从文件中读取行

Question

您好，我如何从文件中读取每一行并将其与其他文件进行比较...实际上该文件应该从命令行获取...请帮助我

if [[-f $@ ]];
    then
    for "$line" in $@;
    do
        if grep "^$line" /etc/passwd > /dev/null;
            then IFS=":";
            read usr pwd uid gid gcos home shell < <(grep "^$user" /etc/passwd);
            IFS=",";
            read name <<< "$gcos";
            printf "UID:%-10s Name:%s\n" "$uid" "$name";
        else
            echo "No User"
        fi
    done
fi

Answer 1

您好，我如何从文件中读取每一行并将其与其他文件进行比较。

如果您只是想比较两个文件，我可以建议：

选项1差异=> 并排合并文件差异

sdiff file1 file2

示例输出：

abcdev                                                          abcdev
abcdev                                                          abcdev
abcdev                                                          abcdev
abcdev                                                        | abcde33

选项#2差异=> 逐行比较文件

diff file1 file2

示例输出：

4c4
< abcdev
---
> abcde33

选项#3维姆迪夫=> 使用 Vim 编辑文件的两个、三个或四个版本并显示差异

vimdiff file1 file2

示例屏幕（您可以在仍然看到差异的同时编辑文件）：

选项#4grep=> 打印与模式匹配的行

grep -Fxvf file1 file2

标志细分：

-F, --fixed-strings
  Interpret PATTERN as a list of fixed strings, separated by newlines, any of which is to be matched.    
-x, --line-regexp
  Select only those matches that exactly match the whole line.
-v, --invert-match
  Invert the sense of matching, to select non-matching lines.
-f FILE, --file=FILE
  Obtain patterns from FILE, one per line.  The empty file contains zero patterns, and therefore matches nothing.

示例输出：

abcde33