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查找并替换两个定界符之间的字符串

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查找并替换两个定界符之间的字符串

如何替换两个定界符之间的字符串？

我找到的一些答案很接近，但我认为我的需求稍微复杂一些。

即smb.conf共享之间有一个空白行。我想定位要更新的共享。第一个分隔符是“[sharename]”，最后一个分隔符可以是空白行。

我想查找并将“writable = yes”替换为“writable = no”，由于空格，它可能格式不准确，但必须出现在我的两个分隔符之间。

答案1

几乎已经完成了，感谢这份清单和 http://fahdshariff.blogspot.com/2012/12/sed-mutli-line-replacement-between-two.html。

我可以在命令行上用“# writeable”替换“writeable”，并且可以不考虑 Y/N 设置而这样做，稍后我会插入另一行。

sed '/\[${share_name}\]/,/^$/{/\[${share_name}\]/n;/^$/!{s/writeable/\#writeable/g}}' \
< ${input_file} \
> /tmp/parse-smb.tmp

虽然这在命令行上使用“！”转义的“！”有效，但在脚本文件 /bin/sh 中无效。我必须删除转义，但触发器不会命中。

外壳的微妙之处。

答案2

啊，“！”没问题，这是“share_name”变量转换失败。在此命令中使用双引号而不是单引号。

sed "/\${share_name}\]/,/^$/{/[${share_name}\]/n;/^$/!s/writeable/\#writeable/g}}" \
< ${input_file} \
> /tmp/parse-smb.tmp

应该意识到后续行也使用了双引号。

sed -i "s/\[${share_name}\]/\[${share_name}\]\n\thosts allow = 10.50.157.0\/24 \n\twriteable = no/" \
/tmp/parse-smb.tmp

答案3

我认为 perl：未经测试

perl -00 -pe '/^\[your_share_name\]/ and s/writable\s*=\s*\Kyes/no/si' smb.conf

答案4

我认为这是 perl 的工作（或者如果你愿意的话，也可以是 python。）

iMac$ cat ./replace.pl
#!/usr/bin/perl

while (<>) {
    if (/^\n/) { $replace = 0; }
    if (/\[share3\]/) { $replace = 1; }
    print unless /writable/;
    if (/writable/) {
    if ($replace == 1) {
        print "  writable = no\n";
    }
    else {
        print;
    }
    }
}
iMac$ cat smb.conf 
[share1]
  writable = yes
  user = anonymous
  host = remote

[share2]
  writable = yes
  user = anonymous
  host = remote

[share3]
  writable = yes
  user = anonymous
  host = remote

[share4]
  writable = yes
  user = anonymous
  host = remote

[share5]
  writable = yes
  user = anonymous
  host = remote
iMac$ cat smb.conf | ./replace.pl
[share1]
  writable = yes
  user = anonymous
  host = remote

[share2]
  writable = yes
  user = anonymous
  host = remote

[share3]
  writable = no
  user = anonymous
  host = remote

[share4]
  writable = yes
  user = anonymous
  host = remote

[share5]
  writable = yes
  user = anonymous
  host = remote

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