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如何在进入 Bash 脚本的一组值之前添加换行符？

tag-icon • tag-icon linux bash scripting sed awk
如何在进入 Bash 脚本的一组值之前添加换行符？

我将一组数据导入到 Bash 脚本中。以下是该数据的示例：

"foo1": "Miscellaneous text",
    "foo2": "More text",
    "foo3": "blah blah blah",
      "foo4": 1635.0,
      "foo5": 0.0,
"foo1": "Miscellaneous text that is different",
    "foo2": "More text1231231",
    "foo3": "blah blah blah234234",
      "foo4": 1633425.0,
      "foo5": 0.0,
"foo1": "Miscellaneous text abc123",
    "foo2": "More text122121",
    "foo3": "blah blah blah414124",
      "foo4": 163235.0,
      "foo5": 1.0,
"foo1": "More Miscellaneous text",
    "foo2": "asdfasdfaMore text",
    "foo3": "blah blahadsfasdf blah",
      "foo4": 1635232.0,
      "foo5": 0.0,

我想在“foo1”前面添加一个换行符 (\n)。换句话说，将数据更改为以下内容：

    \n"foo1": "Miscellaneous text",
        "foo2": "More text",
        "foo3": "blah blah blah",
          "foo4": 1635.0,
          "foo5": 0.0,
    \n"foo1": "Miscellaneous text that is different",
        "foo2": "More text1231231",
        "foo3": "blah blah blah234234",
          "foo4": 1633425.0,
          "foo5": 0.0,
    \n"foo1": "Miscellaneous text abc123",
        "foo2": "More text122121",
        "foo3": "blah blah blah414124",
          "foo4": 163235.0,
          "foo5": 1.0,
    \n"foo1": "More Miscellaneous text",
        "foo2": "asdfasdfaMore text",
        "foo3": "blah blahadsfasdf blah",
          "foo4": 1635232.0,
          "foo5": 0.0,

我认为可以使用 sed/awk 来实现，但我不太确定 foo1 的值是否可以/将会改变。

有任何想法吗？

答案1

这将为以“foo”开头的每一行添加一个“\n”：

sed 's/^"foo1":/\n&/'

答案2

awk解决方案：

$ awk '{ sub(/^"foo1"/, "\\n&") }; 1'
$ awk '{ if (/^"foo1"/) { print "\\n" $0 } else { print $0 } }'

既然你说过：

我想在“foo1”前面添加换行符（\n）

因此我转义了反斜杠来插入一个\n字符而不是一个新行。

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