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如何从 ip 输出中删除换行符？

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如何从 ip 输出中删除换行符？

输入（“ip a s”命令）

1: lo: <LOOPBACK,UP,LOWER_UP> mtu 16436 qdisc noqueue 
    link/loopback 00:00:00:00:00:00 brd 00:00:00:00:00:00
    inet 127.0.0.1/8 scope host lo
    inet6 ::1/128 scope host 
       valid_lft forever preferred_lft forever
2: eth0: <BROADCAST,MULTICAST,UP,LOWER_UP> mtu 1500 qdisc pfifo_fast qlen 1000
    link/ether e3:1c:12:f3:5a:34 brd ff:ff:ff:ff:ff:ff
    inet 1.2.3.4/24 brd 1.2.3.255 scope global eth0
    inet6 fe80::e61f:13ff:fef3:5a34/64 scope link 
       valid_lft forever preferred_lft forever

输出：

1: lo: <LOOPBACK,UP,LOWER_UP> mtu 16436 qdisc noqueue link/loopback 00:00:00:00:00:00 brd 00:00:00:00:00:00 inet 127.0.0.1/8 scope host lo inet6 ::1/128 scope host valid_lft forever preferred_lft forever
2: eth0: <BROADCAST,MULTICAST,UP,LOWER_UP> mtu 1500 qdisc pfifo_fast qlen 1000 link/ether e3:1c:12:f3:5a:34 brd ff:ff:ff:ff:ff:ff inet 1.2.3.4/24 brd 1.2.3.255 scope global eth0 inet6 fe80::e61f:13ff:fef3:5a34/64 scope link valid_lft forever preferred_lft forever

问题：如何删除输入/输出中的新行？

答案1

使用-o/-oneline选项。这正是它的用途。

# ip -o addr show
1: lo    inet 127.0.0.1/8 scope host lo\       valid_lft forever preferred_lft forever
1: lo    inet6 ::1/128 scope host \       valid_lft forever preferred_lft forever
4: wlan0    inet 192.168.0.24/24 brd 192.168.0.255 scope global wlan0\       valid_lft forever preferred_lft forever
4: wlan0    inet6 fe80::c685:8ff:fe80:dd06/64 scope link \       valid_lft forever preferred_lft forever
5: docker0    inet 172.17.42.1/16 scope global docker0\       valid_lft forever preferred_lft forever
5: docker0    inet6 fe80::5484:7aff:fefe:9799/64 scope link \       valid_lft forever preferred_lft forever
23: veth3d95    inet6 fe80::8429:16ff:fed6:beb3/64 scope link \       valid_lft forever preferred_lft forever

答案2

您可以使用perl：

$ ip a s | perl -00pe 's/\n *(?![0-9])/ /g'
1: lo: <LOOPBACK,UP,LOWER_UP> mtu 65536 qdisc noqueue state UNKNOWN  link/loopback 00:00:00:00:00:00 brd 00:00:00:00:00:00 inet 127.0.0.1/8 scope host lo valid_lft forever preferred_lft forever inet6 ::1/128 scope host  valid_lft forever preferred_lft forever
2: eth0: <NO-CARRIER,BROADCAST,MULTICAST,UP> mtu 1500 qdisc pfifo_fast state DOWN qlen 1000 link/ether f4:6d:04:11:43:fc brd ff:ff:ff:ff:ff:ff

答案3

Perl/sed 专家面前的丑陋解决方案

 ip a s| awk 'BEGIN { s=0 ; } /^[^\t ]/ {if (s>0) printf "\n" ; s++ ; } {printf " %s",$0;} END { printf "\n" ;}'

基本上

 BEGIN { s=0 ; }

线路计数器

 /^[^\t ]/ {if (s>0) printf "\n" ; s++ ; }

如果行以非空白且不是 forst 开头，则发出换行符

 {printf " %s",$0;}

复制不带换行符的行

  END { printf "\n" ;}

最后，使用一个新行。

答案4

如果你愿意sed你可以尝试这个解决方案，其中也有一个很好的解释：

您可以使用^[[:digit:]]因为 的输出ip。

ip addr show | sed -e '/^[[:digit:]]/bpp' -e 'H;$bpp' -e 'd' -e ':pp' -e 'x;/^$/d;s/\n/ /g'

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