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LaTeX3 错误信息的错误使用

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LaTeX3 错误信息的错误使用

下面的代码有什么错误？它给出：

Missing \endcsname inserted.
<to be read again> 
                   \cs_set_nopar:Npx 
l.34 \begin{bdoclatex}[KO]

使用的代码。

\documentclass{article}

\RequirePackage{tcolorbox}
\tcbuselibrary{minted}

\ExplSyntaxOn

\msg_set:nnnn { bdoc } { bdoclatex-unknown-formating }
    { Unknown ~ options ~ for ~ the ~ environment ~ bdoclatex. }
    { You ~ can ~ use ~ sbs (side-by-side), ~ code ~ or ~ std (standard). }

\NewDocumentCommand{\formatting}{m}{
    \str_case:nnF { #1 } {
        {sbs}{listing ~ side ~ text}
        {code}{listing ~ only}
        {std}{listing ~ and ~ text } % What to add here ?
    } {
        \msg_error:nn { bdoc } { bdoclatex-unknown-formating }
    }
}

\ExplSyntaxOff

\newtcblisting{bdoclatex}[1][std]{%
    \formatting{#1}
}

\begin{document}

\begin{bdoclatex}[sbs]
    $A = B + C$
\end{bdoclatex}

\begin{bdoclatex}[KO]
    $A = B + C$
\end{bdoclatex}

\end{document}

答案1

您使用了错误的工具。

\documentclass{article}

\usepackage{tcolorbox}
\tcbuselibrary{minted}

\tcbset{
  sbs/.style=listing side text,
  code/.style=listing only,
  std/.style=listing and text,
}

\newtcblisting{bdoclatex}[1][std]{#1}

\begin{document}

\begin{bdoclatex}[sbs]
    $A = B + C$
\end{bdoclatex}

\begin{bdoclatex}[code]
    $A = B + C$
\end{bdoclatex}

\begin{bdoclatex}[std]
    $A = B + C$
\end{bdoclatex}

\begin{bdoclatex}
    $A = B + C$
\end{bdoclatex}

\begin{bdoclatex}[KO]
    $A = B + C$
\end{bdoclatex}

\end{document}

最后一个你得到了标准

! Package pgfkeys Error: I do not know the key '/tcb/KO' and I am going to 
ignore it. Perhaps you misspelled it.

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