是否有可能在 body_filter_by_lua_block 期间避免在 lua nginx 上进行分块传输?

是否有可能在 body_filter_by_lua_block 期间避免在 lua nginx 上进行分块传输?

假设我们想要更改来自上游的响应,我们可以做的就是在该body_filter_by_lua_block阶段使用 Lua+nginx,下面是其中的一个片段。

  server {
    listen 8181;
    location /media {
        alias /media/;
    }
  }

  server {
    listen 8080;

    location /media {
        proxy_pass http://localhost:8181;

        # we need to keep this url since we're going to rewrite
        set_by_lua_block $original_uri { return ngx.var.uri }

        # when the Lua code may change the length of the response body
        header_filter_by_lua_block { ngx.header.content_length = nil }

        # removing (rewriting) the filters
        rewrite_by_lua_block {
          local uri = ngx.re.sub(ngx.var.uri, "^/media/(.*)/hls/(.*)$", "/media/hls/$2")
          ngx.req.set_uri(uri)
        }

        # applying the bandwidth min filter
        # but we can use the ngx.var.original_uri to build/select the filters
        body_filter_by_lua_block {
          local modified_manifest = filtering(ngx.arg[1])
          ngx.arg[1] = modified_manifest
          ngx.arg[2] = true
        }
    }

这很好用!但问题是,这样响应将使用分块传输,而有些客户端无法处理分块响应,你知道我该如何克服这个问题吗?

答案1

我通过以下方式解决了这个问题发出子请求并满足内容长度标头。

    location /mmedia {
         content_by_lua_block {
            local uri = ngx.re.sub(ngx.var.uri, "^/mmedia/(.*)/hls/(.*)$", "/media/$1/hls/$2")
            local res = ngx.location.capture(uri)
            if res then
              ngx.header.content_length = #res.body
              ngx.print(res.body)
            end
         }
    }

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