打印字符串周围的所有行，直到匹配另一个字符串

Question

我有一个示例数据集，其中一个部分具有以“某事”开头的字段。我想在匹配特定字符串“1234”时获取每个“something”部分中的所有行。

我想我可以搜索“1234”并打印之前和之后的所有行，直到匹配“某事”。

期望的输出：

something like this one
 1234
 abcd

something like this one
 zyxw
 1234 

示例数据集：

otherthings
otherthings
otherthings

something like this one
 1234
 abcd 

something not like this one
 xxxx
 yyyy 

something not like this one
 xxxx
 yyyy

something like this one
 1234
 abcd

otherthings
otherthings
otherthings

Answer 1

使用“awk”：

#!/bin/sh

awk '
    function print_section() {
        # Only print section if "1234" was encountered
        if (valid == 1) print section;
    }
    {
        if (/something/) {
            # Start new section
            section = $0; 
        }
        else if (/^\s*$/) {
            # Empty line -> output previous section
            if (section ne "") {
                print_section();
                section = "";
                valid = 0;
            }
        }
        else if (section ne "") {
            # Add line to section if one has been started
            section = section "\n" $0;
            if (/1234/) valid = 1;
        }
    }
    END {
        # End of file, print current section if it exists
        print_section();
    }
' file