运行 lxd_container 模块的示例时，Ansible 返回“任务中未检测到任何操作”

Question

我使用了以下页面https://docs.ansible.com/ansible/lxd_container_module.html提取以下 lxd 示例并将其放入 YAML 文件中：

>>> cat play.yaml

---
# An example for creating a Ubuntu container and install python
- hosts: localhost
  connection: local
  tasks:
    - name: Create a started container
      lxd_container:
        name: mycontainer
        state: started
        source:
          type: image
          mode: pull
          server: https://images.linuxcontainers.org
          protocol: lxd
          alias: ubuntu/xenial/amd64
        profiles: ["default"]
        wait_for_ipv4_addresses: true
        timeout: 600

但是运行它时我收到以下错误：

>>> ansible-playbook play.yaml 
ERROR! no action detected in task

The error appears to have been in '/root/play': line 6, column 7, but may
be elsewhere in the file depending on the exact syntax problem.

The offending line appears to be:

  tasks:
    - name: Create a started container
      ^ here

YAML 文件的格式看起来正确。我也检查了，ansible-doc -l | grep "lxd"但没有返回任何结果。

什么原因导致任务无法运行？

Answer 1

lxd_container模块是在 Ansible 版本 2.2 中添加的。使用以下命令检查您的 Ansible 版本，ansible --version并根据需要使用以下命令更新您的 Ansible 安装：pip install ansible --upgrade