Bash if 语句无法正常工作

Question

我有一个 bash 语句来测试命令行参数。如果传递给脚本的参数是“clean”，则脚本将删除所有 .o 文件。否则，它会构建一个程序。但是，无论传递什么（如果有的话），脚本仍然认为传递了参数“clean”。

#!/bin/bash
if test "`whoami`" != "root" ; then
    echo "You must be logged in as root to build (for loopback mounting)"
    echo "Enter 'su' or 'sudo bash' to switch to root"
    exit
fi
ARG=$1
if [ $ARG=="clean" ] ; then
    echo ">>> cleaning up object files..."
    rm -r src/*.o
    echo ">>> done. "
    echo ">>> Press enter to continue..."
    read
else
    #Builds program
fi

Answer 1

[您需要用空格分隔参数；另外，相等运算符是单个=，您应该引用两边：

if [ "$ARG" = "clean" ]; then