Bash 错误:“

Bash 错误:“

我试图让这个脚本正常运行,但我得到了./passmark.sh line 7: [y command not found

这是我的脚本

#!/bin/bash
# A simple script to ask a user for a pass mark and then display a grade
# the grade will be either an A, B, C, D or F
#
CONT=y
echo
while [$CONT = "y" ]
do
        echo -e "\"Please enter a pass mark: \c \""
        read MARK
        if [$MARK -ge "0" -a $MARK -lt "50"] ; then
                echo -e "\n \"F\" \n"
        elif [$MARK -ge "50" -a $MARK -lt "60"] ; then
                echo -e "\n \"D\" \n"
        elif [$MARK -ge "60" -a $MARK -lt "70"] ; then
                echo -e "\n \"C\" \n"
        elif [$MARK -ge "70" -a $MARK -lt "80"] ; then
                echo -e "\n \"B\" \n"
        elif [$MARK -ge "80" -a $MARK -lt "100"] ; then
                echo -e "\n \"A\" \n"
        else
                echo -e "\"Invalid input!!\n \""
        fi
        echo -e "\"Would you like to enter another pass mark? (y/n) \c \""
        read REPLY
        case "$REPLY" in
                n | N | no | No | NO ) CONT=n ;;
                *) ;;
        esac
echo
done 

答案1

您需要在[和周围留有空格],例如

if [ "$MARK" -ge 0 -a "$MARK" -lt 50 ]; then

按照您编写的方式,当$MARKis 时7,它会尝试执行[7命令,而不是7作为参数传递给[命令([只是 的缩写test)。

您还应该引用该变量。否则,如果用户输入空行或多个单词,则测试表达式将无法正确解析。

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