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检查从脚本并行启动的进程的退出代码

tag-icon • tag-icon bash
检查从脚本并行启动的进程的退出代码

假设我有以下 bash 脚本：

#!/usr/bin/env bash
process-1&
process-2&
process-3&

我有两个问题：

  1. 如何在脚本末尾检查所有进程是否以退出代码 0 退出？
  2. 我的脚本如何“等待”直到所有启动的进程完成，然后进行总结echo（也许通知用户退出代码）？

答案1

您可以使用内置的 bash wait。
3次wait -n，每次检查退出状态。

从man bash:

    wait [-n] [n ...]
           Wait  for  each  specified child process and return its termination
           status.  Each n may be a process ID or a job  specification;  if  a
           job  spec is given, all processes in that job's pipeline are waited
           for.  If n is not given, all currently active child  processes  are
           waited  for,  and  the  return status is zero.  If the -n option is
           supplied, wait waits for any job to terminate and returns its  exit
           status.   If  n specifies a non-existent process or job, the return
           status is 127.  Otherwise, the return status is the exit status  of
           the last process or job waited for.

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