答案1
和tikz-cd
:
\documentclass{article}
\usepackage{amsmath}
\usepackage{tikz-cd}
% based on \binom
\newcommand{\stirlingi}[2]{\genfrac[]{0pt}{}{#1}{#2}}
\newcommand{\stirlingii}[2]{\genfrac\{\}{0pt}{}{#1}{#2}}
\newcommand{\tstirlingi}[2]{\genfrac[]{0pt}{1}{#1}{#2}}
\newcommand{\tstirlingii}[2]{\genfrac\{\}{0pt}{1}{#1}{#2}}
\begin{document}
\[
\begin{tikzcd}[row sep=8em,column sep=4em]
& x^n \arrow[dl,bend right=20,"(-1)^{n-k}\tstirlingii{n}{k}"']
\arrow[dr,"\tstirlingii{n}{k}"']
\\
x^{(n)} \arrow[ur,"\tstirlingi{n}{k}"']
\arrow[rr,"{L(n,k)}"]
&&
(x)_{n} \arrow[ul,bend right=20,"(-1)^{n-k}\tstirlingi{n}{k}"']
\arrow[ll,bend left=15,"{(-1)^{n-k}L(n,k)}"]
\end{tikzcd}
\]
\end{document}
我会避免使用像您图片中所示的大标签。
标签中的括号L(n,k)
是必需的,以避免 Ti钾Z 误将逗号当作用于分隔选项的符号。
答案2
和xy
:
\documentclass[border=10pt]{standalone}
\usepackage{amsmath,amssymb}
\usepackage[all]{xy}
\begin{document}
$$
\xymatrix@C+2.5em@R+2.5em{
&
x^n
\ar[ddr]_*{\begin{Bmatrix}n\\k\end{Bmatrix}}
\ar@/_15pt/[ddl]_*{(-1)^{n-k}\begin{Bmatrix}n\\k\end{Bmatrix}}
& \\
& & \\
x^{(n)}
\ar[rr]^*{L(n,k)}
\ar[uur]_*{\begin{bmatrix}n\\k\end{bmatrix}}
& &
(x)_{n}
\ar@/^15pt/[ll]^*{(-1)^{n-k}L(n,k)}
\ar@/_15pt/[uul]_*{(-1)^{n-k}\begin{bmatrix}n\\k\end{bmatrix}}
}
$$
\end{document}