误消息，尽管我花了几个小时进行调整和研究 tex.stack 帖子，但我仍无法解决。

您的帮助将使我保持理智！:)

谢谢你！

姆韦

\documentclass[12pt]{exam}

\usepackage{amsmath}
%\usepackage{cancel}
%\usepackage{caption} 
% allows captions in minipage envir
\usepackage{amssymb}
%\usepackage{mathrsfs}
\usepackage{framed} %box para
\usepackage{multicol}
\usepackage{tasks}
\usepackage[margin=0.5in]{geometry}
%\everymath{\displaystyle}

\setlength{\parindent}{0pt} % removes paragraph indentation

\pagestyle{head}
\header{Unit 9 Assignment: Lesson 4-7 Part 1 - Quadratic Formula Practice}
       {}
       {02/13/2023} 

\newcommand{\pagetop}{%
  %\makebox[\textwidth]%{Name:\enspace\hrulefill}\par
  \vspace{4mm}
  \fbox{\fbox{\parbox{\dimexpr\textwidth-4\fboxsep-4\fboxrule}{
    \textbf {Use the Quadratic Formula to solve each equation. Write answers in 2 forms: (1) integer or simplified radical (2) decimal approximation.}
    %\par
    %\bigskip

  }}}\par
  \vspace{0.5mm}
}

\begin{document}
\pagetop

\newcommand*{\qf}{x=\frac{-(b) \pm\sqrt{(b)^2-4(a)(c)}}{2(a)}}

\settasks{
    after-item-skip=5em,    after-skip=2cm,
    label-width=2em,
    item-indent=3em,
    label=(\arabic*),
    column-sep=2em
}
\begin{tasks}(2)
%Prob #1
\task -x^2+7x-3=0

Divide by -1 to cancel -1 on leading coefficient.

x^2-7x+3=0

\begin{aligned}
x&=\frac{-(7)\pm\sqrt{(-7)^2-4(1)(3)}}{2(1)}

&=\frac{-7\pm\sqrt{7^2-12}}{2}

&=\frac{-7\pm\sqrt{37}}{2}
\end{aligned}
%Prob #2
\task 0=-0.01x^2+1.22x+3

mutliply through by 100 to eliminate decimals.

0=-1x^2+122x+3

Since the problem asks for horizontal distance@ 30 ft height, can I write this equation:
30=-1x^2+122x+300

Set equation equal to zero by subtracting 30 from both sides.
0=-1x^2+122x+270
and then solve for x

x&=\frac{(-122)\pm\sqrt{(-122)^2-4(-1)(300)}}{2(-1)}

x&=\frac{(-122)\pm\sqrt{16084}}{2(-1)}

x=-2.17 or 124.41

\qf
\end{tasks}
\end{document}

在此处输入图片描述

答案1

在此处输入图片描述

你只需要注意，所有的数学都是在数学模式下进行的

\documentclass[12pt]{exam}

\usepackage{amsmath}
%\usepackage{cancel}
%\usepackage{caption} 
% allows captions in minipage envir
\usepackage{amssymb}
%\usepackage{mathrsfs}
\usepackage{framed} %box para
\usepackage{multicol}
\usepackage{tasks}
\usepackage[margin=0.5in]{geometry}
%\everymath{\displaystyle}

\setlength{\parindent}{0pt} % removes paragraph indentation

\pagestyle{head}
\header{Unit 9 Assignment: Lesson 4-7 Part 1 - Quadratic Formula Practice}
       {}
       {02/13/2023} 

\newcommand{\pagetop}{%
  %\makebox[\textwidth]%{Name:\enspace\hrulefill}\par
  \vspace{4mm}
  \fbox{\fbox{\parbox{\dimexpr\textwidth-4\fboxsep-4\fboxrule}{
    \textbf {Use the Quadratic Formula to solve each equation. Write answers in 2 forms: (1) integer or simplified radical (2) decimal approximation.}
    %\par
    %\bigskip

  }}}\par
  \vspace{0.5mm}
}

\begin{document}
\pagetop

\newcommand*{\qf}{$x=\frac{-(b) \pm\sqrt{(b)^2-4(a)(c)}}{2(a)}$}

\settasks{
    after-item-skip=5em,    after-skip=2cm,
    label-width=2em,
    item-indent=3em,
    label=(\arabic*),
    column-sep=2em
}
\begin{tasks}(2)
%Prob #1
\task $-x^2+7x-3=0$

Divide by $-1$ to cancel $-1$ on leading coefficient.
\[
x^2-7x+3=0
\]
\begin{align*}
x&=\frac{-(7)\pm\sqrt{(-7)^2-4(1)(3)}}{2(1)}\\
&=\frac{-7\pm\sqrt{7^2-12}}{2}\\
&=\frac{-7\pm\sqrt{37}}{2}
\end{align*}


%Prob #2
\task $0=-0.01x^2+1.22x+3$

mutliply through by $100$ to eliminate decimals.
\[
0=-1x^2+122x+3
\]
Since the problem asks for horizontal distance@ 30 ft height, can I write this equation:
\[
30=-1x^2+122x+300
\]
Set equation equal to zero by subtracting $30$ from both sides.
\[
0=-1x^2+122x+270
\]
and then solve for $x$
\begin{align*}
x&=\frac{(-122)\pm\sqrt{(-122)^2-4(-1)(300)}}{2(-1)}\\
x&=\frac{(-122)\pm\sqrt{16084}}{2(-1)}
\end{align*}

$x=-2.17$ or $124.41$

\qf
\end{tasks}
\end{document}

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