我使用的日历深受现有日历的启发这里。我对我所拥有的非常满意，但是今天，我决定我需要一种方法来匹配重复日期。
我尝试了以下方法：
% Definition
\pgfkeys{/pgf/calendar/recurring/.default = 0}
\pgfkeys{/pgf/calendar/recurring/.code =
{
\foreach \m / \d in {1/4,1/8,2/1}
{
\ifnum\pgfcalendarifdatemonth=\m\relax
\ifnum\pgfcalendarifdateday=\d\relax
\global\pgfcalendarmatchestrue
\fi
\fi
}
}
}
% Usage
if (recurring) [event]
这可以正常工作，但并不实用，因为我需要知道所有日期并将它们包含在循环中。最重要的是，如果我想添加多个重复事件，它就无法重复使用。
我的想法是改变我的重复方法如下：
- 添加一年中的某一天的起点（例如：01-04为了1 月 4 日）。
- 添加以天为单位的时间段（例如：10）。
- 添加一些事件。
第一步
我的第一步是使用参数来处理日期，而不是将它们放在我的定义中。这样我就可以在不同的日期集合中重复使用我的定义。这仍然需要大量配置，但至少我可以为多个重复事件创建一个定义。
这就是我得到的：
% Definition
\pgfkeys{/pgf/calendar/recurring/.default = 0}
\pgfkeys{/pgf/calendar/recurring/.code =
{
\foreach \m/\d in {#1}
{
\ifnum\pgfcalendarifdatemonth=\m\relax
\ifnum\pgfcalendarifdateday=\d\relax
\global\pgfcalendarmatchestrue
\fi
\fi
}
}
}
% Usage
if (recurring={01/04,01/14,01,24}) [event]
第二步
我的第二步是计算日期，包括起始点、周期和事件数量。由于我不知道事件发生的月份和日期，我决定使用儒略日期来计算所有内容。这是我得到的：
% Definition
\pgfkeys{/pgf/calendar/recurring/.default = 0}
\pgfkeys{/pgf/calendar/recurring/.code 3 args={3}
{
\foreach \events in {0,..,#3}
{
\pgfcalendardatetojulian{\year-#1+#2*\events}{\jul}
\ifnum\pgfcalendarifdatejulian=\jul\relax
\global\pgfcalendarmatchestrue
\fi
}
}
}
% Usage
if (recurring={01-04}{14}{3}) [event]
第一个参数是开始日期，第二个参数是时间段，第三个参数是事件数量。
这就是我被困住的地方。什么都不起作用。在 texmaker 中，我遇到以下错误：
! Illegal parameter number in definition of \pgf@temp.
<to be read again>
3
l.310 }
You meant to type ## instead of #, right?
Or maybe a } was forgotten somewhere earlier, and things
are all screwed up? I'm going to assume that you meant ##.
我能做些什么来解决这个问题？我是否使用了完全错误的路径来实现我想要的目标？
编辑#1
以下是最后一个可行解决方案的一个工作示例：
% Birthday calendar
% Author: Hakon Malmedal
\documentclass[fontsize=20pt]{scrartcl}
\usepackage[french]{babel}
\usepackage[utf8]{inputenc}
\usepackage[T1]{fontenc}
\usepackage{lmodern}
\usepackage[margin=1cm,a4paper,landscape]{geometry}
\pagestyle{empty}
\usepackage{graphicx}
\usepackage{tikz}
%%%<
\usepackage{verbatim}
%%%>
\begin{comment}
:Title: Birthday calendar
:Tags: Calendar library;Calendars
:Author: Hakon Malmedal
:Slug: birthday-calendar
\end{comment}
\usetikzlibrary{calendar,fit}
\usepackage{expl3,xparse}
%% Adapted from http://tex.stackexchange.com/a/10199/4771
\makeatletter%
\tikzoption{day headings}{\tikzstyle{day heading}=[#1]}
\tikzstyle{day heading}=[]
\tikzstyle{day letter headings}=[
execute before day scope={ \ifdate{day of month=1}{%
\pgfmathsetlength{\pgf@ya}{\tikz@lib@cal@yshift}%
\pgfmathsetlength\pgf@xa{\tikz@lib@cal@xshift}%
\pgftransformyshift{-\pgf@ya}
\foreach \d/\l in {0/Lundi,1/Mardi,2/Mercredi,3/Jeudi,%
4/Vendredi,5/Samedi,6/Dimanche} {
\pgf@xa=\d\pgf@xa%
\pgftransformxshift{\pgf@xa-\cellwidth/2}%
\pgftransformyshift{\pgf@ya}%
\node[above=-0.5ex,day heading]{\l};%
}
}{}%
}%
]
\makeatother%
%% End
%% Adapted from pgf source
\def\pgfcalendarmonthname#1{%
\translate{\ifcase#1\or Janvier\or Février\or Mars\or Avril\or
Mai\or Juin\or Juillet\or Août\or Septembre\or Octobre\or
Novembre\or Decembre\fi}%
}
\makeatletter
\tikzstyle{month label above centered}=[%
execute before day scope={%
\ifdate{day of month=1}{%
{
\pgfmathsetlength{\pgf@xa}{\tikz@lib@cal@xshift}%
\pgf@xb=\tikz@lib@cal@width\pgf@xa%
\advance\pgf@xb by-\pgf@xa%
\pgf@xb=.5\pgf@xb%
\pgftransformxshift{\pgf@xb}%
\pgftransformxshift{-\cellwidth/2}%
\pgfmathsetlength{\pgf@y}{\tikz@lib@cal@yshift}%
\pgftransformyshift{0.333\pgf@y}
\tikzmonthcode%
}
}{}},
every month/.append style={anchor=base}
]
\makeatother
%% End
\ExplSyntaxOn
%% Adapted from http://tex.stackexchange.com/a/56214/4771
%%
% first of all we define the user level commands
\NewDocumentCommand{\addtext}{ m }{ \bdaycal_input_add:n { #1 } }
\NewDocumentCommand{\addtextyear}{ mm }{ \bdaycal_input_add_y:nn { #1 } { #2 } }
\NewDocumentCommand{\showtext}{ }{ \bdaycal_output_direct: }
% allocate variable:
% a sequence for global storage of the inputs;
\seq_new:N \g_bdaycal_input_seq
% store globally an input in the sequence
\cs_new:Npn \bdaycal_input_add:n #1
{
\seq_gput_right:Nn \g_bdaycal_input_seq { #1 }
}
\cs_new:Npn \bdaycal_input_add_y:nn #1 #2
{
\seq_gput_right:Nn \g_bdaycal_input_seq { #1 ~ ( \int_to_arabic:n
{ \pgfcalendarifdateyear - #2 } ) }
}
% how to output in direct order; we simply do a mapping function calling
% \bdaycal_print:n after incrementing the counter
\cs_new_protected:Npn \bdaycal_output_direct:
{
\seq_map_inline:Nn \g_bdaycal_input_seq
{
\bdaycal_print:n { ##1 }
}
\seq_gclear:N \g_bdaycal_input_seq
}
% the printing macro; change here for adapting to your wishes
\cs_new:Npn \bdaycal_print:n #1
{
#1 \par
}
%% End
%% Knuth's AoCP, vol 1, 2nd ed, pp 155--156
\int_new:N \l_easter_Y_int
\int_new:N \l_easter_G_int
\int_new:N \l_easter_C_int
\int_new:N \l_easter_X_int
\int_new:N \l_easter_Z_int
\int_new:N \l_easter_D_int
\int_new:N \l_easter_E_int
\int_new:N \l_easter_N_int
\int_new:N \l_easter_M_int
\int_new:N \l_easter_julian_day_int
\cs_new:Nn \easter_sunday:n {
\int_set:Nn \l_easter_Y_int { #1 }
\int_set:Nn \l_easter_G_int {
\int_mod:nn { \l_easter_Y_int } { 19 } + 1
}
\int_set:Nn \l_easter_C_int {
\int_div_truncate:nn { \l_easter_Y_int } { 100 } + 1
}
\int_set:Nn \l_easter_X_int {
\int_div_truncate:nn { 3 * \l_easter_C_int } { 4 } - 12
}
\int_set:Nn \l_easter_Z_int {
\int_div_truncate:nn { 8 * \l_easter_C_int + 5 } { 25 } - 5
}
\int_set:Nn \l_easter_D_int {
\int_div_truncate:nn { 5 * \l_easter_Y_int } { 4 } - \l_easter_X_int - 10
}
\int_set:Nn \l_easter_E_int {
\int_mod:nn { 11 * \l_easter_G_int + 20 + \l_easter_Z_int
- \l_easter_X_int } { 30 }
}
% \int_mod:nn behaves strangely.
\int_compare:nNnT { \l_easter_E_int } < { 0 }
{
\int_add:Nn \l_easter_E_int { 30 }
}
\int_compare:nNnTF { \l_easter_E_int } = { 25 }
{ % true
\int_compare:nNnT { \l_easter_G_int } > { 11 }
{ % true
\int_incr:N \l_easter_E_int
}
}
{ % false
\int_compare:nNnT { \l_easter_E_int } = { 24 }
{ % true
\int_incr:N \l_easter_E_int
}
}
\int_set:Nn \l_easter_N_int { 44 - \l_easter_E_int }
\int_compare:nNnT { \l_easter_N_int } < { 21 }
{ % true
\int_add:Nn \l_easter_N_int { 30 }
}
\int_add:Nn \l_easter_N_int {
7 - \int_mod:nn { \l_easter_D_int + \l_easter_N_int } { 7 }
}
\int_compare:nNnTF { \l_easter_N_int } > { 31 }
{ % true
\int_sub:Nn \l_easter_N_int { 31 }
\int_set:Nn \l_easter_M_int { 4 } % April
}
{ % false
\int_set:Nn \l_easter_M_int { 3 } % March
}
\pgfcalendardatetojulian { \l_easter_Y_int -
\l_easter_M_int - \l_easter_N_int
} { \l_easter_julian_day_int }
}
\ExplSyntaxOff
\pgfkeys{/tikz/event/.code = \addtext{#1}}
\pgfkeys{/pgf/calendar/recurring/.default = 0}
\pgfkeys{/pgf/calendar/recurring/.code =
{
\foreach \m/\d in {#1}
{
\ifnum\pgfcalendarifdatemonth=\m\relax
\ifnum\pgfcalendarifdateday=\d\relax
\global\pgfcalendarmatchestrue
\fi
\fi
}
}
}
\pgfkeys{/tikz/day code =
{
\node (lower right) at (0,0) [above left,font=\Large] {\tikzdaytext};
\node (upper left) at (-\cellwidth,\cellheight)
[below right,align=left,text width=\cellwidth-\pgflinewidth,
font=\tiny,black] {\showtext};
\node (lower left) at (-\cellwidth,0) {};
\node[rounded corners, draw,
fit=(lower right) (upper left) (lower left),
inner sep=1mm] {};
}
}
\pgfkeys{/tikz/inner sep = 0pt}
\pgfkeys{/tikz/day xshift=\cellwidth+2mm+2mm}
\pgfkeys{/tikz/day yshift=\cellheight+2mm+2mm}
\newlength{\cellheight}
\setlength{\cellheight}{25mm}
\newlength{\cellwidth}
\setlength{\cellwidth}{35mm}
\begin{document}
\centering
\begin{tikzpicture}[thick]
\calendar[dates=2024-01-01 to 2024-01-last,
week list,
month label above centered,
month text=\textsc{\%mt \%y0},
day headings={font=\footnotesize},
day letter headings]
if (recurring={01/04,01/14,01/24}) [event={Something}]
;
\end{tikzpicture}
\end{document}
答案1
以下是recurring语法测试
重复 =事件次从日期每一个重复[天|周]
在哪里
date是通常日历语法中的日期，YYYY-MM-DD其中YYYY-是可选的，occurrences是事件应重复的次数（除了第一次重复的次数date），repeat是重复事件与- [天|周] 要么 ，
days要么weeks。
关键词times、days和weeks可以是单数time，day和week。
的值repeat将由 PGFMath 进行评估（因此可以是8-2^2），而occurrences只能由 eTeX 进行评估（8-2*2可以工作）。
您的 1 月 4 日、14 日和 20 日活动将是
recurring = 2 times from 01-04 every 10 days
代码
\documentclass{article}
\usepackage{tikz}
\usetikzlibrary{calendar}
\makeatletter
\pgfqkeys{/pgf/calendar}{
recurring/.code args={#1 time#2 from #3 every #4 #5}{%
% This macro converts yyyy-mm-dd to julian date (in \pgfutil@tempctna)
% as well as mm-dd with the current year
\pgfcalendar@special@datetojulian{#3}%
\pgfqkeys{/pgf/calendar/@recurring}{#5={#4}{#1}}},
@recurring/days/.code 2 args={% #1 is the every, #2 is the times
\ifnum\pgfintmod{\pgfcalendarifdatejulian-\pgfutil@tempcnta}{#1}=0
\pgfmathsetcount\c@pgf@counta{#2}%
\unless\ifnum\pgfintdivtruncate
{\pgfcalendarifdatejulian-\pgfutil@tempcnta}{#1}>\c@pgf@counta
\pgfcalendarmatchestrue
\fi
\fi},
@recurring/weeks/.style 2 args={/pgf/calendar/@recurring/days={7*(#1)}{#2}},
@recurring/day/.style={/pgf/calendar/@recurring/days={#1}},
@recurring/week/.style={/pgf/calendar/@recurring/weeks={#1}}}
\makeatother
\begin{document}
\tikz
\calendar[
dates=2023-01-01 to 2023-03-31,
month list, month label left, month yshift=1.25em]
if (Sunday) [days={fill=red!50}]
if (recurring = 17 times from 2023-01-01 every 2 days) [green!50!black]
if (recurring = 4 times from 2023-02-06 every 2 weeks) [blue!50]
if (recurring = 2 times from 01-04 every 10 days) [days={fill=green!50}];
\end{document}
输出
