我有一个从屏幕上剪下来的图表。我尝试用 将其置于中心\begin{center}，但似乎没有任何效果。
这是我的代码：
\documentclass{article}
\usepackage[dvipsnames]{xcolor}
\usepackage{tikz}
\usetikzlibrary{arrows}
\usetikzlibrary{arrows.meta}
\usetikzlibrary{positioning}
\begin{document}
\begin{center}
\begin{tikzpicture}
\node[text width=5cm,align=center,draw] (ftli) {
\textbf{FTLI}:
\[
\int_{C}\nabla f \cdot \,d \vec{s} = f(\vec{B}) - f(\vec{A})\,.
\]
for any curve $C$ in $X$ which starts at $\vec{A}$ and ends at $\vec{B}$.
};
\node[text width=5cm,align=center,draw] (pi) [below left= 3cm of ftli] {
\textbf{Path Independent on} $X$:
\[
\int_{C_1} F\,ds = \int_{C_2} F\,ds
\]
for any two curves $C_1$ and $C_2$ in $X$ which start and end at the same points.
};
\node[text width=5cm,align=center,draw] (cons) [below right= 3cm of ftli] {
\textbf{$F$ Conservative}
\[
\nabla f
=
\vec{F}.
\]
on $X$ for some function $f$.
};
\node[draw,dotted,align=center] (0) [below= 3cm of pi] {
\(
\oint_{C} Fds=0
\)
for all closed curves $C$ on $X$.
};
\node[draw,dotted,align=center] (sym) [below= 5cm of cons] {$D\vec{F}$ is symmetric on $X$.};
\draw[shorten >=0.5cm,double,-{>[length=5pt]},double distance = 2pt] (ftli) -- (pi) node[midway,above] {(Corollary of the FTLI)};
\draw[shorten <=0.5cm,double,-{>[length=5pt]},double distance = 2pt] (cons) -- (ftli) node[midway,above] {$X$ \textcolor{ForestGreen}{open}, \textcolor{Blue}{connected}.};
\draw[shorten <=0.1cm,shorten >=0.1cm,double,{<[length=5pt]}-{>[length=5pt]},double distance = 2pt] (pi) -- (0);
\draw[shorten >=0.1cm,shorten <=0.1cm,double,{[length=5pt]}-{>[length=5pt]},double distance = 2pt] (cons) -- (sym) node[midway,above] {$X$ \textcolor{ForestGreen}{open}, \textcolor{Blue}{\textit{connected}}.};
\draw[shorten >=0.1cm,shorten <=0.1cm,double,{[length=5pt]}-{>[length=5pt]},double distance = 2pt] (sym) -- (0) node[midway,above] {$X$ \textcolor{ForestGreen}{open}, \textcolor{Brown}{\textit{simply connected}}, $\vec{F}$ is $C^1$.};
\end{tikzpicture}
\end{center}
\end{document}
它看起来是这样的：
- 我怎样才能使图表居中？
- 我怎样才能使“五边形”的底部（上面写着 X 开口，简单连接）齐平。我估算了 y 位置，但我想知道如何指定它应该位于一个节点下方和在另一个的右边？
答案1
一些建议：
默认的文本宽度
article非常小。如果您将其放大，例如使用几何包，那么您将有更多的空间用于图表。将图表的两个分支移近一点
您可以使用定位库语法分别指定
below of和right of部分：
\documentclass{article}
\usepackage[dvipsnames]{xcolor}
\usepackage{tikz}
\usepackage{geometry}
\usetikzlibrary{arrows}
\usetikzlibrary{arrows.meta}
\usetikzlibrary{positioning}
\begin{document}
\begin{center}
\begin{tikzpicture}[node distance=5cm and -2cm]
\node[text width=5cm,align=center,draw] (ftli) {
\textbf{FTLI}:
\[
\int_{C}\nabla f \cdot \,d \vec{s} = f(\vec{B}) - f(\vec{A})\,.
\]
for any curve $C$ in $X$ which starts at $\vec{A}$ and ends at $\vec{B}$.
};
\node[text width=5cm,align=center,draw,below left=of ftli] (pi) {
\textbf{Path Independent on} $X$:
\[
\int_{C_1} F\,ds = \int_{C_2} F\,ds
\]
for any two curves $C_1$ and $C_2$ in $X$ which start and end at the same points.
};
\node[text width=5cm,align=center,draw,below=of ftli,right=2cm of pi] (cons) {
\textbf{$F$ Conservative}
\[
\nabla f
=
\vec{F}.
\]
on $X$ for some function $f$.
};
\node[draw,dotted,align=center,below=of pi,text width=5cm] (0) {
\(
\oint_{C} Fds=0
\)
for all closed curves $C$ on $X$.
};
\node[draw,dotted,align=center,below=of cons,right=2cm of 0,text width=5cm] (sym) {$D\vec{F}$ is symmetric on $X$.};
\draw[shorten >=0.5cm,double,-{>[length=5pt]},double distance = 2pt] (ftli) -- (pi) node[midway,above left] {(Corollary of the FTLI)};
\draw[shorten <=0.5cm,double,-{>[length=5pt]},double distance = 2pt] (cons) -- (ftli) node[midway,above right] {$X$ \textcolor{ForestGreen}{open}, \textcolor{Blue}{connected}.};
\draw[shorten <=0.1cm,shorten >=0.1cm,double,{<[length=5pt]}-{>[length=5pt]},double distance = 2pt] (pi) -- (0);
\draw[shorten >=0.1cm,shorten <=0.1cm,double,{[length=5pt]}-{>[length=5pt]},double distance = 2pt] (cons) -- (sym) node[midway,right] {$X$ \textcolor{ForestGreen}{open}, \textcolor{Blue}{\textit{connected}}.};
\draw[shorten >=0.1cm,shorten <=0.1cm,double,{[length=5pt]}-{>[length=5pt]},double distance = 2pt] (sym) -- (0) node[midway,above=0.8cm] {$X$ \textcolor{ForestGreen}{open}, \textcolor{Brown}{\textit{simply connected}}, $\vec{F}$ is $C^1$.};
\end{tikzpicture}
\end{center}
\end{document}
答案2
你的图片让我留在了树上。可以使用以下forest包（相对简单）绘制：
\documentclass{article}
\usepackage{geometry}
\usepackage[dvipsnames]{xcolor}
\usepackage{forest}
\usetikzlibrary{arrows.meta}
\begin{document}
\begin{center}
\begin{forest}
for tree = {draw,
text width=64mm, text centered,
outer sep=2pt,
edge = {arr=->},
l sep=12mm,
s sep=12mm,
tier/.option=level,
/tikz/arr/.style = {>=Implies, double, double distance=2pt, #1},
/tikz/ELS/.style = {% Edge Label Style
pos=0.5,
outer sep=4pt, anchor=#1},
EL/.style = {if n=1{edge label={node[ELS=east]{$#1$}}}
{edge label={node[ELS=west]{$#1$}}}}
},
%%%% diagram body
[{\textbf{FTLI}:
\[
\int_{C}\nabla f \cdot \,d \vec{s} = f(\vec{B}) - f(\vec{A})\,.,
\]
for any curve $C$ in $X$ which starts at $\vec{A}$ and ends at $\vec{B}$.,
}
[\textbf{Path Independent on} $X$:
\[
{\int_{C_1} F\,ds = \int_{C_2} F\,ds}
\]
for any two curves $C_1$ and $C_2$ in $X$ which start and end at the same points.,
name=A,
EL={(Corollary of the FTLI)}
[{$\oint F\,ds$ for all closed curves $C$ on $X$}, dashed, no edge,
name=L]
]
[{\textbf{$F$ Conservative}
\[
\nabla f = \vec{F}
\]
on $X$ for some function $f$.},
name=B,
EL={$X$ \textcolor{ForestGreen}{open},
\textcolor{Blue}{connected}}
[ $D\vec{F}$ is symmetric on $X$., densely dashed, name=R,
]
]
]
\draw[arr=<->] (A) -- (L);
\draw[arr=->] (R) -- node[above=4mm] {$X$ \textcolor{ForestGreen}{open},
\textcolor{Brown}
{\textit{simply connected}},
$\vec{F}$ is $C^1$.} (L);
\draw[arr=->] (B) -- node[right] {$X$ \textcolor{ForestGreen}{open},
\textcolor{Blue}{connected}} (R);
\end{forest}
\end{center}
\end{document}
