如何控制森林环境中父节点与第一个子节点之间的垂直空间

Question

根据答案https://tex.stackexchange.com/a/270761/278762来自@GonzaloMedina。我如何控制y下图所示的垂直空间

代码：

\documentclass[border=5pt]{standalone}
\usepackage{forest}

\begin{document}

\begin{forest}
  for tree={
    font=\ttfamily,
    grow'=0,
    child anchor=west,
    parent anchor=south,
    anchor=west,
    calign=first,
    edge path={
      \noexpand\path [draw, \forestoption{edge}]
      (!u.south west) +(7.5pt,0) |- node[fill,inner sep=1.25pt] {} (.child anchor)\forestoption{edge label};
    },
    before typesetting nodes={
      if n=1
        {insert before={[,phantom]}}
        {}
    },
    fit=band,
    before computing xy={l=15pt},
  }
[text1
  [text1.1
    [text1.1.1]
    [text1.1.2]
    [text1.1.3]
  ]
  [text1.2
    [text1.2.1]
    [text1.2.2]
  ]
]
\end{forest}

\end{document}

输出：

Answer 1

如果您想要更改的所有子项的间距text1.1，您只需更改s sep：

[text1
  [text1.1, s sep=1cm
    [text1.1.1]
    [text1.1.2]
    [text1.1.3]
  ]

另一方面，如果您只想更改上面的间距text 1.1.1，那么您可以yshift=向节点添加：

[text1
  [text1.1
    [text1.1.1, yshift=-1.5cm]
    [text1.1.2]
    [text1.1.3]
  ]

如果要对所有x.x.1节点执行此操作，可以将其添加到for tree：

if n children=0{if n=1{yshift=-1.5cm}{}}{}

完整代码如下：

\documentclass{article}
\usepackage{forest}

\begin{document}

\begin{forest}
  for tree={
    font=\ttfamily,
    grow'=0,
    child anchor=west,
    parent anchor=south,
    anchor=west,
    calign=first,
    edge path={
      \noexpand\path [draw, \forestoption{edge}]
      (!u.south west) +(7.5pt,0) |- node[fill,inner sep=1.25pt] {} (.child anchor)\forestoption{edge label};
    },
    before typesetting nodes={
      if n=1
        {insert before={[,phantom]}}
        {}
    },
    fit=band,
    before computing xy={l=15pt},
    if n children=0{if n=1{yshift=-1.5cm}{}}{}
  }
[text1
  [text1.1
    [text1.1.1]
    [text1.1.2]
    [text1.1.3]
  ]
  [text1.2
    [text1.2.1]
    [text1.2.2]
  ]
]
\end{forest}