当我写很多地图时，地图的对齐并不好。
\documentclass{article}
\usepackage{amsmath,amssymb,amsthm,mathtools,xcolor,enumitem}
\usepackage[hmargin=3cm,vmargin=3cm]{geometry}
\usepackage{pzccal }
\usepackage{mathrsfs}
\usepackage{tikz-cd}
\tikzcdset{scale cd/.style={every label/.append style={scale=#1},
cells={nodes={scale=#1}}}}
\usepackage{graphicx}
\usepackage{mdframed}
\everymath{\color{blue}}
\apptocmd{\[}{\color{blue}}{}{}
\usepackage[breakable]{tcolorbox}
\newcommand{\function}[5][]{ % Function
\ifx &
\begin{array}{rcl}
\displaystyle #2 & \longrightarrow & \displaystyle #3 \\
\displaystyle #4 & \longmapsto & \displaystyle #5
\end{array}
\else
\begin{array}{ccrcl}
\displaystyle #1 & : & \displaystyle #2 & \longrightarrow & \displaystyle #3 \\[10.5pt]
& & \displaystyle #4 & \longmapsto & \displaystyle #5
\end{array}
\fi
}
\newcommand{\functions}[7][]{ % Functions
\ifx &
\begin{array}{rcl}
\displaystyle #2 & \longrightarrow & \displaystyle #3 \\
\displaystyle #4 & \longmapsto & \displaystyle #5 \\
\displaystyle #6 & \longmapsto & \displaystyle #7
\end{array}
\else
\begin{array}{ccrcl}
\displaystyle #1 & : & \displaystyle #2 & \longrightarrow & \displaystyle #3 \\
& & \displaystyle #4 & \longmapsto & \displaystyle #5 \\
& & \displaystyle #6 & \longmapsto & \displaystyle #7
\end{array}
\fi
}
\begin{document}
\begin{tcolorbox}[colback=blue!5,colframe=blue!35!black]
alors les applications:
\[
\function[f]{\widetilde{\mathscr{X}}}{\widetilde{\mathscr{A}}}{X}{A=\mathcal{O}_{X}(X)}
\]
\[
\function[f^{-1}]{\widetilde{\mathscr{A}}}{\widetilde{\mathscr{X}}}{A}{X=Zar(K\mid A)}
\]
\[
\function[g]{\widetilde{\mathscr{A}}}{\widetilde{\mathscr{W}}}{A}{W=\{R\in Zar(K\mid A)\mid R\text{ est un point fermé de } Zar(K\mid A)\}}
\]
\[
\function[g^{-1}]{\widetilde{\mathscr{W}}}{\widetilde{\mathscr{A}}}{W}{\mathcal{O}_{W}(W)}\]
\[
\function[h]{\widetilde{\mathscr{W}}}{\widetilde{\mathscr{X}}}{W }{X=\{R\in Zar(K)\mid \overline{(R)}\cap W=\emptyset\}}
\]
\[
\function[h^{-1}]{\widetilde{\mathscr{X}}}{\widetilde{\mathscr{W}}}{X}{W=\{\text{L'ensemble des points fermé de } X\}}
\]
sont des bijections,chaque application est l'inverse d'autre application en ligne.
\end{tcolorbox}
\end{document}
它看起来像这样：
答案1
我假设您追求的是这样的（到目前为止，从您的问题中还不清楚这一点）：
- 我估计使用您的函数几乎不可能获得上述结果。
tcolorbox在我看来，直接用代码来表达其内容中的数学术语会更加清楚：
\documentclass{article}
\usepackage[hmargin=3cm,vmargin=3cm]{geometry}
\usepackage{xcolor}
\usepackage{pzccal}
\usepackage{mathrsfs}
\usepackage{amssymb,amsthm,
mathtools}
\DeclareMathOperator{\zar}{Zar}
\everymath{\color{blue}}
\usepackage{enumitem}
\usepackage{graphicx}
\usepackage{mdframed}
\apptocmd{\[}{\color{blue}}{}{}
\usepackage[breakable]{tcolorbox}
\begin{document}
\begin{tcolorbox}[colback=blue!5,colframe=blue!35!black]
alors les applications:
\begin{alignat*}{3}
f: &\quad & \widetilde{\mathscr{X}}
& \to \widetilde{\mathscr{A}} \\
& & X
& \mapsto A = \mathcal{O}_{X}(X) \\[1ex]
f^{-1}: & & \widetilde{\mathscr{X}}
& \to \widetilde{\mathscr{A}} \\
& & A
& \mapsto X = \zar(K\mid A) \\[1ex]
g: & & \widetilde{\mathscr{A}}
& \to \widetilde{\mathscr{W}} \\
& & A
& \mapsto W=\{R\in \zar(K\mid A)
\mid R\text{ est un point fermé de }
\zar(K\mid A)\} \\[1ex]
g^{-1}: & & \widetilde{\mathscr{W}}
& \to \widetilde{\mathscr{A}} \\
& & A
& \mapsto \mathcal{O}_{W}(W) \\[1ex]
h: & & \widetilde{\mathscr{W}}
& \to \widetilde{\mathscr{X}} \\
& & W
& \mapsto X=\{R\in \zar(K)\mid \overline{(R)}
\cap W=\emptyset\} \\[1ex]
h^{-1}: & & \widetilde{\mathscr{X}}
& \to \widetilde{\mathscr{W}} \\
& & X
& W = \{\text{L'ensemble des points fermé de } X\}
\end{alignat*}
sont des bijections,chaque application est l'inverse d'autre application en ligne.
\end{tcolorbox}
\end{document}